Problem 105
Question
How many optically active stereoisomers are possible for butan- 2,3 -diol? (a) 1 (b) 2 (c) 3 (d) 4
Step-by-Step Solution
Verified Answer
2 optically active stereoisomers are possible for butan-2,3-diol.
1Step 1: Determine the Number of Chiral Centers
To find the number of optically active stereoisomers, we must first determine the number of chiral centers in butan-2,3-diol. A chiral center is a carbon atom that has four different groups attached to it. In butan-2,3-diol, the structure is CH3-CHOH-CHOH-CH3. Each of the two central carbon atoms (C2 and C3) is attached to four different groups: a hydrogen atom, a hydroxyl group (-OH), a methyl group (CH3), and the rest of the molecule. Therefore, there are 2 chiral centers in butan-2,3-diol.
2Step 2: Calculate Possible Stereoisomers
The formula to calculate the maximum number of stereoisomers is 2^n, where n is the number of chiral centers. Since butan-2,3-diol has 2 chiral centers (as found in Step 1), the maximum number of stereoisomers is 2^2 = 4.
3Step 3: Identify Optically Active Stereoisomers
Optically active stereoisomers are those that rotate plane-polarized light. They come in enantiomeric pairs, which are nonsuperimposable mirror images of each other. Since the calculation in Step 2 gives 4 stereoisomers, they can exist as two pairs of enantiomers, resulting in 2 optically active stereoisomers.
Key Concepts
Chiral CentersStereoisomers CalculationEnantiomersButan-2,3-diol
Chiral Centers
In organic chemistry, a chiral center is a crucial concept for identifying the potential optical activity of a compound. A chiral center, also known as a stereocenter, is typically a carbon atom bearing four distinct substituents. This distinct arrangement creates a situation where the molecule can exist in two non-superimposable mirror images, known as enantiomers.
In the case of butan-2,3-diol, the structure features two chiral centers at the second and third carbon atoms. Here is how it breaks down:
In the case of butan-2,3-diol, the structure features two chiral centers at the second and third carbon atoms. Here is how it breaks down:
- At the second carbon (C2), the substituents are a hydrogen atom, a hydroxyl group (-OH), a methyl group (CH3), and the rest of the molecule.
- Similarly, the third carbon (C3) has the same four different groups attached.
Stereoisomers Calculation
Once the number of chiral centers is determined, calculating the total number of possible stereoisomers becomes straightforward. The formula used is 2n, where n is the number of chiral centers.
For butan-2,3-diol, having two chiral centers means we apply the formula as follows:
For butan-2,3-diol, having two chiral centers means we apply the formula as follows:
- Number of chiral centers, n = 2
- Maximum stereoisomers = 22 = 4
Enantiomers
Enantiomers are a type of stereoisomer that are especially important in understanding optical activity. They are non-superimposable mirror images of each other, much like left and right hands. Each enantiomer in a pair will rotate plane-polarized light in opposite directions, a property termed optical activity.
In the context of butan-2,3-diol, with four stereoisomers calculated, these can be paired into enantiomers. Since each pair consists of two enantiomers, the enantiomeric pairs are responsible for the optical activity observed in these molecules. Here are the key characteristics of enantiomers:
In the context of butan-2,3-diol, with four stereoisomers calculated, these can be paired into enantiomers. Since each pair consists of two enantiomers, the enantiomeric pairs are responsible for the optical activity observed in these molecules. Here are the key characteristics of enantiomers:
- Identical physical properties (melting point, boiling point, etc.) except for their interaction with plane-polarized light and chiral environments.
- One enantiomer will rotate polarized light clockwise (dextrorotatory), while the other will rotate it counterclockwise (levorotatory).
Butan-2,3-diol
Butan-2,3-diol is a simple organic molecule that serves as an excellent example for studying chirality and stereochemistry. The molecule has the formula CH3-CHOH-CHOH-CH3. This particular compound is noteworthy because it includes two adjacent chiral centers, making it capable of forming multiple stereoisomers.
Here are some essential aspects:
Here are some essential aspects:
- It contains two hydroxyl groups (-OH) attached to the second and third carbon atoms, which contribute significantly to its reactivity and solubility properties.
- The presence of two chiral centers allows the molecule to form four stereoisomers, including two pairs of enantiomers.
- Understanding the structure of butan-2,3-diol provides insight into how molecular chirality affects physical and chemical properties.
Other exercises in this chapter
Problem 103
Which of the following compounds will exhibit geometrical isomerism? (a) 1-phenyl-2-butene (b) 3 -phenyl-1-butene (c) 2 -phenyl-1-butene (d) 1,1 -diphenyl-1-pro
View solution Problem 104
Which of the following compounds will show geometrical isomerism? 1\. 2 -butene 2\. propene 3\. 1 -phenylpropene 4\. 2 -methylbut-2-ene (a) 1,2 (b) 3,4 (c) \(1,
View solution Problem 110
Which is true regarding the \(\mathrm{HOCH}_{2}-(\mathrm{CHOH})_{4}\) \(-\mathrm{CH}_{2} \mathrm{OH} ?\) (1) the number of racemic mixtures will be four for the
View solution Problem 112
Match the following: List I List II 1\. \(\mathrm{CH}_{3} \mathrm{COOH}\) and \(\mathrm{HCOOCH}_{3}\) (i) metamers 2\. \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm
View solution