Problem 105
Question
determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. $$ 6+\frac{1}{x}=\frac{7}{x} $$
Step-by-Step Solution
Verified Answer
The original statement is false. The correct equation would be \(6 + \frac{1}{x} = -6x\).
1Step 1: Isolate the fraction value on the left side
Subtract 6 from both sides of the equation. Which gives you: \(\frac{1}{x}= \frac{7}{x}-6\)
2Step 2: Find the least common denominator(LCD) and combine the fractions
The denominators are 'x' and 'x' which are the same so they can be combined directly. This results in: \(\frac{1}{x}=-6\). The equation simplifies further to: \(x*\frac{1}{x}=-6*x\).
3Step 3: Simplify the equation to show the falsity of the original statement
The equation simplifies to: \(1=-6*x\) . If you solve for \(x\), you still will not get an answer such that the original equation is true. So, the original equation is indeed false.
4Step 4: Change original false equation to make a true equation
Since we know \(6 + \frac{1}{x} = -6x\), we can replace \(\frac{7}{x}\) with \( -6x\) to produce a correct equation. Thus, \(6 + \frac{1}{x} = -6x\) is the correct equation.
Key Concepts
Linear EquationsSolving EquationsEquations with Fractions
Linear Equations
Linear equations are mathematical expressions that create straight lines when graphed. They are fundamental in algebra and are typically set in the form of \(ax + b = c\). Understanding linear equations helps in solving real-world problems, which makes them essential in mathematics.
What distinguishes a linear equation from other types? It is the absence of exponents on variables, meaning every term should be either a constant or a variable raised to the power of one. This is why they stay linear rather than becoming curved like quadratic equations or exponential functions.
What distinguishes a linear equation from other types? It is the absence of exponents on variables, meaning every term should be either a constant or a variable raised to the power of one. This is why they stay linear rather than becoming curved like quadratic equations or exponential functions.
- Linear equations usually involve two operations: addition/subtraction and multiplication/division.
- They are used to find an unknown variable that produces a solution on both sides of the equation.
- The variables are typically denoted as \(x\) or \(y\) and are combined with constants to form equations.
Solving Equations
Solving equations means finding the value of a variable that makes the equation true. It's like reverse engineering the equation to locate the unknown value. This process generally involves a series of steps to isolate the variable on one side.
Here are some steps you might follow when solving an equation:
Sometimes, solving an equation might reveal that no solution exists or that the given equation was based on incorrect premises. That's why it's crucial to verify your final answer.
Here are some steps you might follow when solving an equation:
- Identify and simplify both sides where possible.
- Use inverse operations to eliminate numbers attached to the variable.
- Check your solution by substituting back into the original equation.
Sometimes, solving an equation might reveal that no solution exists or that the given equation was based on incorrect premises. That's why it's crucial to verify your final answer.
Equations with Fractions
Equations with fractions can seem tricky at first, but they're manageable with a few simple steps. Fractions appear when terms in equations have numerators and denominators. Solving these requires carefully managing these fractional components.
Consider the equation \(6+\frac{1}{x}=\frac{7}{x}\) from the original problem. The fractions here involve the denominator \(x\).
Here are strategies to deal with fractions:
Consider the equation \(6+\frac{1}{x}=\frac{7}{x}\) from the original problem. The fractions here involve the denominator \(x\).
Here are strategies to deal with fractions:
- Find a common denominator to deal with fractions on each side easily.
- Multiply through by this common denominator to eliminate fractions.
- Simplify the resulting equation to find the variable's value.
Other exercises in this chapter
Problem 105
Factor Completely. $$6 x^{4}+35 x^{2}-6$$
View solution Problem 105
Simplify by reducing the index of the radical. $$ \sqrt[6]{x^{4}} $$
View solution Problem 105
Perform the indicated computations. Write the answers in scientific notation. If necessary, round the decimal factor in your scientific notation answer to two d
View solution Problem 106
Factor Completely. $$7 x^{4}+34 x^{2}-5$$
View solution