Problem 105
Question
In Exercises 93 - 106, find the sum of the infinite geometric series. \( \dfrac{1}{9} - \dfrac{1}{3} + 1 - 3 + \cdots \)
Step-by-Step Solution
Verified Answer
The sum of the given infinite geometric series is \( -0.025 \).
1Step 1: Identifying the first term (a)
The first term \( a \) of the geometric series is the first number in the series, which is \( \dfrac{1}{9} \).
2Step 2: Identifying the common ratio (r)
The common ratio \( r \) of the geometric series can be obtained by dividing the second term by the first term, or dividing the third term by the second term, and so on. Here, \( r = \dfrac{- \dfrac{1}{3}}{\dfrac{1}{9}} = -3 \).
3Step 3: Applying the formula for the sum of an infinite geometric series
Using the formula \( S = \dfrac{a}{1-r} \), we can substitute \( a = \dfrac{1}{9} \) and \( r = -3 \), which gives us \( S = \dfrac{\dfrac{1}{9}}{1-(-3)} = -0.025 \).
Key Concepts
Common RatioGeometric Series Sum FormulaFirst Term Identification
Common Ratio
In a geometric series, the common ratio is a critical component. It determines how each term in the series relates to the one before it. To find the common ratio \( r \), you divide any term in the series by the preceding term. This process needs to be consistent for every consecutive term.
For instance, if you begin with a series like \( \frac{1}{9}, -\frac{1}{3}, 1, -3, \ldots \), you find the common ratio by calculating \( r = \frac{-\frac{1}{3}}{\frac{1}{9}} \). Here, each fraction represents a term, and the division shows how the series transforms from one term to the next. Finding this ratio is crucial because it directs whether or not the series will converge, particularly in infinite series.
For instance, if you begin with a series like \( \frac{1}{9}, -\frac{1}{3}, 1, -3, \ldots \), you find the common ratio by calculating \( r = \frac{-\frac{1}{3}}{\frac{1}{9}} \). Here, each fraction represents a term, and the division shows how the series transforms from one term to the next. Finding this ratio is crucial because it directs whether or not the series will converge, particularly in infinite series.
Geometric Series Sum Formula
The geometric series sum formula is a powerful tool for evaluating the sum of an infinite geometric series. The formula is given by \( S = \frac{a}{1-r} \), where \( S \) is the sum of the series, \( a \) is the first term, and \( r \) is the common ratio.
With this formula, you can determine the sum of an infinite geometric series provided that the absolute value of \( r \) is less than 1, which ensures the series converges. If \( |r| \geq 1 \), then the series does not have a sum, as it either diverges or equals infinity. In our example, this formula was applied with \( a = \frac{1}{9} \) and \( r = -3 \), which interestingly indicates a divergence rather than a valid sum for a converging series.
With this formula, you can determine the sum of an infinite geometric series provided that the absolute value of \( r \) is less than 1, which ensures the series converges. If \( |r| \geq 1 \), then the series does not have a sum, as it either diverges or equals infinity. In our example, this formula was applied with \( a = \frac{1}{9} \) and \( r = -3 \), which interestingly indicates a divergence rather than a valid sum for a converging series.
First Term Identification
Identifying the first term \( a \) is the foundational step when dealing with any geometric series, including those that are infinite. It is simply the initial value you start from in the sequence of numbers.
For the series \( \frac{1}{9}, -\frac{1}{3}, 1, -3, \ldots \), the first term, \( a \), is \( \frac{1}{9} \). This term sets the stage for the rest of the series because it is the reference point from which the series evolves based on the common ratio. Acknowledging this first term correctly ensures accurate calculations for further analysis, including determining possible convergence and calculating the series sum using the geometric series sum formula.
For the series \( \frac{1}{9}, -\frac{1}{3}, 1, -3, \ldots \), the first term, \( a \), is \( \frac{1}{9} \). This term sets the stage for the rest of the series because it is the reference point from which the series evolves based on the common ratio. Acknowledging this first term correctly ensures accurate calculations for further analysis, including determining possible convergence and calculating the series sum using the geometric series sum formula.
Other exercises in this chapter
Problem 103
In Exercises 103-112, use sigma notation to write the sum. \( \dfrac{1}{3(1)} + \dfrac{1}{3(2)} + \dfrac{1}{3(3)} + \cdots + \dfrac{1}{3(9)} \)
View solution Problem 104
In Exercises 103-112, use sigma notation to write the sum. \( \dfrac{5}{1 + 1} + \dfrac{5}{1 + 2} + \dfrac{5}{1 + 3} + \cdots + \dfrac{5}{1 + 15} \)
View solution Problem 105
In Exercises 105 and 106, determine whether the statement is true or false. Justify your answer. Given an arithmetic sequence for which only the first two terms
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In Exercises 103-112, use sigma notation to write the sum. \( [2 \left(\dfrac{1}{8} \right) + 3] + [2 \left(\dfrac{2}{8} \right) + 3] + \cdots + [2 \left(\dfrac
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