Problem 106
Question
Graph \(f\) and state its domain. $$f(x)=\log (x-3)$$
Step-by-Step Solution
Verified Answer
Domain: \((3, \infty)\). Graph: Vertical asymptote at \(x = 3\), increasing rightward.
1Step 1: Identify the Function and Its Type
The given function is \(f(x) = \log(x-3)\). This is a logarithmic function. Logarithmic functions are defined only for positive arguments, which means the expression inside the logarithm should be greater than zero.
2Step 2: Find the Domain of the Function
To find the domain, set the expression inside the logarithm greater than zero: \(x-3 > 0\). Solving this inequality gives \(x > 3\). Therefore, the domain of \(f(x)\) is all real numbers greater than 3, which is represented as \((3, \infty)\) in interval notation.
3Step 3: Graph the Function
To graph \(f(x) = \log(x-3)\), start your graph at \(x = 3\), moving rightward because the domain is \(x > 3\). As \(x\) approaches 3 from the right, the function approaches negative infinity, denoting a vertical asymptote at \(x = 3\). As \(x\) increases, \(f(x)\) increases slowly without bound.
4Step 4: Analyze Important Points
Choose values for \(x\) greater than 3 to find key points. For example, at \(x = 4\), \(f(4) = \log(4-3) = \log(1) = 0\). At \(x = 5\), \(f(5) = \log(5-3) = \log(2)\), which is approximately 0.301. These points help in visualizing the graph.
Key Concepts
Domain of a FunctionGraphing FunctionsMathematical Analysis
Domain of a Function
The domain of a function defines the set of all possible input values (usually designated by "x") for which the function is defined. In the case of logarithmic functions like \(f(x) = \log(x-3)\), the domain is crucial to ensure the expression inside the logarithm is positive.
To determine this, set the argument of the logarithm to be greater than zero: \(x-3 > 0\). Solving this inequality, you find \(x > 3\). Hence, the domain of \(f\) is all real numbers greater than 3.
In interval notation, this is expressed as \((3, \infty)\).
To determine this, set the argument of the logarithm to be greater than zero: \(x-3 > 0\). Solving this inequality, you find \(x > 3\). Hence, the domain of \(f\) is all real numbers greater than 3.
In interval notation, this is expressed as \((3, \infty)\).
- Always remember: you can't take the logarithm of zero or negative numbers.
- Logarithmic functions only exist when their arguments are positive.
Graphing Functions
Graphing functions allows us to visualize their behavior and understand their properties better. For the function \(f(x) = \log(x-3)\), the graph starts at \(x = 3\). This is because the domain begins at values greater than 3.
A key feature of this graph is the vertical asymptote at \(x = 3\). Here, as \(x\) approaches 3 from the right (but doesn't reach 3), the function \(f(x)\) tends towards negative infinity.
A key feature of this graph is the vertical asymptote at \(x = 3\). Here, as \(x\) approaches 3 from the right (but doesn't reach 3), the function \(f(x)\) tends towards negative infinity.
- Select key points within the domain to help plot the graph. For example, at \(x = 4\), \(f(x) = 0\). This point passes through the x-axis.
- As \(x\) increases, \(f(x)\) grows gradually, increasing without bound.
Mathematical Analysis
Mathematical analysis in the context of functions involves understanding their behavior, limits, and possible applications. In \(f(x) = \log(x-3)\), the analysis explains how the logarithmic function behaves as \(x\) changes within its domain.
- As \(x\) approaches 3, the function value decreases dramatically, showing a vertical asymptote at \(x = 3\).
- Past the asymptote, each incremental increase in \(x\) results in a slow increase in \(f(x)\).
Other exercises in this chapter
Problem 99
Explain how linear and exponential functions differ. Give examples.
View solution Problem 105
Graph \(f\) and state its domain. $$f(x)=\log (x+1)$$
View solution Problem 107
Graph \(f\) and state its domain. $$f(x)=\ln (-x)$$
View solution Problem 108
Graph \(f\) and state its domain. $$f(x)=\ln \left(x^{2}+1\right)$$
View solution