Problem 103
Question
determine whether each statement “makes sense” or “does not make sense” and explain your reasoning. When I know that an equation's graph is a straight line, I don't need to plot more than two points, although I sometimes plot three just to check that the points line up.
Step-by-Step Solution
Verified Answer
The statement makes sense because in mathematics, a straight line is uniquely defined by any two points. Therefore, when graphing a linear equation, it's technically necessary to plot only two points. Plotting a third point is a measure to confirm the straight-line alignment of the points, acting as a check against calculation errors.
1Step 1: Understand What Linearity Means
In mathematics, a linear equation is one that, when graphed, forms a straight line. This means that there is a consistent relationship between variables - any change in one variable leads to a proportional change in the other. An important property of straight lines is that any two points uniquely define a line.
2Step 2: Evaluate the Statement
With the understanding of linearity, the statement 'When I know that an equation's graph is a straight line, I don't need to plot more than two points, although I sometimes plot three just to check that the points line up.' can be evaluated. The statement is indeed true. As mentioned, any two points uniquely define a line. This means that to graph a linear equation - a straight line, only two points are technically necessary to establish the line. However, marking a third point can indeed be a good measure to confirm that the points align and indeed form a straight line - this is essentially a check for errors in calculations.
3Step 3: Final Evaluation
Thus, the statement 'When I know that an equation's graph is a straight line, I don't need to plot more than two points, although I sometimes plot three just to check that the points line up.' makes sense since it is aligned with the mathematical concepts of linearity and graphing linear equations.
Key Concepts
Graphing Linear EquationsPoints Defining a LineConsistency of Linearity
Graphing Linear Equations
Graphing linear equations involves plotting points on a coordinate plane that are solutions to the equation. A linear equation is usually written in the form \(y = mx + b\), where \(m\) represents the slope and \(b\) is the y-intercept. This form makes it straightforward to graph because:
- The y-intercept \(b\) tells us where the line crosses the y-axis.
- The slope \(m\) indicates the steepness and direction of the line.
Points Defining a Line
In geometry, any two points are enough to define a straight line. This is because a line is the shortest distance between two distinct points. To graph a linear equation, all you need are two points that fit the equation's criteria. Here’s how you can select these points:
- Choose a value for \(x\) and solve the equation to find the corresponding \(y\).
- Repeat with a different \(x\) value to find another point.
Consistency of Linearity
The concept of checking the consistency of linearity involves verifying that the graph of a linear equation remains true to its definition as a straight line. While only two points are mathematically required to establish a line, adding a third can serve as an error check:
- Plot a third point based on another \(x\) value.
- This point should lie on the same line formed by the initial two points.
Other exercises in this chapter
Problem 102
Explain how to graph an cquation in two variables in the rectangular coordinate system.
View solution Problem 103
Will help you prepare for the material covered in the next section. In each exercise, evaluate $$\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$$ for the given ordered pairs \
View solution Problem 104
determine whether each statement “makes sense” or “does not make sense” and explain your reasoning. The graph that I'm looking at is U-shaped, so its equation c
View solution Problem 105
determine whether each statement “makes sense” or “does not make sense” and explain your reasoning. I'm working with a linear equation in two variables and foun
View solution