Problem 104
Question
\(\mathrm{MgSO}_{4}\) on reaction with \(\mathrm{NH}_{4} \mathrm{OH}\) and \(\mathrm{Na}_{2} \mathrm{HPO}_{4}\) forms a white crystalline precipitate. What is its formula? (a) \(\mathrm{Mg}\left(\mathrm{NH}_{4}\right) \mathrm{PO}_{4}\) (b) \(\mathrm{Mg}_{3}\left(\mathrm{PO}_{4}\right)_{2}\) (c) \(\mathrm{MgCl}_{2} \cdot \mathrm{MgSO}_{4}\) (d) \(\mathrm{MgSO}_{4}\)
Step-by-Step Solution
Verified Answer
The white crystalline precipitate formed is \( \mathrm{Mg}\left(\mathrm{NH}_{4}\right) \mathrm{PO}_{4} \).
1Step 1: Understand the Reaction
The problem states that Magnesium sulfate \( \mathrm{MgSO}_{4} \) reacts with Ammonium hydroxide \( \mathrm{NH}_{4} \mathrm{OH} \) and Sodium hydrogen phosphate \( \mathrm{Na}_{2} \mathrm{HPO}_{4} \) to form a white crystalline precipitate. We need to determine the composition of this precipitate.
2Step 2: Identify Possible Precipitates
The options provided list possible compounds that could precipitate from the reaction. We need to analyze each option: 1. \( \mathrm{Mg}\left(\mathrm{NH}_{4}\right) \mathrm{PO}_{4} \) 2. \( \mathrm{Mg}_{3}\left(\mathrm{PO}_{4}\right)_{2} \) 3. \( \mathrm{MgCl}_{2} \cdot \mathrm{MgSO}_{4} \) 4. \( \mathrm{MgSO}_{4} \) again (which would not form since that's a starting reactant).
3Step 3: Predict Reaction Products
\( \mathrm{MgSO}_{4} \) and \( \mathrm{Na}_{2} \mathrm{HPO}_{4} \) can react with \( \mathrm{NH}_{4} \mathrm{OH} \) to produce mixtures containing various possible precipitates. \( \mathrm{Mg}\left(\mathrm{NH}_{4}\right) \mathrm{PO}_{4} \) is one likely candidate, as it uses all components present (Mg, NH4, and PO4).
4Step 4: Verify Stoichiometry
Ensure that the proposed precipitate \( \mathrm{Mg}\left(\mathrm{NH}_{4}\right) \mathrm{PO}_{4} \) balances stoichiometrically with the given starting reagents. Both \( \mathrm{NH}_{4} \) and \( \mathrm{PO}_{4} \) appear once each per \( \mathrm{Mg} \) atom, which matches well with the reagent availability.
5Step 5: Compare with Given Options
Among the options, \( \mathrm{Mg}\left(\mathrm{NH}_{4}\right) \mathrm{PO}_{4} \) correctly reflects the products observed in similar experiments, forming a white crystalline precipitate. The stoichiometry and chemical composition align with practical chemistry.
Key Concepts
Understanding Magnesium SulfateThe Role of Ammonium HydroxideRole of Sodium Hydrogen PhosphateChemical Stoichiometry in Reaction Predictions
Understanding Magnesium Sulfate
Magnesium sulfate is a salt often encountered in chemical experiments. Its chemical formula is \( \mathrm{MgSO}_{4} \).
This compound is well-known for its solubility in water, but, in some reactions, it can lead to the formation of precipitates.
Magnesium sulfate consists of a magnesium ion \( (\mathrm{Mg}^{2+}) \) and a sulfate ion \( (\mathrm{SO}_{4}^{2-}) \).
These ions play crucial roles in determining the kinds of chemical reactions \( \mathrm{MgSO}_{4} \) can participate in, especially precipitation reactions.
Precipitation occurs when ions in solution form a solid. This happens when the product of their concentrations exceeds the solubility product.
This compound is well-known for its solubility in water, but, in some reactions, it can lead to the formation of precipitates.
Magnesium sulfate consists of a magnesium ion \( (\mathrm{Mg}^{2+}) \) and a sulfate ion \( (\mathrm{SO}_{4}^{2-}) \).
These ions play crucial roles in determining the kinds of chemical reactions \( \mathrm{MgSO}_{4} \) can participate in, especially precipitation reactions.
Precipitation occurs when ions in solution form a solid. This happens when the product of their concentrations exceeds the solubility product.
The Role of Ammonium Hydroxide
Ammonium hydroxide \( \mathrm{NH}_{4} \mathrm{OH} \) is an important reagent.
It introduces ammonium ions \( (\mathrm{NH}_{4}^{+}) \) and hydroxide ions \( (\mathrm{OH}^{-}) \) into a solution.
Both ions can participate in a variety of reactions depending on the other chemicals present.
Understanding how \( \mathrm{NH}_{4} \mathrm{OH} \) influences this reaction is key to predicting its products.
It introduces ammonium ions \( (\mathrm{NH}_{4}^{+}) \) and hydroxide ions \( (\mathrm{OH}^{-}) \) into a solution.
Both ions can participate in a variety of reactions depending on the other chemicals present.
- Ammonium ions \( (\mathrm{NH}_{4}^{+}) \) can combine with other anions to form compounds.
- Hydroxide ions can prompt reactions resulting in precipitation, especially with metal cations.
Understanding how \( \mathrm{NH}_{4} \mathrm{OH} \) influences this reaction is key to predicting its products.
Role of Sodium Hydrogen Phosphate
Sodium hydrogen phosphate \( \mathrm{Na}_{2} \mathrm{HPO}_{4} \) is a source of phosphate ions \( (\mathrm{PO}_{4}^{3-}) \).
The introduction of phosphate ions can lead to the formation of new compounds when they interact with available cations in the solution.
The introduction of phosphate ions can lead to the formation of new compounds when they interact with available cations in the solution.
- Phosphate ions readily combine with metal ions, such as magnesium, to form precipitates.
- This transformation is key to the reaction discussed in the exercise, leading to potential compounds like \( \mathrm{Mg}\left(\mathrm{NH}_{4}\right) \mathrm{PO}_{4} \).
Chemical Stoichiometry in Reaction Predictions
Chemical stoichiometry involves the quantitative relationship between reactants and products in a chemical reaction.
It helps predict the amounts and identities of products formed.
Stoichiometry uses balanced chemical equations to ensure conservation of mass and charge.
In the given reaction:
It helps predict the amounts and identities of products formed.
Stoichiometry uses balanced chemical equations to ensure conservation of mass and charge.
In the given reaction:
- Magnesium sulfate, ammonium hydroxide, and sodium hydrogen phosphate mix to potentially form various compounds.
- The proposed precipitate, magnesium ammonium phosphate \( \mathrm{Mg}\left(\mathrm{NH}_{4}\right) \mathrm{PO}_{4} \), aligns well with initial reactants.
- Stoichiometrically, each magnesium is matched with one ammonium and one phosphate, underscoring the likelihood of this product.
Other exercises in this chapter
Problem 101
A metal (A) heating in nitrogen gas gives (B). (B) on treatment with \(\mathrm{H}_{2} \mathrm{O}\) gives a colourless gas which on passing through \(\mathrm{CuS
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Which of the following is correct? (a) sodium reduces \(\mathrm{CO}_{2}\) to carbon (b) in the Castner's process of sodium extraction, \(\mathrm{NaCl}\) is used
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A sodium salt on treatment with \(\mathrm{MgCl}_{2}\) gives white precipitate only on heating. The anion of the sodium salt is (a) \(\mathrm{HCO}_{3}^{-}\) (b)
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The metallic lusture exhibited by sodium is explained by (a) diffusion of sodium ions (b) oscillation of loose electrons (c) excitation of free electrons (d) ex
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