Problem 106

Question

Factor each trinomial of the form \(x^{2}+b x y+c y^{2}\). \(p^{2}-2 p q-35 q^{2}\)

Step-by-Step Solution

Verified
Answer
The factors are \((p - 7q)(p + 5q)\).
1Step 1 - Identify coefficients
Observe the trinomial in the form of \(p^{2} + b p q + c q^{2}\). In this case, \(b = -2\) and \(c = -35\).
2Step 2 - Find two numbers that multiply and sum correctly
We need to find two numbers that multiply to \( -35 \) (the constant term, \(c\)) and add to \(-2\) (the coefficient of the middle term, \(b\)). These numbers are \(-7\) and \(5\), since \((-7) \times 5 = -35\) and \((-7) + 5 = -2\).
3Step 3 - Rewrite the trinomial
Rewrite \(p^{2} - 2 p q - 35 q^{2}\) as \(p^{2} - 7 p q + 5 p q - 35 q^{2}\).
4Step 4 - Factor by grouping
Group the expression into two pairs and factor each pair: \((p^2 - 7pq) + (5pq - 35q^2)\). From each pair, factor out the common term: \(p(p - 7q) + 5q(p - 7q)\).
5Step 5 - Factor out the common binomial
Factor out the common binomial factor \((p - 7q)\): \((p - 7q)(p + 5q)\).

Key Concepts

algebraic factoringtrinomial expressionspolynomial factoring
algebraic factoring
Algebraic factoring is a fundamental concept in algebra that simplifies complex expressions. Factoring means breaking down a large expression into simpler parts (factors) that, when multiplied together, give the original expression.
For instance, factoring transforms sums or differences of terms into a product of simpler factors.
This is extremely useful in solving equations, simplifying expressions, and even in other areas of mathematics such as calculus.
In the given exercise, we are specifically dealing with the factoring of trinomials.