Problem 104
Question
Explain how to add rational expressions that have different denominators. Use \(\frac{3}{x+5}+\frac{7}{x+2}\) in your explanation.
Step-by-Step Solution
Verified Answer
The addition of the given rational expressions is \(\frac{10x + 41}{(x + 5)(x + 2)}\)
1Step 1: Identifying the Common Denominator
The common denominator is found by multiplying the two denominators together. Here, it would be \((x+5)(x+2)\).
2Step 2: Modifying Rational Expressions
To get fractions with the same denominator, each fraction is multiplied by an appropriate form of 1 using the missing parts of the common denominator. For the first fraction, we multiply by \(\frac{(x+2)}{(x+2)}\) and the second fraction is multiplied by \(\frac{(x+5)}{(x+5)}\). The expressions become: \(\frac{3(x + 2)}{n(x + 5)(x + 2)} + \frac{7(x+5)}{(x + 5)(x + 2)}\).
3Step 3: Adding the Rational Expressions
Now that both fractions have the same denominator, they can be added together as follows \(\frac{3(x + 2)+ 7(x+5)}{(x + 5)(x + 2)}\), this simplifies to \(\frac{3x + 6 + 7x + 35}{(x + 5)(x + 2)}\).
Other exercises in this chapter
Problem 103
Explain how to find the least common denominator for denominators of \(x^{2}-100\) and \(x^{2}-20 x+100\)
View solution Problem 104
perform the indicated operation. Where possible, reduce the answer to its lowest terms. $$\text { Simplify: } \frac{(y+2) y-2 \cdot 4}{4 y(y+4)}$$
View solution Problem 105
Determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. $$\frac{3 x+7}{3 x+10}=\
View solution Problem 105
Then rewrite the right side of the equation to correct the error that now exists. $$\frac{1}{x}+\frac{2}{5}=\frac{3}{x+5}$$
View solution