Problem 106
Question
Determine whether each statement makes sense or does not make sense, and explain your reasoning. Special-product formulas have patterns that make their multiplications quicker than using the FOIL method.
Step-by-Step Solution
Verified Answer
The statement makes partial sense. Special-product formulas do have patterns that can make their multiplications quicker than using the FOIL method but this is only applicable to specific patterns and not in general.
1Step 1: Understand Special-Product Formulas
Special-product formulas are shortcuts used in algebra to quickly multiply two expressions of the form \( (a + b)(a - b) \), \( (a + b)^2 \), and \( (a - b)^2 \).
2Step 2: Understand the FOIL Method
The FOIL method is another way to multiply two binomials. The acronym FOIL stands for first, outer, inner, last, referring to the four multiplications that occur: multiply the first terms of each binomial, the outer terms, the inner terms, and lastly the last terms.
3Step 3: Compare the Two Methods
Comparing the two methods, the FOIL method involves a systematic way to perform four multiplications for any two binomials. On the other hand, special-product formulas, when applicable, can further simplify these multiplications. However, it is not generally quicker than the FOIL method but in certain cases with specific patterns, it can be quicker.
Other exercises in this chapter
Problem 105
Perform the indicated computations. Write the answers in scientifi c notation. If necessary, round the decimal factor in your scientific notation answer to two
View solution Problem 106
Simplify by reducing the index of the radical. $$\sqrt[9]{x^{6}}$$
View solution Problem 106
Factor completely. $$ 7 x^{4}+34 x^{2}-5 $$
View solution Problem 106
Perform the indicated operations. $$\frac{1}{x^{n}-1}-\frac{1}{x^{n}+1}-\frac{1}{x^{2 n}-1}$$
View solution