Problem 104
Question
The electrons, identified by quantum numbers \(\mathrm{n}\) and \(l\) (i) \(\mathrm{n}=4 . l=1\) (ii) \(\mathrm{n}=4, l=0\) (iii) \(\mathrm{n}=3, l=2\) (iv) \(\mathrm{n}\) \(=3, l=1\) can be placed in order of increasing energy from the lowest to highest as (a) (iv) \(<(i i)<(i i i)<(i)\) (b) (ii) \(<(\mathrm{iv})<(\mathrm{i})<(\mathrm{iii})\) (c) (i) \(<(\mathrm{iii})<(\mathrm{ii})<\) (iv) (d) (iii) < (i) < (iv) < (ii)
Step-by-Step Solution
Verified Answer
The order is (ii) < (iv) < (i) < (iii), which is option (b).
1Step 1: Understanding Quantum Numbers
The quantum numbers given are \(n\) and \(l\), where \(n\) is the principal quantum number indicating the energy level and \(l\) is the azimuthal quantum number indicating the subshell: \(l=0\) is \(s\), \(l=1\) is \(p\), \(l=2\) is \(d\).
2Step 2: Calculating Energy Level using n and l
To determine the energy order of orbitals, we use the rule: the lower the sum of \(n + l\), the lower the energy. For the same \(n + l\) value, the orbital with the smaller \(n\) has lower energy.
3Step 3: Calculate for Each Orbital
Calculate \(n + l\) for each set of quantum numbers:- (i) \(n = 4\), \(l = 1\): \(n + l = 4 + 1 = 5\)- (ii) \(n = 4\), \(l = 0\): \(n + l = 4 + 0 = 4\)- (iii) \(n = 3\), \(l = 2\): \(n + l = 3 + 2 = 5\)- (iv) \(n = 3\), \(l = 1\): \(n + l = 3 + 1 = 4\)
4Step 4: Ordering by Increasing Energy
From the \(n + l\) values, order the orbitals from lowest to highest energy:1. (ii) \(n + l = 4\)2. (iv) \(n + l = 4\), but \(n = 3\) is lower than \(n = 4\)3. (i) \(n + l = 5\)4. (iii) \(n + l = 5\), but \(n = 3\) is lower than \(n = 4\)
5Step 5: Selecting the Correct Option
Translate the order from Step 4 into the format given by the possible answer choices:
The correct order based on increasing energy is (ii), (iv), (i), (iii), matching option (b).
Key Concepts
Principal Quantum NumberAzimuthal Quantum NumberOrbital Energy Order
Principal Quantum Number
The principal quantum number is symbolized by \( n \). It plays an essential role in the atomic structure by **defining the energy level** of an electron within an atom. The value of \( n \) can be any positive integer, starting from 1. Each increase in \( n \) represents a higher energy level. Consequently, electrons in higher principal quantum levels are found further from the nucleus.
Important characteristics of \( n \):
Important characteristics of \( n \):
- It describes the overall **size and energy** of an electron cloud.
- Higher \( n \) values correspond to higher energy levels, meaning the electron cloud is larger and the electron has more energy.
Azimuthal Quantum Number
The azimuthal quantum number, denoted by \( l \), is crucial for understanding the **shape and type of subshell** an electron occupies within a given energy level. Also termed the orbital (or angular momentum) quantum number, \( l \) can take on integer values ranging from 0 to \( n-1 \). These include:
In the context of electron configuration, the azimuthal quantum number helps determine orbital shape and energy level. As noted in the exercise, when assessing which electron configuration has lower energy, \( l \) combined with \( n \) determines the electron's energy priority.
- \( l = 0 \): s subshell (spherical shape)
- \( l = 1 \): p subshell (dumbbell shape)
- \( l = 2 \): d subshell (more complex shape with four lobes)
In the context of electron configuration, the azimuthal quantum number helps determine orbital shape and energy level. As noted in the exercise, when assessing which electron configuration has lower energy, \( l \) combined with \( n \) determines the electron's energy priority.
Orbital Energy Order
The order of electron energy in orbitals is determined using the **\( n + l \) rule**. This guideline ranks the energy of electrons by evaluating the sum of their respective quantum numbers \( n \) and \( l \).
- The lower the \( n + l \) value, the lower the energy of the electron.
- If two orbitals share the same \( n + l \) value, the one with the smaller \( n \) is lower in energy.
Other exercises in this chapter
Problem 102
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