Problem 105
Question
Solve each equation. $$ 6+4 t-1=6-15 t+12 t-8 $$
Step-by-Step Solution
Verified Answer
The solution to the equation is \(t = -1\).
1Step 1: Simplify Each Side
First, simplify the expression on each side of the equation. On the left side: \[ 6 + 4t - 1 = 5 + 4t \]On the right side: \[ 6 - 15t + 12t - 8 = -2 - 3t \] So the equation becomes: \[ 5 + 4t = -2 - 3t \]
2Step 2: Move Variable Terms to One Side
Choose one side of the equation to move all the variable terms to. Let's move all terms involving \(t\) to the left side.Add \(3t\) to both sides:\[ 5 + 4t + 3t = -2 - 3t + 3t \]This simplifies to:\[ 5 + 7t = -2 \]
3Step 3: Isolate the Variable Term
To solve for \(t\), you need to isolate the \(t\) term.Subtract 5 from both sides:\[ 5 + 7t - 5 = -2 - 5 \]Which simplifies to:\[ 7t = -7 \]
4Step 4: Solve for the Variable
Divide both sides by 7 to solve for \(t\):\[ t = \frac{-7}{7} \]Simplifying gives:\[ t = -1 \]
Key Concepts
Simplifying ExpressionsSolving EquationsIsolate the Variable
Simplifying Expressions
When working with linear equations, the first step is often to simplify the expressions on each side. Simplifying means changing the expression to its simplest form. You do this by combining like terms. Like terms are terms that contain the same variable raised to the same power.
For example, in the equation, terms like \(4t\) and \(-15t\) are like terms because they both contain the variable \(t\). You can combine them by adding or subtracting their coefficients (the numbers in front of the variables).
In the given exercise, we start by simplifying both sides:
For example, in the equation, terms like \(4t\) and \(-15t\) are like terms because they both contain the variable \(t\). You can combine them by adding or subtracting their coefficients (the numbers in front of the variables).
In the given exercise, we start by simplifying both sides:
- On the left side: \(6 + 4t - 1\) becomes \(5 + 4t\); we combined \(6\) and \(-1\).
- On the right side: \(6 - 15t + 12t - 8\) simplifies to \(-2 - 3t\). We combined \(-15t\) and \(12t\), as well as \(6\) and \(-8\).
Solving Equations
Once the expressions are simplified, the next task is to solve the equation. Solving equations involves finding the value of the variable that makes the equation true.
In our example, after simplification, we have \(5 + 4t = -2 - 3t\). The strategy to solve this is to get all terms containing the variable on one side of the equation and constant terms on the other side.
Here's how you continue:
In our example, after simplification, we have \(5 + 4t = -2 - 3t\). The strategy to solve this is to get all terms containing the variable on one side of the equation and constant terms on the other side.
Here's how you continue:
- Add \(3t\) to both sides to get \(5 + 4t + 3t = -2 - 3t + 3t\), which simplifies to \(5 + 7t = -2\).
Isolate the Variable
The final part of solving a linear equation involves isolating the variable. This means getting the variable by itself on one side of the equation, so that you can clearly see its value.
Continuing from our example, we now have \(5 + 7t = -2\). Here’s how to isolate \(t\):
Continuing from our example, we now have \(5 + 7t = -2\). Here’s how to isolate \(t\):
- Subtract \(5\) from both sides to move constant terms away from the side with \(t\): \(5 + 7t - 5 = -2 - 5\) simplifies to \(7t = -7\).
- Finally, divide both sides by the coefficient of \(t\), which is \(7\): \(t = \frac{-7}{7}\), simplifying to \(t = -1\).
Other exercises in this chapter
Problem 104
Evaluate each expression. $$ \text { a. } 2 \cdot 3^{2} $$
View solution Problem 105
Simplify each expression. $$3 x^{2}-\left(-2 x^{2}\right)-5 x^{2}$$
View solution Problem 105
Simplify each expression. $$ (16 b+8)\left(\frac{5}{4}\right)-8 b $$
View solution Problem 105
Evaluate each expression. a. Subtract \(-3.9\) from \(-11.2\) b. Subtract \(-11.2\) from \(-3.9\)
View solution