Problem 105
Question
Suppose \(g(x)=f(1-x)\) for all \(x, \lim _{x \rightarrow 1^{+}} f(x)=4,\) and \(\lim _{x \rightarrow 1^{-}} f(x)=6 .\) Find \(\lim _{x \rightarrow 0^{+}} g(x)\) and \(\lim _{x \rightarrow 0^{-}} g(x)\).
Step-by-Step Solution
Verified Answer
Answer: The right-hand limit of g(x) as x approaches 0 is 6, and the left-hand limit of g(x) as x approaches 0 is 4.
1Step 1: Define g(x) and Find Its Limits
We are given that \(g(x) = f(1 - x)\). We want to find \(\lim_{x \rightarrow 0^{+}} g(x)\) and \(\lim_{x \rightarrow 0^{-}} g(x)\).
2Step 2: Substitute x with 1 - x
Let's make the substitution \(u = 1 - x\). Since we want to find the right-hand limit of g(x), we need to see how u behaves when x approaches 0 from the right, or in other words when \(x \rightarrow 0^{+}\). Under this condition, \(u = 1 - x\) will approach 1 from the left, which is denoted as \(u \rightarrow 1^{-}\).
Similarly, if x approaches 0 from the left, or \(x \rightarrow 0^{-}\), then \(u = 1 - x\) will approach 1 from the right, denoted as \(u \rightarrow 1^{+}\).
3Step 3: Apply the Limits to g(x)
Now, we can apply the limits to g(x) in terms of u:
$$\lim_{x \rightarrow 0^{+}} g(x) = \lim_{u \rightarrow 1^{-}} f(u) = 6$$
And
$$\lim_{x \rightarrow 0^{-}} g(x) = \lim_{u \rightarrow 1^{+}} f(u) = 4$$
So we have our final answers:
4Step 4: Find the Right-Hand and Left-Hand Limits
The right-hand limit of g(x) as x approaches 0 is 6:
$$\lim_{x \rightarrow 0^{+}} g(x) = 6$$
And the left-hand limit of g(x) as x approaches 0 is 4:
$$\lim_{x \rightarrow 0^{-}} g(x) = 4$$
Key Concepts
Limit from the RightLimit from the LeftSubstitution Method
Limit from the Right
When we talk about finding the "Limit from the Right," we mean analyzing the behavior of a function as the input value approaches a specific number from values greater than that number. In mathematical terms, for a function \(f(x)\), if we are considering the limit as \(x\) approaches a number \(c\) from the right, we write it as \(\lim_{x \rightarrow c^{+}} f(x)\). Here, \(x\) gets closer to \(c\) by taking values that are slightly larger than \(c\).
In the original exercise, we have a function \(g(x) = f(1 - x)\) and we need to find \(\lim_{x \rightarrow 0^{+}} g(x)\). To do this, we substitute \(u = 1 - x\). As \(x\) approaches \(0\) from the right, \(u\) approaches \(1\) from the left. This means we are evaluating \(\lim_{u \rightarrow 1^{-}} f(u)\).
According to the given information, \(\lim_{x \rightarrow 1^{-}} f(x) = 6\), which means those approaching from values less than 1 lead \(f(x)\) to 6. Therefore, \(\lim_{x \rightarrow 0^{+}} g(x) = 6\).
In the original exercise, we have a function \(g(x) = f(1 - x)\) and we need to find \(\lim_{x \rightarrow 0^{+}} g(x)\). To do this, we substitute \(u = 1 - x\). As \(x\) approaches \(0\) from the right, \(u\) approaches \(1\) from the left. This means we are evaluating \(\lim_{u \rightarrow 1^{-}} f(u)\).
According to the given information, \(\lim_{x \rightarrow 1^{-}} f(x) = 6\), which means those approaching from values less than 1 lead \(f(x)\) to 6. Therefore, \(\lim_{x \rightarrow 0^{+}} g(x) = 6\).
- Identify the input approaching from the right.
- Make substitution adjustments if necessary.
- Apply the known limits of the original function \(f(x)\).
Limit from the Left
The "Limit from the Left" involves understanding how a function behaves as its input approaches a specific number from smaller values. For a function \(f(x)\), the limit as \(x\) approaches \(c\) from the left is written as \(\lim_{x \rightarrow c^{-}} f(x)\). Here, \(x\) nears \(c\) from values that are slightly less than \(c\).
In the problem, we determined \(g(x)\) as \(f(1 - x)\) and sought \(\lim_{x \rightarrow 0^{-}} g(x)\). By setting \(u = 1 - x\), as \(x\) nears \(0\) from the left, \(u\) nears \(1\) from the right, transitioning us to \(\lim_{u \rightarrow 1^{+}} f(u)\).
From the problem's premise, \(\lim_{x \rightarrow 1^{+}} f(x) = 4\), indicating that as we approach 1 from greater values, \(f(x)\) equals 4. Thus, \(\lim_{x \rightarrow 0^{-}} g(x) = 4\).
In the problem, we determined \(g(x)\) as \(f(1 - x)\) and sought \(\lim_{x \rightarrow 0^{-}} g(x)\). By setting \(u = 1 - x\), as \(x\) nears \(0\) from the left, \(u\) nears \(1\) from the right, transitioning us to \(\lim_{u \rightarrow 1^{+}} f(u)\).
From the problem's premise, \(\lim_{x \rightarrow 1^{+}} f(x) = 4\), indicating that as we approach 1 from greater values, \(f(x)\) equals 4. Thus, \(\lim_{x \rightarrow 0^{-}} g(x) = 4\).
- Identify approaching values from the left side.
- Make basic substitutions possibly required.
- Utilize provided limits for \(f(x)\) to solve \(g(x)\).
Substitution Method
The substitution method can simplify complex limit problems by transforming a function into a more manageable form. This tactic involves substituting a part of the expression with a different variable, making it easier to analyze the limit.
In the given task, \(g(x) = f(1 - x)\) required finding its limit as \(x\) approached both sides of zero. The substitution \(u = 1 - x\) was crucial. It allowed converting the problem from finding the limit of \(g(x)\) as \(x\) neared 0 to a more straightforward limit involving \(f(u)\) as \(u\) approached 1, either from the left or right.
Steps to employ substitution effectively include:
In the given task, \(g(x) = f(1 - x)\) required finding its limit as \(x\) approached both sides of zero. The substitution \(u = 1 - x\) was crucial. It allowed converting the problem from finding the limit of \(g(x)\) as \(x\) neared 0 to a more straightforward limit involving \(f(u)\) as \(u\) approached 1, either from the left or right.
Steps to employ substitution effectively include:
- Identify parts of the function that complicate taking a limit, such as "1 - x" in this exercise.
- Introduce a simpler variable such as \(u = 1 - x\). This aligns the problem with the known behaviors of \(f(x)\).
- Re-evaluate the limit in terms of new variables to use existing information or limits.
Other exercises in this chapter
Problem 104
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