Problem 104
Question
Write each equation in its equivalent exponential form. Then solve for x. $$\log _{64} x=\frac{2}{3}$$
Step-by-Step Solution
Verified Answer
The equivalent exponential form of the equation is \(64^\frac{2}{3} = x\). Solving for x gives \(x = 16\).
1Step 1: Write the logarithmic equation in its exponential form
The logarithmic equation is given by \(\log _{64} x=\frac{2}{3}\). We can convert this into exponential form using the rule mentioned above. So it becomes: \(64^\frac{2}{3} = x\)
2Step 2: Solve for x
Use the rule for exponentiation which states that \(a^\frac{m}{n} = \sqrt[n]{a^m}\). Therefore, \(64^\frac{2}{3} = \sqrt[3]{64^2}\). We know that \(\sqrt[3]{64} = 4\) and \(4^2 = 16\). So, \(x = 16\)
Key Concepts
Logarithmic EquationsSolving for xExponentiation Rule
Logarithmic Equations
Logarithmic equations come in handy when you need to solve equations involving logarithmic expressions. These equations are tied to their inverse operations, exponents. So, when we have a logarithmic equation, such as \( \log_{b}(x) = y \), it reads as "Log base \( b \) of \( x \) is equal to \( y \)." This actually means that \( x \) is \( b \) raised to the power of \( y \).
To transform a logarithmic equation into a more solvable exponential form, you can apply this principle. This transformation can help unveil solutions that may not be apparent in the logarithmic expression alone. Writing \( \log_{64}(x) = \frac{2}{3} \) as an exponential equation gives \( 64^{\frac{2}{3}} = x \).
Using this approach allows you to shift perspectives from the log equation to one where you can directly solve for \( x \) through exponentiation.
To transform a logarithmic equation into a more solvable exponential form, you can apply this principle. This transformation can help unveil solutions that may not be apparent in the logarithmic expression alone. Writing \( \log_{64}(x) = \frac{2}{3} \) as an exponential equation gives \( 64^{\frac{2}{3}} = x \).
Using this approach allows you to shift perspectives from the log equation to one where you can directly solve for \( x \) through exponentiation.
Solving for x
Once a logarithmic equation is converted into its exponential form, your next step is to solve for \( x \). This involves evaluating the number that results from the exponential expression.
Consider the converted equation \( 64^{\frac{2}{3}} = x \). It may initially look complex because of the fractional exponent, but breaking it down into simpler steps helps. Fractional exponents signify roots and powers; specifically, the denominator can be viewed as the root while the numerator indicates the power. Thus, \( 64^{\frac{2}{3}} \) is equivalent to \( (\sqrt[3]{64})^2 \).
By understanding and implementing this method, it becomes more straightforward to isolate and solve for \( x \). Evaluating \( \sqrt[3]{64} \) gives \( 4 \), and squaring it results in \( 16 \). Thus, \( x = 16 \). This step-by-step method can simplify seemingly complicated calculations.
Consider the converted equation \( 64^{\frac{2}{3}} = x \). It may initially look complex because of the fractional exponent, but breaking it down into simpler steps helps. Fractional exponents signify roots and powers; specifically, the denominator can be viewed as the root while the numerator indicates the power. Thus, \( 64^{\frac{2}{3}} \) is equivalent to \( (\sqrt[3]{64})^2 \).
By understanding and implementing this method, it becomes more straightforward to isolate and solve for \( x \). Evaluating \( \sqrt[3]{64} \) gives \( 4 \), and squaring it results in \( 16 \). Thus, \( x = 16 \). This step-by-step method can simplify seemingly complicated calculations.
Exponentiation Rule
The exponentiation rule is a powerful tool in mathematics, particularly when dealing with fractional exponents. It allows the transformation and simplification of mathematical expressions.
Consider \( a^{\frac{m}{n}} \). This expression can be decomposed using the exponentiation rule into \( (\sqrt[n]{a})^m \) or equivalently, \( \sqrt[n]{a^m} \). Both expressions provide clarity and ease in computation. For instance, taking \( 64^{\frac{2}{3}} \), this can be translated into \( \sqrt[3]{64^2} \), or \( (\sqrt[3]{64})^2 \).
Applying this rule, you first determine the cube root of 64, which is 4, and then square the result to get 16. Working through such problems with the exponentiation rule offers a systematic and less daunting way to arrive at solutions, reinforcing the connection between exponents and logarithms.
Consider \( a^{\frac{m}{n}} \). This expression can be decomposed using the exponentiation rule into \( (\sqrt[n]{a})^m \) or equivalently, \( \sqrt[n]{a^m} \). Both expressions provide clarity and ease in computation. For instance, taking \( 64^{\frac{2}{3}} \), this can be translated into \( \sqrt[3]{64^2} \), or \( (\sqrt[3]{64})^2 \).
Applying this rule, you first determine the cube root of 64, which is 4, and then square the result to get 16. Working through such problems with the exponentiation rule offers a systematic and less daunting way to arrive at solutions, reinforcing the connection between exponents and logarithms.
Other exercises in this chapter
Problem 103
The loudness level of a sound can be expressed by comparing the sound's intensity to the intensity of a sound barely audible to the human ear. The formula $$D=1
View solution Problem 103
The formula \(A=37.3 e^{0.0095 t}\) models the population of California, \(A,\) in millions, \(t\) years after 2010 . a. What was the population of California i
View solution Problem 104
The formula $$t=\frac{1}{c}[\ln A-\ln (A-N)]$$ describes the time, \(t,\) in weeks, that it takes to achieve mastery of a portion of a task, where \(A\) is the
View solution Problem 104
The formula \(A=25.1 e^{0.0187 t}\) models the population of Texas, A, in millions, \(t\) years after 2010. a. What was the population of Texas in 2010 ? b. Whe
View solution