Problem 105
Question
For any positive integers \(m, n\) (with \(n \geq m\) ), let and \(\left(\begin{array}{l}n \\ m\end{array}\right)={ }^{n} C_{m}\), then \(\left(\begin{array}{l}n \\ m\end{array}\right)+\left(\begin{array}{l}n-1 \\\ m\end{array}\right)+\left(\begin{array}{l}n-2 \\\ m\end{array}\right)+\ldots+\left(\begin{array}{c}m \\ m\end{array}\right)=\) (A) \(\left(\begin{array}{l}n+1 \\ m\end{array}\right)\) (B) \(\left(\begin{array}{l}n+1 \\ m+1\end{array}\right)\) (C) \(\left(\begin{array}{c}n \\ m+1\end{array}\right)\) (D) None of these
Step-by-Step Solution
Verified Answer
The answer is (B) \( \binom{n+1}{m+1} \).
1Step 1: Understand the Problem
We need to determine the sum of a series of binomial coefficients: \( \binom{n}{m} + \binom{n-1}{m} + \binom{n-2}{m} + \ldots + \binom{m}{m} \). We will use properties of binomial coefficients and combinatorial identities to find this sum.
2Step 2: Recognize the Pattern
The sequence given: \( \binom{n}{m}, \binom{n-1}{m}, \ldots, \binom{m}{m} \) resembles parts of a binomial coefficient identity, specifically the identity used for downward sums. Consider a possible identity that helps with sums like \( \binom{n}{k} + \binom{n-1}{k} + \cdots + \binom{k}{k} \).
3Step 3: Apply the Relevant Identity
There's a relevant identity in combinatorics: \( \binom{n}{k} + \binom{n-1}{k} + \cdots + \binom{k}{k} = \binom{n+1}{k+1} \). This translates here to: \( \binom{n}{m} + \binom{n-1}{m} + \cdots + \binom{m}{m} = \binom{n+1}{m+1} \).
4Step 4: Compare with Problem Options
Recall the choices provided. The matching expression from the identity is \( \binom{n+1}{m+1} \), which corresponds to option (B).
5Step 5: Conclusion and Final Answer
Using the binomial coefficient identity, the sum of the given sequence is \( \binom{n+1}{m+1} \), which matches option (B). Therefore, the correct choice is (B) \( \binom{n+1}{m+1} \).
Key Concepts
Combinatorial IdentitiesPascal's IdentityMathematical Induction
Combinatorial Identities
Combinatorial identities play a crucial role in simplifying and solving problems involving binomial coefficients. These involve understanding how combinations of objects can be added, removed, or rearranged in ways that can be described with an equation.
Consider, for instance, a simple identity: \( \binom{n}{k} = \binom{n-1}{k-1} + \binom{n-1}{k} \). This identity reflects that any group of \(k\) items chosen from \(n\) items can either include a specific item or not, leading to an addition of two distinct groups of choices.
In these identities, each term in a sequence can represent a way to count the number of solutions to a problem. Combinatorial identities help verify or discover new ways to count by establishing equality through known expressions.
Consider, for instance, a simple identity: \( \binom{n}{k} = \binom{n-1}{k-1} + \binom{n-1}{k} \). This identity reflects that any group of \(k\) items chosen from \(n\) items can either include a specific item or not, leading to an addition of two distinct groups of choices.
In these identities, each term in a sequence can represent a way to count the number of solutions to a problem. Combinatorial identities help verify or discover new ways to count by establishing equality through known expressions.
- They help in connecting different combinatorial expressions.
- They can provide elegant proofs to complex problems.
- They are essential for developing new mathematical formulas.
Pascal's Identity
Pascal's Identity is a fundamental combinatorial identity that is simple but very powerful. It is named after the French mathematician Blaise Pascal.
This identity is expressed as: \[\binom{n}{k} = \binom{n-1}{k-1} + \binom{n-1}{k} \] What this means is if you want to choose \(k\) items from \(n\) items, you have two choices for the first item: include it or not. The identity breaks down this choice into :
This identity holds up across different levels of problems and illustrates a basic structure of recursive computation. It's not only a useful computational tool but also foundational in understanding more complex identities.
This identity is expressed as: \[\binom{n}{k} = \binom{n-1}{k-1} + \binom{n-1}{k} \] What this means is if you want to choose \(k\) items from \(n\) items, you have two choices for the first item: include it or not. The identity breaks down this choice into :
- \(\binom{n-1}{k-1}\): choosing the first item and then \(k-1\) items from the remaining \(n-1\).
- \(\binom{n-1}{k}\): not choosing the first item and picking all \(k\) items from the rest \(n-1\) items.
This identity holds up across different levels of problems and illustrates a basic structure of recursive computation. It's not only a useful computational tool but also foundational in understanding more complex identities.
Mathematical Induction
Mathematical induction is a key proof technique used widely in mathematics. It is especially useful for proving statements about integers. This method works like a domino effect, where knocking over the first domino causes the whole series to fall.
The process of induction involves two main steps:
Using induction with binomial coefficients often involves proving identities or inequalities. Induction helps ensure the structural reliability of these identities over potentially infinite cases.
Teaching induction through examples, such as proving combinatorial identities, can deeply enhance the understanding of this concept. This makes mathematical induction a cornerstone of logical reasoning in mathematics.
The process of induction involves two main steps:
- Base Case: Prove the statement is true for the initial value.
- Inductive Step: Show if the statement is true for an arbitrary value \(n\), then it is also true for \(n+1\).
Using induction with binomial coefficients often involves proving identities or inequalities. Induction helps ensure the structural reliability of these identities over potentially infinite cases.
Teaching induction through examples, such as proving combinatorial identities, can deeply enhance the understanding of this concept. This makes mathematical induction a cornerstone of logical reasoning in mathematics.
Other exercises in this chapter
Problem 103
The number of words that can be formed, with the letters of the work 'Pataliputra' without changing the relative order of the vowels and consonants, is (A) 3600
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On a new year day every student of a class sends a card to every other student. The postman delivers 600 cards. The number of students in the class are (A) 42 (
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The number of ways of choosing \(m\) coupons out of an unlimited number of coupons bearing the letters \(A, B\) and \(C\) so that they cannot be used to spell t
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The number of ways in which 16 identical things can be distributed among 4 persons if each person gets at least 3 things, is (A) 33 (B) 35 (C) 38 (D) None of th
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