Problem 104
Question
Hydrazine has been employed as a reducing agent for metals. Using standard reduction potentials, predict whether the following metals can be reduced to the metallic state by hydrazine under standard conditions in acidic solution: (a) \(\mathrm{Fe}^{2+}\), (b) \(\mathrm{Sn}^{2+}\), (c) \(\mathrm{Cu}^{2+}\), (d) \(\mathrm{Ag}^{+}\), (e) \(\mathrm{Cr}^{3+}\), (f) \(\mathrm{Co}^{3+}\).
Step-by-Step Solution
Verified Answer
Based on the comparison of standard reduction potentials, hydrazine can only reduce \(\mathrm{Cr}^{3+}\) to its metallic state under standard conditions in an acidic solution. The other metal ions \(\mathrm{Fe}^{2+}\), \(\mathrm{Sn}^{2+}\), \(\mathrm{Cu}^{2+}\), \(\mathrm{Ag}^{+}\), and \(\mathrm{Co}^{3+}\) cannot be reduced by hydrazine under these conditions.
1Step 1: Find the reduction potential of hydrazine
In acidic solution, the reduction half-reaction for hydrazine (\(\mathrm{N}_{2}\mathrm{H}_{4}\)) is given by:
\[\mathrm{N}_{2}\mathrm{H}_{4}(l) + 4\mathrm{H}^{+}(aq) + 4e^{-} \rightarrow 2\mathrm{NH}_{4}^{+}(aq)\]
The standard reduction potential (\(E^{\circ}\)) of hydrazine in this reaction is -0.76 V.
2Step 2: Compare reduction potentials with given metal ions
Now let's compare the standard reduction potentials for each metal ion and determine whether they can be reduced by hydrazine:
(a) \(\mathrm{Fe}^{2+}(aq) + 2e^{-} \rightarrow \mathrm{Fe}(s)\), \(E^{\circ} = -0.44\) V. Since the reduction potential of \(\mathrm{Fe}^{2+}\) is greater than hydrazine, hydrazine cannot reduce it.
(b) \(\mathrm{Sn}^{2+}(aq) + 2e^{-} \rightarrow \mathrm{Sn}(s)\), \(E^{\circ} = -0.14\) V. The reduction potential of \(\mathrm{Sn}^{2+}\) is greater than hydrazine, so hydrazine cannot reduce it.
(c) \(\mathrm{Cu}^{2+}(aq) + 2e^{-} \rightarrow \mathrm{Cu}(s)\), \(E^{\circ} = +0.34\) V. The reduction potential of \(\mathrm{Cu}^{2+}\) is greater than hydrazine, so hydrazine cannot reduce it.
(d) \(\mathrm{Ag}^{+}(aq) + e^{-} \rightarrow \mathrm{Ag}(s)\), \(E^{\circ} = +0.80\) V. The reduction potential of \(\mathrm{Ag}^{+}\) is greater than hydrazine, so hydrazine cannot reduce it.
(e) \(\mathrm{Cr}^{3+}(aq) + 3e^{-} \rightarrow \mathrm{Cr}(s)\), \(E^{\circ} = -0.74\) V. The reduction potential of \(\mathrm{Cr}^{3+}\) is less than hydrazine, so hydrazine can reduce it.
(f) \(\mathrm{Co}^{3+}(aq) + 3e^{-} \rightarrow \mathrm{Co}(s)\), \(E^{\circ} = -0.28\) V. The reduction potential of \(\mathrm{Co}^{3+}\) is greater than hydrazine, so hydrazine cannot reduce it.
3Step 3: Compile the conclusions
By comparing the standard reduction potentials, we can conclude the following:
(a) \(\mathrm{Fe}^{2+}\) cannot be reduced by hydrazine.
(b) \(\mathrm{Sn}^{2+}\) cannot be reduced by hydrazine.
(c) \(\mathrm{Cu}^{2+}\) cannot be reduced by hydrazine.
(d) \(\mathrm{Ag}^{+}\) cannot be reduced by hydrazine.
(e) \(\mathrm{Cr}^{3+}\) can be reduced by hydrazine.
(f) \(\mathrm{Co}^{3+}\) cannot be reduced by hydrazine.
Key Concepts
Oxidation-ReductionMetal Ion ReductionElectrochemistry
Oxidation-Reduction
Oxidation-reduction, often referred to as redox, involves chemical reactions where electrons are transferred between substances. This process consists of two key parts: oxidation, where a substance loses electrons, and reduction, where a substance gains electrons.
In oxidation-reduction reactions, each element has a specific oxidation state. When an element undergoes oxidation, it will increase its oxidation state by losing electrons. Conversely, reduction will lower the oxidation state as the element gains electrons.
In oxidation-reduction reactions, each element has a specific oxidation state. When an element undergoes oxidation, it will increase its oxidation state by losing electrons. Conversely, reduction will lower the oxidation state as the element gains electrons.
- When hydrazine (\(\mathrm{N}_{2}\mathrm{H}_{4}\)) interacts with metal ions, it donates its electrons to reduce them.
- The efficiency of a reducing agent like hydrazine is decided by its standard reduction potential. A negative potential means it can donate electrons to metals with more positive potentials.
- Knowing which metals can be reduced by hydrazine is determined by comparing their respective standard reduction potentials.
Metal Ion Reduction
The process of metal ion reduction is a fundamental concept in chemistry, often involved in obtaining pure metals from their ionic form. It occurs when metal ions gain electrons and transform into solid metals.
Metal ion reduction is significantly influenced by the reduction potential. Metals with a more positive standard reduction potential are more easily reduced.
Metal ion reduction is significantly influenced by the reduction potential. Metals with a more positive standard reduction potential are more easily reduced.
- Reduction potentials are measured in volts (V) which helps predict their likelihood to gain electrons.
- Metals with a higher reduction potential compared to the reducing agent are less likely to be reduced by that agent.
- In our case, hydrazine’s potential at -0.76 V has to be lower than that of the metal to successfully reduce it.
Electrochemistry
Electrochemistry is the branch of chemistry that examines chemical reactions which take place at the interface of an electrode, typically involving the movement of electrons.
Central to electrochemistry are concepts like electrodes, electrochemical cells, and importantly, the standard electrode, or reduction potential. This potential indicates how likely a substance is to be reduced.
Central to electrochemistry are concepts like electrodes, electrochemical cells, and importantly, the standard electrode, or reduction potential. This potential indicates how likely a substance is to be reduced.
- Standard reduction potentials provide groundwork for predicting reactions in an electrochemical cell.
- Unlike typical reactions, electrochemical cells harness the energy from redox reactions to do electrical work.
- To determine whether hydrazine can reduce a metal ion, one must evaluate the cell potential. If it’s positive, reduction of the metal ion is possible in the electrochemical environment.
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