Problem 105
Question
In Exercises \(105-110\), find the difference quotient \(\frac{f(x+h)-f(x)}{h}\) \(h \neq 0,\) for the given function \(f\). $$f(x)=3 x-1$$
Step-by-Step Solution
Verified Answer
The difference quotient of the function \(f(x) = 3x - 1\) is \(3\).
1Step 1: Substitution
Substitute \(x+h\) into the function \(f\), so \(f(x + h) = 3(x + h) - 1\). After doing that, distribute the \(3\) in \(3(x + h)\) and evaluate \(f(x+h) = 3x + 3h - 1\)
2Step 2: Difference Quotient
Set up the difference quotient. Substitute \(f(x+h)\) and \(f(x)\) into the formula: \[\frac{f(x+h) - f(x)}{h} = \frac{(3x + 3h - 1) - (3x - 1)}{h}.\] After doing that, simplify the expression by combining like terms: \[\frac{3h}{h}\]
3Step 3: Simplify
Finally, simplify the ratio by dividing \(3h\) by \(h\) to get \(3\).
Key Concepts
Understanding FunctionsAlgebra Techniques in Difference QuotientsSimplifying Expressions
Understanding Functions
A function is a special relationship between two sets of numbers or objects, generally expressed as a rule. For each input value (often referred to as "x"), there is exactly one output value (referred to as "f(x)"). This mapping rule is what defines a function. For example, in our given function,
\[ f(x) = 3x - 1 \]we have a linear function since it forms a straight line when graphed. Linear functions have constant rates of change, which means that as you move from one point to another, the change in "y" is proportional to the change in "x".
\[ f(x) = 3x - 1 \]we have a linear function since it forms a straight line when graphed. Linear functions have constant rates of change, which means that as you move from one point to another, the change in "y" is proportional to the change in "x".
- The input "x" is multiplied by a constant (in this case 3).
- Then a constant is subtracted or added (here, we subtract 1).
Algebra Techniques in Difference Quotients
Algebra is the branch of mathematics that deals with symbols and the rules for manipulating those symbols. It is the foundation for understanding the difference quotient, a way to measure the rate at which function outputs change as input values change.
To find the difference quotient, you begin by substituting \(x + h\) into the function. This involves using algebra to expand or manipulate the expression. In the context of our exercise:
To find the difference quotient, you begin by substituting \(x + h\) into the function. This involves using algebra to expand or manipulate the expression. In the context of our exercise:
- Start by substituting \(x + h\) into the function: \(f(x+h) = 3(x + h) - 1\).
- Use the distributive property (multiplying each term by 3): \(3x + 3h - 1\).
Simplifying Expressions
Simplification is the process of reducing an expression to its most basic form while maintaining its original value or meaning. This helps to make the expression easier to work with or understand.
In our problem, after setting up the difference quotient:\[\frac{f(x+h) - f(x)}{h} = \frac{(3x + 3h - 1) - (3x - 1)}{h},\]you'll want to simplify by:
In our problem, after setting up the difference quotient:\[\frac{f(x+h) - f(x)}{h} = \frac{(3x + 3h - 1) - (3x - 1)}{h},\]you'll want to simplify by:
- Combining like terms (in this case, after the subtraction, the terms \(3x\) cancel out).
- Simplifying the resulting expression \(\frac{3h}{h}\) by dividing both numerator and denominator by \(h\).
Other exercises in this chapter
Problem 103
In Exercises \(101-104,\) let \(f(t)=3 t+1\) and \(g(x)=x^{2}+4\). Find an expression for \((f \circ f)(t)\), and give the domain of \(f \circ f\)
View solution Problem 104
In Exercises \(101-104,\) let \(f(t)=3 t+1\) and \(g(x)=x^{2}+4\). Find an expression for \((g \circ g)(x),\) and give the domain of \(g \circ g\)
View solution Problem 106
In Exercises \(105-110\), find the difference quotient \(\frac{f(x+h)-f(x)}{h}\) \(h \neq 0,\) for the given function \(f\). $$f(x)=-2 x+3$$
View solution Problem 107
In Exercises \(105-110\), find the difference quotient \(\frac{f(x+h)-f(x)}{h}\) \(h \neq 0,\) for the given function \(f\). $$f(x)=-x^{2}+x$$
View solution