Problem 104
Question
The power and type of the lens by which a person can see clearly the distant objects, if a person cannot see objects beyond \(40 \mathrm{~cm}\), are : (a) \(-2.5 \mathrm{D}\) and concave lens (b) \(-2.5 \mathrm{D}\) and convex lens (c) \(-3.5 \mathrm{D}\) and concave lens (d) \(-3.5 \mathrm{D}\) and convex lens
Step-by-Step Solution
Verified Answer
The power is \(-2.5 \mathrm{D}\) and the lens is concave; option (a) is correct.
1Step 1: Understanding the Problem
A person who cannot see objects beyond 40 cm is likely nearsighted, or myopic. We need to determine the power and type of lens required for this person to clearly see distant objects.
2Step 2: Formula for Lens Power
The lens formula is given by \( \, \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \, \). For distant vision correction, the far point \( u \) is at infinity, making the formula \( \, \frac{1}{f} = \frac{1}{v} \, \). Here, \( v \) is -40 cm (negative as it is virtual) and we need the focal length \( f \).
3Step 3: Calculate the Focal Length
Using the modified formula: \( \frac{1}{f} = \frac{1}{-0.4} \). Converting 40 cm to meters gives us \( \frac{1}{-0.4} \approx -2.5 \) m. Therefore, \( f = -0.4 \) m.
4Step 4: Determining Lens Power
The power \( P \) of the lens is calculated as \( P = \frac{1}{f} \) where \( f \) is in meters. So, \( P = \frac{1}{-0.4} = -2.5 \) D.
5Step 5: Identifying Lens Type
Since the power is negative, the lens type must be concave. Concave lenses are used for correcting myopia (nearsightedness).
6Step 6: Select the Correct Option
From the options given, the correct one is (a) \(-2.5 \mathrm{D}\) and concave lens.
Key Concepts
Myopia CorrectionConcave LensFocal Length Determination
Myopia Correction
Myopia, or nearsightedness, is a common vision condition where close objects appear clearly, but distant ones are blurry. This is usually due to the eyeball being too long or the cornea having excessive curvature, which causes light rays to focus in front of the retina instead of on it.
To correct myopia, the use of lenses is essential.
To correct myopia, the use of lenses is essential.
- The lenses help shift the focus back onto the retina.
- This is accomplished by diverging light rays slightly before they enter the eye.
Concave Lens
A concave lens, also known as a diverging lens, is characterized by its inward-curving surfaces. These lenses are thinner at the center than at the edges. The primary function of a concave lens is to diverge light rays passing through it.
In practical applications, concave lenses are used in eyeglasses, camera lenses, and telescopes, supporting functions that require image correction or enlargement.
- This divergence makes the rays appear to originate from a point behind the lens.
- This is why they create a virtual image of objects, allowing viewers to see them as if they were further away.
In practical applications, concave lenses are used in eyeglasses, camera lenses, and telescopes, supporting functions that require image correction or enlargement.
Focal Length Determination
Determining the focal length of a lens is an essential process in understanding how lenses work to correct myopia. The focal length, represented by the letter \( f \), is the distance between the lens and the point where light rays converge or appear to diverge from a single point.
To find the focal length of a corrective lens:
When \( v \) is -40 cm (converted to -0.4 m), the focal length \( f \) becomes -0.4 m, and thus the lens power \( P \) is \( -2.5 \) D.
Understanding these calculations helps patients and opticians determine the required lens specifications for effective vision correction.
To find the focal length of a corrective lens:
- Use the lens formula: \( \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \).
- For distant objects, assume the far point \( u \) to be at infinity. This simplifies the formula to \( \frac{1}{f} = \frac{1}{v} \).
When \( v \) is -40 cm (converted to -0.4 m), the focal length \( f \) becomes -0.4 m, and thus the lens power \( P \) is \( -2.5 \) D.
Understanding these calculations helps patients and opticians determine the required lens specifications for effective vision correction.
Other exercises in this chapter
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