Problem 106
Question
Graph each parabola by hand, and check using a graphing calculator. Give the vertex, axis, domain, and range. $$x=-2(y+3)^{2}$$
Step-by-Step Solution
Verified Answer
Vertex: (0, -3). Axis: y = -3. Domain: (-∞, 0]. Range: (-∞, ∞).
1Step 1: Identify the Form of the Equation
The given equation is \( x = -2(y+3)^2 \). This is in the form \( x = a(y-k)^2 + h \), where \( a = -2 \), \( k = -3 \), and \( h = 0 \). This is a parabola that opens horizontally.
2Step 2: Find the Vertex
The vertex form \( x = a(y-k)^2 + h \) makes it simple to identify the vertex of the parabola. The vertex is \((h, k) \). Substituting the identified values gives the vertex as \((0, -3)\).
3Step 3: Determine the Axis of Symmetry
For a horizontally opening parabola, the axis of symmetry is a horizontal line at the y-coordinate of the vertex. Therefore, the equation for the axis of symmetry is \( y = -3 \).
4Step 4: Find the Domain
Since the parabola opens horizontally to the left (as indicated by \( a = -2 \), which is negative), the domain consists of all x-values that the parabola will cover. Here, that's all points to the left of and including the vertex. Hence, the domain is \(( -\infty, 0 ]\).
5Step 5: Find the Range
The range of a horizontally opening parabola is determined by its possible y-values. Since the parabola doesn't open vertically, it covers all real y-values. Hence, the range is \(( -\infty, \infty )\).
6Step 6: Graph the Parabola by Hand
Draw the y-axis and x-axis on a graph paper. Plot the vertex at \((0, -3)\). Since it opens to the left, draw a horizontal parabola by marking points symmetrically around and moving leftwards from the vertex.
7Step 7: Verify Using a Graphing Calculator
Input the equation \( x = -2(y+3)^2 \) into a graphing calculator. Check that the graph matches your hand-drawn sketch, with the vertex at \((0, -3)\), opening to the left.
Key Concepts
Vertex of ParabolaAxis of SymmetryDomain and Range
Vertex of Parabola
The vertex of a parabola is a significant point that denotes its highest or lowest position, depending on the orientation. In the equation \( x = -2(y+3)^2 \) given in vertex form \( x = a(y-k)^2 + h \), the vertex can be directly identified because it is indicated by the terms \( (h, k) \). Here, the values \( h = 0 \) and \( k = -3 \) give us a vertex at the point \( (0, -3) \).
- The vertex is the turning point of the parabola, where it changes direction.
- For a horizontally opening parabola, the vertex is a point on the x-axis plane corresponding to \( x = h \).
Axis of Symmetry
The axis of symmetry of a parabola is an imaginary line that serves as a mirror, dividing the parabola into two equal halves. For horizontally opening parabolas, like in our equation \( x = -2(y+3)^2 \), the axis of symmetry is a horizontal line.
You can find this axis by simply looking at the y-coordinate of the vertex. In this case, with the vertex at \( (0, -3) \), the axis of symmetry is the line \( y = -3 \). Essentially, this means every point on the parabola has a mirror point equally distant from this line.
You can find this axis by simply looking at the y-coordinate of the vertex. In this case, with the vertex at \( (0, -3) \), the axis of symmetry is the line \( y = -3 \). Essentially, this means every point on the parabola has a mirror point equally distant from this line.
- The axis of symmetry helps in drawing the parabola and ensuring that it is symmetrical.
- For vertically opening parabolas, the axis of symmetry is vertical, represented by \( x = h \).
- For horizontally opening parabolas, the axis is horizontal, represented by \( y = k \).
Domain and Range
In mathematics, understanding the domain and range of a function is key to knowing which values will be produced as outputs. For the given horizontal parabola \( x = -2(y+3)^2 \), we explore both the domain and the range:
Domain:
Since the parabola opens to the left and the vertex is at \( x = 0 \), the domain includes all x-values \( x \leq 0 \). This means the parabola stretches infinitely towards the negative x-axis, covering values \((-\infty, 0] \).
Range:
For horizontal parabolas, the range includes all real y-values, as there is no restriction on y. Thus, the range for this parabola is \((-\infty, \infty) \).
Domain:
Since the parabola opens to the left and the vertex is at \( x = 0 \), the domain includes all x-values \( x \leq 0 \). This means the parabola stretches infinitely towards the negative x-axis, covering values \((-\infty, 0] \).
Range:
For horizontal parabolas, the range includes all real y-values, as there is no restriction on y. Thus, the range for this parabola is \((-\infty, \infty) \).
- Domain: A set of x-values that the parabola touches or covers. For horizontal parabolas, it is determined by movement towards either the right or left from the vertex.
- Range: A set of y-values that the parabola spans, covering all possible y-values between its upward or downward extent.
Other exercises in this chapter
Problem 104
Graph each parabola by hand, and check using a graphing calculator. Give the vertex, axis, domain, and range. $$(y+2)^{2}=x+1$$
View solution Problem 105
Graph each parabola by hand, and check using a graphing calculator. Give the vertex, axis, domain, and range. $$x=(y-4)^{2}+2$$
View solution Problem 107
Graph each parabola by hand, and check using a graphing calculator. Give the vertex, axis, domain, and range. $$x=\frac{2}{3} y^{2}-4 y+8$$
View solution Problem 108
Graph each parabola by hand, and check using a graphing calculator. Give the vertex, axis, domain, and range. $$x=y^{2}+2 y-8$$
View solution