Problem 105
Question
Earth's Crust The following chemical reactions have helped to shape Earth's crust. Determine the oxidation numbers of all the elements in the reactants and products, and identify which elements are oxidized and which are reduced. a. \(3 \mathrm{SiO}_{2}(s)+2 \mathrm{Fe}_{3} \mathrm{O}_{4}(s) \rightarrow 3 \mathrm{Fe}_{2} \mathrm{SiO}_{4}(s)+\mathrm{O}_{2}(g)\) b. \(\operatorname{SiO}_{2}(s)+2 \operatorname{Fe}(s)+\mathrm{O}_{2}(g) \rightarrow \mathrm{Fe}_{2} \mathrm{SiO}_{4}(s)\) c. \(4 \mathrm{FeO}(s)+\mathrm{O}_{2}(g)+6 \mathrm{H}_{2} \mathrm{O}(\ell) \rightarrow 4 \mathrm{Fe}(\mathrm{OH})_{3}(s)\)
Step-by-Step Solution
Verified Answer
Question: In each of the following reactions, identify which elements are oxidized and which elements are reduced:
(a) $3 \mathrm{SiO}_2(s)+2 \mathrm{Fe}_3 \mathrm{O}_4(s) \rightarrow 3 \mathrm{Fe}_2 \mathrm{SiO}_4(s)+\mathrm{O}_2(g)$
(b) $\mathrm{SiO}_2(s)+2 \mathrm{Fe}(s)+\mathrm{O}_2(g) \rightarrow \mathrm{Fe}_2 \mathrm{SiO}_4(s)$
(c) $4 \mathrm{FeO}(s)+\mathrm{O}_2(g)+6 \mathrm{H}_2 \mathrm{O}(l) \rightarrow 4 \mathrm{Fe}(\mathrm{OH})_3(s)$
Answer:
(a) Fe is reduced and O is oxidized.
(b) Fe is oxidized and O in SiO2 is reduced.
(c) Fe is oxidized and O in FeO is reduced.
1Step 1: Assign oxidation numbers to all the elements in the reactants
The oxidation numbers for each element are as follows:
Si in SiO2: +4
O in SiO2: -2
Fe in Fe3O4: +8/3 (average)
O in Fe3O4: -2
2Step 2: Assign oxidation numbers to all the elements in the products
The oxidation numbers for each element are as follows:
Fe in Fe2SiO4: +2
Si in Fe2SiO4: +4
O in Fe2SiO4: -2
O in O2: 0
3Step 3: Identify which elements are oxidized and which are reduced
Comparing the oxidation numbers of the elements in the reactants and products, we can see that:
Fe is reduced (from +8/3 to +2)
O is oxidized (from -2 in Fe3O4 to 0 in O2)
For reaction (b):
$\operatorname{SiO}_{2}(s)+2 \operatorname{Fe}(s)+\mathrm{O}_{2}(g)
\rightarrow \mathrm{Fe}_{2} \mathrm{SiO}_{4}(s)$
4Step 1: Assign oxidation numbers to all the elements in the reactants
The oxidation numbers for each element are as follows:
Si in SiO2: +4
O in SiO2: -2
Fe: 0
O in O2: 0
5Step 2: Assign oxidation numbers to all the elements in the products
The oxidation numbers for each element are as follows:
Fe in Fe2SiO4: +2
Si in Fe2SiO4: +4
O in Fe2SiO4: -2
6Step 3: Identify which elements are oxidized and which are reduced
Comparing the oxidation numbers of the elements in the reactants and products, we can see that:
Fe is oxidized (from 0 to +2)
O in SiO2 is reduced (from -2 to -2 in Fe2SiO4)
For reaction (c):
$4 \mathrm{FeO}(s)+\mathrm{O}_{2}(g)+6 \mathrm{H}_{2} \mathrm{O}(\ell)
\rightarrow 4 \mathrm{Fe}(\mathrm{OH})_{3}(s)$
7Step 1: Assign oxidation numbers to all the elements in the reactants
The oxidation numbers for each element are as follows:
Fe in FeO: +2
O in FeO: -2
O in O2: 0
H in H2O: +1
O in H2O: -2
8Step 2: Assign oxidation numbers to all the elements in the products
The oxidation numbers for each element are as follows:
Fe in Fe(OH)3: +3
O in Fe(OH)3: -2
H in Fe(OH)3: +1
9Step 3: Identify which elements are oxidized and which are reduced
Comparing the oxidation numbers of the elements in the reactants and products, we can see that:
Fe is oxidized (from +2 to +3)
O in FeO is reduced (from -2 to -2 in Fe(OH)3)
Key Concepts
Chemical ReactionsEarth's CrustOxidation and Reduction
Chemical Reactions
Chemical reactions are processes where substances are transformed into new substances with different properties. They involve the rearrangement of atoms to form new compounds.
In the context of the Earth's crust, these reactions can have a significant impact. The Earth's crust is constantly changing due to chemical reactions between minerals. For example, when silicon dioxide \((SiO_2)\) reacts with iron oxide \((Fe_3O_4)\), it forms a new compound, ferrous silicate \((Fe_2SiO_4)\), and oxygen \((O_2)\).
The reactants, \(SiO_2\) and \(Fe_3O_4\), lose and gain atoms to form the products. This rearrangement of atoms is the essence of a chemical reaction.
In the context of the Earth's crust, these reactions can have a significant impact. The Earth's crust is constantly changing due to chemical reactions between minerals. For example, when silicon dioxide \((SiO_2)\) reacts with iron oxide \((Fe_3O_4)\), it forms a new compound, ferrous silicate \((Fe_2SiO_4)\), and oxygen \((O_2)\).
The reactants, \(SiO_2\) and \(Fe_3O_4\), lose and gain atoms to form the products. This rearrangement of atoms is the essence of a chemical reaction.
- Reactants are the starting materials in a chemical reaction.
- Products are the substances formed as a result of the reaction.
Earth's Crust
The Earth's crust is the outermost layer of our planet. It is a thin shell compared to the Earth's other layers but plays a crucial role in the natural environment.
Composed mostly of rocks and minerals, the crust is constantly being shaped by both natural processes and human activity.
Composed mostly of rocks and minerals, the crust is constantly being shaped by both natural processes and human activity.
- The crust contains elements like oxygen, silicon, aluminum, iron, calcium, and more.
- Many chemical reactions, such as oxidation, occur naturally within the crust.
Oxidation and Reduction
Oxidation and reduction are chemical processes that often occur together and are known as redox reactions. In these reactions, there is a transfer of electrons between elements, which alters their oxidation numbers.
Oxidation involves losing electrons, resulting in an increase in oxidation number. For example, when iron \((Fe)\) changes from an oxidation state of 0 to +3, it is oxidized.
Reduction, on the other hand, involves gaining electrons, resulting in a decrease in oxidation number. In redox reactions, one substance is oxidized while another is reduced.
Oxidation involves losing electrons, resulting in an increase in oxidation number. For example, when iron \((Fe)\) changes from an oxidation state of 0 to +3, it is oxidized.
Reduction, on the other hand, involves gaining electrons, resulting in a decrease in oxidation number. In redox reactions, one substance is oxidized while another is reduced.
- The substance that gives away electrons and becomes oxidized is known as the reducing agent.
- The substance that accepts electrons and becomes reduced is known as the oxidizing agent.
Other exercises in this chapter
Problem 103
Balance the following net ionic reactions, and identify which elements are oxidized and which are reduced: a. \(\mathrm{MnO}_{2}(s)+\mathrm{HCl}(a q) \rightarro
View solution Problem 104
Balance the following net ionic reactions, and identify which elements are oxidized and which are reduced: a. \(\mathrm{MnO}_{4}^{-}(a q)+\mathrm{S}^{2-}(a q) \
View solution Problem 106
Determine the oxidation numbers of each of the elements in the following reactions, and identify which of them are oxidized or reduced, if any. a. \(\operatorna
View solution Problem 107
Combine the half-reaction for the reduction of \(\mathrm{O}_{2}\) \(\mathrm{O}_{2}(a q)+4 \mathrm{H}^{+}(a q)+4 \mathrm{e}^{-} \rightarrow 2 \mathrm{H}_{2} \mat
View solution