Problem 106
Question
Which of the following is a correct pair with respect to molecular formula of a xenon compound and the hybridization state of xenon in it? (a) \(\mathrm{XeF}_{2}, \mathrm{sp}\) (b) \(\mathrm{XeF}_{4}, \mathrm{sp}^{2}\) (c) \(\mathrm{XeF}_{4}, \mathrm{sp}^{3}\) (d) \(\mathrm{XeF}_{2}, \mathrm{sp}^{3} \mathrm{~d}\)
Step-by-Step Solution
Verified Answer
Option (d) \( \mathrm{XeF}_2, \mathrm{sp}^3\mathrm{d} \) is correct.
1Step 1: Understanding Xenon's Valence Electrons
Xenon is a noble gas, and it has 8 valence electrons in its outer shell. When xenon forms compounds, these electrons can be used to form bonds with other elements, such as fluorine.
2Step 2: Analyzing Option (a) \( \mathrm{XeF}_2, \mathrm{sp} \)
In \( \mathrm{XeF}_2 \), xenon is bonded to two fluorine atoms and has 3 lone pairs. This results in a total of 5 pairs: 2 bonding pairs and 3 lone pairs, which leads to a linear shape and the hybridization being \( \mathrm{sp}^3\mathrm{d} \), not \( \mathrm{sp} \).
3Step 3: Analyzing Option (b) \( \mathrm{XeF}_4, \mathrm{sp}^2 \)
In \( \mathrm{XeF}_4 \), xenon is bonded to four fluorine atoms and has 2 lone pairs. This leads to 6 pairs: 4 bonding pairs and 2 lone pairs, resulting in a square planar shape and the hybridization being \( \mathrm{sp}^3\mathrm{d}^2 \), not \( \mathrm{sp}^2 \).
4Step 4: Analyzing Option (c) \( \mathrm{XeF}_4, \mathrm{sp}^3 \)
Again, in \( \mathrm{XeF}_4 \), xenon has 6 pairs: 4 bonds with fluorine and 2 lone pairs, leading to \( \mathrm{sp}^3\mathrm{d}^2 \) hybridization, not \( \mathrm{sp}^3 \).
5Step 5: Analyzing Option (d) \( \mathrm{XeF}_2, \mathrm{sp}^3\mathrm{d} \)
In \( \mathrm{XeF}_2 \), xenon with its two bonds to fluorine atoms and three lone pairs forms 5 pairs overall, which corresponds to an \( \mathrm{sp}^3\mathrm{d} \) hybridization, matching the description.
Key Concepts
Molecular FormulaHybridizationValence ElectronsBonding Pairs
Molecular Formula
The molecular formula provides a concise representation of a compound, revealing the types and numbers of atoms present in a molecule. In the context of xenon compounds, the molecular formula helps us understand the arrangement and ratio of atoms within the compound.
For instance:
For instance:
- **XeF2** indicates a xenon atom bonded to two fluorine atoms.
- **XeF4** signifies a xenon atom connected to four fluorine atoms.
Hybridization
Hybridization is a concept used to explain the arrangement of bonding in molecules. It describes how atomic orbitals mix to form new hybrid orbitals, which can house pairs of electrons, serving as bonding or lone pair regions around the central atom.
In xenon compounds:
In xenon compounds:
- **XeF2**: Xenon uses 5 orbitals which combine into sp3d hybridization, forming a linear shape.
- **XeF4**: The sp3d2 hybridization is employed, resulting in a square planar shape due to the six pairs (4 bonds and 2 lone pairs).
Valence Electrons
Valence electrons are the outermost electrons of an atom and are integral in bonding. For xenon, a noble gas, it has a stable octet with 8 valence electrons.
When forming compounds like XeF2 or XeF4:
When forming compounds like XeF2 or XeF4:
- **XeF2**: Xenon shares two of its electrons with fluorine atoms, involving three lone pairs in the remaining orbitals.
- **XeF4**: Xenon shares four electrons, leaving two lone pairs to complete its octet.
Bonding Pairs
Bonding pairs refer to the pairs of electrons involved in bonds between atoms. These are significant in determining the molecular geometry. In xenon compounds:
- **XeF2**: Features 2 bonding pairs and 3 lone pairs, organizing themselves into a linear configuration due to the electron repulsion.
- **XeF4**: Contains 4 bonding pairs and 2 lone pairs, resulting in a square planar shape.
Other exercises in this chapter
Problem 104
Which of the following gas mixtures is used by divers inside the sea? (a) \(\mathrm{O}_{2}+\mathrm{Ar}\) (b) \(\mathrm{O}_{2}+\mathrm{He}\) (c) \(\mathrm{O}_{2}
View solution Problem 105
What are the products formed in the reaction of xenon hexafluoride with silicon dioxide? (a) \(\mathrm{XeO}_{3}+\mathrm{SiF}_{2}\) (b) \(\mathrm{XeOF}_{4}+\math
View solution Problem 107
The increase in boiling points of noble gases from He to Xe is due to the (a) increase in atomic volume (b) increase in electron affinity (c) increase in polari
View solution Problem 109
Which of the following is an explosive compound? (a) \(\mathrm{XeOF}_{2}\) (b) \(\mathrm{XeF}_{2}\) (c) \(\mathrm{XeO}_{3}\) (d) \(\mathrm{XeOF}_{4}\)
View solution