Problem 107
Question
A nearsighted person cannot read a sign that is more than \(5.2 \mathrm{~m}\) from his eyes. To deal with this problem, he wears contact lenses that do not correct his vision completely, but do allow him to read signs located up to distances of \(12.0 \mathrm{~m}\) from his eyes. What is the focal length of the contacts?
Step-by-Step Solution
Verified Answer
Focal length of the contacts is approximately 8.73 m.
1Step 1: Understand the Problem
A nearsighted person has a far point of 5.2 meters without correction. With contact lenses, this person can see up to 12.0 meters. We are to find the focal length of these lenses.
2Step 2: Use the Lens Formula
The lens formula relates the object distance \(d_o\), image distance \(d_i\), and the focal length \(f\) of a lens: \[\frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i}\] In this situation, the far point without lenses (5.2 meters) serves as the image distance \(d_i\), and the farthest point visible with lenses (12.0 meters) is the object distance \(d_o\).
3Step 3: Assign Known Values
Assign the known distances to the formula: \(d_o = 12.0\) m and \(d_i = -5.2\) m. The image distance \(d_i\) is negative because the image forms on the same side as the object for a nearsighted person.
4Step 4: Substitute Values into the Formula
Substitute the known values into the lens formula: \[\frac{1}{f} = \frac{1}{12.0} + \frac{1}{-5.2}\]
5Step 5: Calculate \(\frac{1}{f}\)
Calculate the right side of the equation: \[\frac{1}{f} = \frac{1}{12.0} - \frac{1}{5.2}\]Find common denominators and perform the subtraction.
6Step 6: Solve for \(f\)
After calculating the right side, invert the result to find \(f\): \(f = 1 / \text{(result from previous step)}\).
7Step 7: Conclusion
Compute the value of \(f\) and confirm the units in meters. The focal length of the contacts is the value you have calculated.
Key Concepts
Lens FormulaNearsightednessFocal LengthVision Correction
Lens Formula
The lens formula is a fundamental concept in optics. It helps us relate the focal length of a lens to the distances of an object and its image. The formula is given by:
\[\frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i}\]where:
In our exercise, understanding the relationship between these distances and the focal length enables us to determine the power needed in lenses to correct vision.
\[\frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i}\]where:
- \(f\) is the focal length of the lens.
- \(d_o\) is the distance from the lens to the object (object distance).
- \(d_i\) is the distance from the lens to the image (image distance).
In our exercise, understanding the relationship between these distances and the focal length enables us to determine the power needed in lenses to correct vision.
Nearsightedness
Nearsightedness, or myopia, is a common vision condition where distant objects appear blurry while close objects can be seen clearly. This happens because the eye is elongated or the cornea is too curved, which causes light to focus in front of the retina rather than directly on it.
To address nearsightedness:
To address nearsightedness:
- Corrective lenses such as glasses or contact lenses are used to diverge light rays and move the focus back onto the retina.
- The far point (farthest distance an object can be seen clearly without correction) is closer than normal.
Focal Length
Focal length is a critical term used when discussing lenses. It represents the distance from the lens to its focus, where parallel rays of light meet. A lens with shorter focal length bends light more than one with a longer focal length.
Key considerations for focal length include:
Key considerations for focal length include:
- Lenses for nearsighted individuals will have a negative focal length.
- Shorter focal length lenses provide stronger correction due to greater bending of light.
Vision Correction
Vision correction aims to adjust the eye's focusing ability to see clearly at various distances. For nearsightedness, lenses need to diverge light before it reaches the eye.
Methods of vision correction include:
Methods of vision correction include:
- Eyeglasses which can easily be adjusted for different lighting needs and distances.
- Contact lenses which sit right on the eye for convenience and comfort.
Other exercises in this chapter
Problem 104
A slide projector has a converging lens whose focal length is \(105.00 \mathrm{~mm}\). (a) How far (in meters) from the lens must the screen be located if a sli
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The near point of a naked eye is \(32 \mathrm{~cm}\). When an object is placed at the near point and viewed by the naked eye, it has an angular size of 0.060 ra
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A camper is trying to start a fire by focusing sunlight onto a piece of paper. The diameter of the sun is \(1.39 \times 10^{9} \mathrm{~m},\) and its mean dista
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(a) For a diverging lens \((f=-20.0 \mathrm{~cm}),\) construct a ray diagram to scale and find the image distance for an object that is \(20.0 \mathrm{~cm}\) fr
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