Problem 106
Question
Place the following molecules and ions in order from smallest to largest bond order: \(\mathrm{N}_{2}{\underline{\phantom{xx}}}^{2+}, \mathrm{He}_{2}^{+}, \mathrm{Cl}_{2} \mathrm{H}_{2}^{-}, \mathrm{O}_{2}{\underline{\phantom{xx}}}^{2-}\).
Step-by-Step Solution
Verified Answer
\( \mathrm{He}_{2}^{+}, \mathrm{H}_{2}^{-}, \mathrm{O}_{2}^{2-}, \mathrm{N}_{2}^{2+}, \mathrm{Cl}_{2} \)
1Step 1: Understanding Bond Order
Bond order is the number of chemical bonds between a pair of atoms. It can be calculated from molecular orbital theory as half the difference between the number of bonding electrons and antibonding electrons.
2Step 2: Calculating Bond Order for Each Molecule/Ion
- For \( \mathrm{N}_{2}^{2+} \), remove 2 electrons from \( \mathrm{N}_2 \). Bond order = \( (8 - 4)/2 = 2 \).- For \( \mathrm{He}_{2}^{+} \), bond order = \( (2 - 1)/2 = 0.5 \).- For \( \mathrm{Cl}_{2} \), bond order = \( (14 - 8)/2 = 3 \).- For \( \mathrm{H}_{2}^{-} \), bond order = \( (2 - 0)/2 = 1 \).- For \( \mathrm{O}_{2}^{2-} \), bond order = \( (8 - 6)/2 = 1 \).
3Step 3: Ordering the Bond Orders
Identify the bond orders calculated: \( \mathrm{He}_{2}^{+} = 0.5 \), \( \mathrm{H}_{2}^{-} = 1 \), \( \mathrm{O}_{2}^{2-} = 1 \), \( \mathrm{N}_{2}^{2+} = 2 \), \( \mathrm{Cl}_{2} = 3 \).
4Step 4: Arranging in Sequence
Arrange the molecules/ions in the sequence of increasing bond order: \( \mathrm{He}_{2}^{+} \), \( \mathrm{H}_{2}^{-} \), \( \mathrm{O}_{2}^{2-} \), \( \mathrm{N}_{2}^{2+} \), \( \mathrm{Cl}_{2} \).
Key Concepts
Molecular Orbital TheoryChemical BondsElectrons in Molecules
Molecular Orbital Theory
Molecular Orbital Theory (MO Theory) offers a comprehensive way to understand how electrons are distributed in molecules. This theory suggests that atomic orbitals combine to form molecular orbitals when atoms bond together. These molecular orbitals can hold electrons, similar to atomic orbitals, but they are spread out over the entire molecule rather than being localized around individual atoms. This approach helps explain the bonding and properties of molecules that might not be easily understood through other models, such as Valence Bond Theory. MO theory divides molecular orbitals into bonding and antibonding types:
- Bonding Molecular Orbitals: These are lower in energy and tend to hold atoms together. Electrons in these orbitals increase stability.
- Antibonding Molecular Orbitals: These are higher in energy and can destabilize a molecule. Electrons here can pull atoms apart.
Chemical Bonds
Chemical bonds are the connections between atoms that result from the attraction of electrons. Understanding these bonds is crucial, as they determine the structure and stability of molecules. Chemical bonds can be represented and analyzed in various ways. In the context of Molecular Orbital Theory, we can easily visualize how electrons shared between atoms result in bonding or antibonding interactions.
- Ionic Bonds: Formed when electrons are transferred from one atom to another, typically between metals and nonmetals.
- Covalent Bonds: Occur when electrons are shared between atoms, commonly observed between nonmetals.
- Metallic Bonds: Characterized by a 'sea' of shared free electrons moving through a lattice of metal ions, giving metals their unique properties.
Electrons in Molecules
Electrons play a vital role in the formation, structure, and stability of molecules. Within MO Theory, electrons can occupy various molecular orbitals, impacting the molecule's energy and stability. These electrons can be distributed in two main types of orbitals:
- Bonding Orbitals: Occupied by electrons that enhance the stability of a molecule, leading to the formation of chemical bonds.
- Antibonding Orbitals: Higher in energy, these can reduce stability if occupied by electrons.
Other exercises in this chapter
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