Problem 103
Question
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} y=-4 x \\ 4 x+y=1 \end{array}\right. $$
Step-by-Step Solution
Verified Answer
The system of equations has no solution.
1Step 1: Identify the Equations
The system of equations given is:1) \( y = -4x \)2) \( 4x + y = 1 \)
2Step 2: Substitute Equation
Substitute the expression for \( y \) from the first equation into the second equation. This gives:\( 4x + (-4x) = 1 \).
3Step 3: Simplify the Equation
Simplify the equation from Step 2:\( 4x - 4x = 0 \), hence the equation simplifies to:\( 0 = 1 \).
4Step 4: Solve for x
Since \( 0 = 1 \) is not a true statement, this indicates that there is no solution for \( x \) and subsequently for \( y \) in the system of equations.
Key Concepts
substitution methodno solutioninconsistent equations
substitution method
The substitution method is one way to solve systems of equations. It works by solving one of the equations for one variable and then substituting this expression into the other equation. This substitution helps us simplify the system to one equation with one variable, making it easier to solve.
For example, in the given system:
\[ y = -4x \] and \[ 4x + y = 1 \],
we can solve the first equation for \( y \). We already have: \[ y = -4x \],
Next, we substitute \( -4x \) for \( y \) in the second equation:
\[ 4x + (-4x) = 1 \]
This simplifies the system to a single equation that is easier to solve.
For example, in the given system:
\[ y = -4x \] and \[ 4x + y = 1 \],
we can solve the first equation for \( y \). We already have: \[ y = -4x \],
Next, we substitute \( -4x \) for \( y \) in the second equation:
\[ 4x + (-4x) = 1 \]
This simplifies the system to a single equation that is easier to solve.
no solution
Sometimes, you might encounter a system of equations that has no solution. This happens when the equations are contradictory. In our example, after substituting and simplifying, we get: \[ 4x - 4x = 1 \],
which simplifies to \[ 0 = 1 \]. This is not true, so there is no solution.
No matter what \( x \) you choose, you can't make \( 0 = 1 \) true. This indicates the system of equations does not have a solution that works for both equations at the same time.
which simplifies to \[ 0 = 1 \]. This is not true, so there is no solution.
No matter what \( x \) you choose, you can't make \( 0 = 1 \) true. This indicates the system of equations does not have a solution that works for both equations at the same time.
inconsistent equations
When a system of equations has no solution, it is called inconsistent. Inconsistent equations mean that the lines represented by the equations do not intersect. Instead, they are parallel.
For the given system: \[ y = -4x \] and \[ 4x + y = 1 \],
if we simplify the second equation using the substitution method, we end up with: \[ 0 = 1 \]. This contradiction shows the lines are parallel and never meet.
Therefore, the system is inconsistent and there is no point that satisfies both equations. Always look out for these contradictions when solving systems of equations.
For the given system: \[ y = -4x \] and \[ 4x + y = 1 \],
if we simplify the second equation using the substitution method, we end up with: \[ 0 = 1 \]. This contradiction shows the lines are parallel and never meet.
Therefore, the system is inconsistent and there is no point that satisfies both equations. Always look out for these contradictions when solving systems of equations.
Other exercises in this chapter
Problem 101
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} 2 x+16 y=8 \\ -x-8 y=-4 \end{array}\right. $$
View solution Problem 102
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} 15 x+4 y=6 \\ -30 x-8 y=-12 \end{array}\right. $$
View solution Problem 104
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} y=-\frac{1}{4} x \\ x+4 y=8 \end{array}\right. $$
View solution Problem 105
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} y=\frac{7}{8} x+4 \\ -7 x+8 y=6 \end{array}\right. $$
View solution