Problem 103
Question
What pressure is exerted by a gas mixture containing \(2.00 \mathrm{g}\) of \(\mathrm{H}_{2}\) and \(7.00 \mathrm{g}\) of \(\mathrm{N}_{2}\) at \(273^{\circ} \mathrm{C}\) in a \(10.0 \mathrm{L}\) container? What is the contribution of \(\mathrm{N}_{2}\) to the total pressure?
Step-by-Step Solution
Verified Answer
Based on the given information, calculate the total pressure exerted by a gas mixture of Hydrogen (H2) and Nitrogen (N2) and the individual pressure contribution of Nitrogen (N2).
Mass of Hydrogen (H2): 2.00 g
Mass of Nitrogen (N2): 7.00 g
Temperature: 273 °C
Volume of the container: 10.0 L
Provide the answer in atmospheres (atm).
1Step 1: Calculate moles of given gases
First, we need to determine the moles of each gas present in the gas mixture.
We are given:
Mass of H2 = 2.00 g
Molar mass of H2 = 2 g/mol
Moles of H2 = (Mass of H2) / (Molar mass of H2)
n(H2) = 2.00 g / 2 g/mol = 1.00 mol
Now, for N2:
Mass of N2 = 7.00 g
Molar mass of N2 = 28 g/mol
Moles of N2 = (Mass of N2) / (Molar mass of N2)
n(N2) = 7.00 g / 28 g/mol = 0.25 mol
2Step 2: Calculate the Individual pressure of H2 and N2 using the ideal gas law
Now, we have to find the pressure exerted by each gas using the ideal gas law:
PV = nRT
R (Gas constant) = 0.0821 L atm/(mol K)
Given:
Volume (V) = 10.0 L
Temperature = 273 °C + 273.15 = 546.15 K
First, we will find out the pressure exerted by H2.
P(H2) V = n(H2) R T
P(H2) = n(H2) R T / V
P(H2) = (1.00 mol)(0.0821 L atm/mol K)(546.15 K) / (10.0 L)
P(H2) ≈ 4.49 atm
Now, the pressure exerted by N2.
P(N2) V = n(N2) R T
P(N2) = n(N2) R T / V
P(N2) = (0.25 mol)(0.0821 L atm/mol K)(546.15 K) / (10.0 L)
P(N2) ≈ 1.12 atm
3Step 3: Calculate the total pressure
The total pressure exerted by the gas mixture is the sum of the pressures of H2 and N2.
P(total) = P(H2) + P(N2)
P(total) = 4.49 atm + 1.12 atm
P(total) ≈ 5.61 atm
So, the total pressure exerted by the gas mixture is approximately 5.61 atm. The contribution of N2 to the total pressure is 1.12 atm.
Key Concepts
Gas Pressure CalculationsMole CalculationGas Mixtures
Gas Pressure Calculations
When dealing with gas pressure, particularly in a mixture, we rely on the ideal gas law: \( PV = nRT \). This formula helps us determine the pressure that a gas or a mixture of gases exerts within a container. In this equation:
- \( P \) is the pressure of the gas
- \( V \) is the volume the gas occupies
- \( n \) represents the moles of the gas present
- \( R \) is the ideal gas constant, often 0.0821 L atm/mol K
- \( T \) is the temperature in Kelvin
Mole Calculation
The concept of moles is fundamental when we talk about gas reactions and calculations. The mole is a unit that measures the amount of a substance. To find the number of moles of a gas, we use the formula:
- \( \, \text{Moles} = \frac{\text{Mass of the substance}}{\text{Molar mass of the substance}} \, \)
Gas Mixtures
Gas mixtures occur when different gases share a common container, contributing to the overall behavior of the gas system. A key property of gas mixtures is that each gas behaves independently, following the ideal gas law, and contributes to the total pressure through its partial pressure.
- Partial Pressure: This is the pressure exerted by a single gas in a mixture. It can be calculated using the ideal gas law for each gas separately.
- Total Pressure: The sum of all partial pressures of gases in the mixture. In our example, hydrogen and nitrogen each contribute separately to the total pressure, which is determined by summing their individual pressures.
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