Problem 106
Question
Perform the operations. Write all answers in the form \(a+b i .\) $$ -9 i(4-6 i) $$
Step-by-Step Solution
Verified Answer
The expression simplifies to
\(-54 - 36i\).
1Step 1: Distribute the Complex Number
To start, distribute \(-9i\) across the terms inside the parentheses.\(-9i(4-6i) = (-9i)(4) + (-9i)(-6i)\).
2Step 2: Multiply Each Term
Calculate each multiplication separately:- For \((-9i)(4)\), we have \(-36i\).- For \((-9i)(-6i)\), we notice this is a product of two imaginary numbers. The result is \(54i^2\).
3Step 3: Simplify Using the Property of \(i^2\)
Remember that \(i^2 = -1\). Therefore, \(54i^2 = 54(-1) = -54.\)
4Step 4: Combine Real and Imaginary Parts
Combine the real part (-54) and the imaginary part (-36i), giving us the expression \(-54 - 36i\).
Key Concepts
Understanding the Distributive Property in Complex NumbersThe Imaginary Unit: iReal and Imaginary Parts of Complex NumbersSimplification of Complex Expressions
Understanding the Distributive Property in Complex Numbers
The distributive property is a fundamental aspect of mathematics that helps you expand expressions. With complex numbers, it works just like with real numbers. When you have an expression like \(-9i(4 - 6i)\), you apply the distributive property by multiplying \(-9i\) with each term inside the parentheses separately.
Applying this property, you perform the operation:
The distributive property simplifies the handling of expressions involving both real and imaginary terms, making complex arithmetic more structured.
Applying this property, you perform the operation:
- Multiply \(-9i\) by 4.
- Then multiply \(-9i\) by \(-6i\).
The distributive property simplifies the handling of expressions involving both real and imaginary terms, making complex arithmetic more structured.
The Imaginary Unit: i
The imaginary unit, often denoted as \(i\), is the backbone of complex numbers. It allows us to extend the real number system to solve equations that would otherwise have no real solution. By definition, \(i\) is the square root of \(-1\). Therefore, \(i^2 = -1\), which is a crucial identity used in calculations.
When dealing with expressions like \(-9i(-6i)\), you multiply the two imaginary units together. This operation uses the property \(i^2 = -1\), transforming the expression into a real number. Understanding \(i\) and this property helps simplify expressions and solve complex equations effectively.
When dealing with expressions like \(-9i(-6i)\), you multiply the two imaginary units together. This operation uses the property \(i^2 = -1\), transforming the expression into a real number. Understanding \(i\) and this property helps simplify expressions and solve complex equations effectively.
Real and Imaginary Parts of Complex Numbers
In a complex number, the real part is completely separate from the imaginary part. A complex number takes the form \(a + bi\), where \(a\) is the real part, and \(bi\) is the imaginary part. For example, in the expression\(-54 - 36i\),
- -54 is the real part.
- -36i is the imaginary part.
Simplification of Complex Expressions
Simplification is crucial when working with complex numbers. When you carry out operations on complex expressions, like in the given exercise, you often end up with a mixture of real numbers and terms involving the imaginary unit \(i\).
In this process:
In this process:
- Combine all real parts together.
- Combine all imaginary parts and express them as a single term.
Other exercises in this chapter
Problem 106
Look Alikes \(\cdots\) a. \(\sqrt{2}+\sqrt{18}\) b. \(\sqrt{2}+\sqrt{19}\)
View solution Problem 106
The following problems involve addition, subtraction, and multiplication of radical expressions, as well as rationalizing the denominator. Perform the operation
View solution Problem 107
Use a calculator to evaluate each expression. Round to the nearest hundredth. See Using Your Calculator: Rational Exponents. $$ (1.045)^{2 / 5} $$
View solution Problem 107
Simplify each radical expression, if possible. Assume all variables are unrestricted. $$ -\sqrt[5]{-\frac{1}{32}} $$
View solution