Problem 106
Question
Factor each trinomial of the form \(x^{2}+b x y+c y^{2}\). \(p^{2}-2 p q-35 q^{2}\)
Step-by-Step Solution
Verified Answer
The factors are \((p - 7q)(p + 5q)\).
1Step 1 - Identify coefficients
Observe the trinomial in the form of \(p^{2} + b p q + c q^{2}\). In this case, \(b = -2\) and \(c = -35\).
2Step 2 - Find two numbers that multiply and sum correctly
We need to find two numbers that multiply to \( -35 \) (the constant term, \(c\)) and add to \(-2\) (the coefficient of the middle term, \(b\)). These numbers are \(-7\) and \(5\), since \((-7) \times 5 = -35\) and \((-7) + 5 = -2\).
3Step 3 - Rewrite the trinomial
Rewrite \(p^{2} - 2 p q - 35 q^{2}\) as \(p^{2} - 7 p q + 5 p q - 35 q^{2}\).
4Step 4 - Factor by grouping
Group the expression into two pairs and factor each pair: \((p^2 - 7pq) + (5pq - 35q^2)\). From each pair, factor out the common term: \(p(p - 7q) + 5q(p - 7q)\).
5Step 5 - Factor out the common binomial
Factor out the common binomial factor \((p - 7q)\): \((p - 7q)(p + 5q)\).
Key Concepts
algebraic factoringtrinomial expressionspolynomial factoring
algebraic factoring
Algebraic factoring is a fundamental concept in algebra that simplifies complex expressions. Factoring means breaking down a large expression into simpler parts (factors) that, when multiplied together, give the original expression.
For instance, factoring transforms sums or differences of terms into a product of simpler factors.
This is extremely useful in solving equations, simplifying expressions, and even in other areas of mathematics such as calculus.
In the given exercise, we are specifically dealing with the factoring of trinomials.
For instance, factoring transforms sums or differences of terms into a product of simpler factors.
This is extremely useful in solving equations, simplifying expressions, and even in other areas of mathematics such as calculus.
In the given exercise, we are specifically dealing with the factoring of trinomials.
trinomial expressions
Trinomial expressions are polynomials composed of three terms.
A common class of trinomials has a form like this: ewline + +
For example, consider the trinomial given in the exercise: ewline
A common class of trinomials has a form like this: ewline + +
For example, consider the trinomial given in the exercise: ewline
.
This can be considered as having the structure , where each term plays a specific role in the factoring process.
The quadratic term is p^2 unlike ax^2 in the common form.
The linear term
Understanding how to identify these components is crucial to successfully factoring the trinomial.
polynomial factoring
Polynomial factoring is the process of expressing a polynomial as a product of its factors.
When you factor a polynomial, you break it down into simpler polynomials that can be multiplied together to get the original polynomial.
This is very helpful in solving polynomial equations, simplifying expressions, and understanding the properties of polynomials.
In the exercise, we factored the trinomial
When you factor a polynomial, you break it down into simpler polynomials that can be multiplied together to get the original polynomial.
This is very helpful in solving polynomial equations, simplifying expressions, and understanding the properties of polynomials.
In the exercise, we factored the trinomial
into two binomials:
and
.
The process involves several key steps:
- Identifying the coefficients and constants in the trinomial.
- Finding two numbers that multiply to the constant term and add to the coefficient of the middle term.
- Rewriting the trinomial using these numbers.
- Grouping and factoring the resulting pairs of terms.
Other exercises in this chapter
Problem 104
Factor each trinomial of the form \(x^{2}+b x y+c y^{2}\). \(p^{2}-8 p q-65 q^{2}\)
View solution Problem 105
Factor each trinomial of the form \(x^{2}+b x y+c y^{2}\). \(m^{2}-64 m n-65 n^{2}\)
View solution Problem 107
Factor each trinomial of the form \(x^{2}+b x y+c y^{2}\). \(a^{2}+5 a b-24 b^{2}\)
View solution Problem 108
Factor each trinomial of the form \(x^{2}+b x y+c y^{2}\). \(r^{2}+3 r s-28 s^{2}\)
View solution