Problem 104
Question
(a) Write the reactions for the discharge and charge of a nickel-cadmium (nicad) rechargeable hattery. (b) Given the following reduction potentials, calculate the standard emf of the cell: $$ \begin{array}{r} \mathrm{Cd}(\mathrm{OH})_{2}(s)+2 \mathrm{e}^{-} \longrightarrow \mathrm{Cd}(s)+2 \mathrm{OH}^{-}(a q) \\ \qquad \begin{aligned} E_{\mathrm{red}}^{\circ} &=-0.76 \mathrm{~V} \end{aligned} \\ \mathrm{NiO}(\mathrm{OH})(s)+\mathrm{H}_{2} \mathrm{O}(l)+\mathrm{e}^{-} \longrightarrow \mathrm{Ni}(\mathrm{OH})_{2}(s)+\mathrm{OH}^{-}(a q) \\ E_{\mathrm{red}}^{\circ}=+0.49 \mathrm{~V} \end{array} $$ (c) A typical nicad voltaic cell generates an emf of \(+1.30 \mathrm{~V}\). Why is there a difference between this value and the one you calculated in part (b)? (d) Calculate the equilibrium constant for the overall nicad reaction based on this typical emf value.
Step-by-Step Solution
VerifiedKey Concepts
Nickel-Cadmium Battery
These batteries are popular due to their capability to deliver a consistent voltage until they are nearly depleted. They are also capable of handling high discharge rates and enduring many charge-discharge cycles, which makes them ideal for use in portable electronic devices and tools. However, they must be stored properly to avoid the 'memory effect', where the battery loses its maximum energy capacity when repeatedly recharged after being only partially discharged.
Standard Reduction Potentials
In the context of a nickel-cadmium battery, each half-reaction has its own standard reduction potential. For cadmium, the reduction potential is -0.76 V, which makes it more likely to lose electrons (oxidize) than something with a more positive potential. For nickel (III) hydroxide, the standard potential is +0.49 V, indicating it is more likely to accept electrons (reduce) compared to cadmium.
To calculate the standard cell potential, you use the formula:
\[ E^{\circ}_{\text{cell}} = E^{\circ}_{\text{cathode}} - E^{\circ}_{\text{anode}} \]
This gives you the EMF under standard conditions, providing insight into the driving forces behind the cell's reactions.
Equilibrium Constant
In electrochemical cells, \( K \) can be related to the cell's potential using the Nernst equation. At standard conditions, any change in the EMF of the cell affects the value of \( K \). In the case of the nickel-cadmium battery with an EMF of 1.30 V, this indicates a strong propensity for the forward reaction, thus a large \( K \) value. This is why the nicad battery is so efficient at producing energy - it shows a strong preference for the formation of products.
Nernst Equation
The equation is given by:
\[ E = E^{\circ} - \frac{RT}{nF} \ln Q \]
where:
- \( E \) is the cell potential under specific conditions.
- \( E^{\circ} \) is the standard cell potential.
- \( R \) is the ideal gas constant.
- \( T \) is the temperature in Kelvin.
- \( n \) is the number of moles of electrons exchanged.
- \( F \) is Faraday's constant.
- \( Q \) is the reaction quotient.