Problem 102
Question
The number of ordered triplets of positive integers which are solutions of the equation \(x+y+z=100\) is (A) 5081 (B) 6005 (C) 4851 (D) None of these
Step-by-Step Solution
Verified Answer
4851; the answer is (C).
1Step 1: Understanding the Equation
We are given the equation \(x + y + z = 100\) and we need to find the number of ordered triplets of positive integers \((x, y, z)\) that satisfy this equation. Each variable must take a positive integer value.
2Step 2: Reformulation Using Non-Negative Integers
The task requires positive integers, so we can rewrite \(x = x' + 1, y = y' + 1, z = z' + 1\) where \(x', y', z'\) are non-negative integers. Substituting in the equation, we get \(x' + 1 + y' + 1 + z' + 1 = 100\). This simplifies to \(x' + y' + z' = 97\). Now, we solve for non-negative integer solutions to this new equation.
3Step 3: Applying the Stars and Bars Theorem
To count non-negative solutions of \(x' + y' + z' = 97\), we can apply the "Stars and Bars" theorem. According to this theorem, the number of solutions in non-negative integers is given by the formula \(\binom{n+k-1}{k-1}\), where \(n\) is the total to be obtained (97 in this case) and \(k\) is the number of variables (3 here).
4Step 4: Calculating the Number of Solutions
Plugging values into the formula, we have: \(\binom{97 + 3 - 1}{3 - 1} = \binom{99}{2}\). To calculate \(\binom{99}{2}\), compute: \[ \binom{99}{2} = \frac{99 \times 98}{2} = 4851 \]
5Step 5: Identifying the Correct Answer
The computed number of ordered triplets is 4851. Comparing this to the options given, the answer is (C) 4851.
Key Concepts
CombinatoricsOrdered TripletsNon-negative Solutions
Combinatorics
Combinatorics is a branch of mathematics that deals with counting, arranging, and finding patterns or structures in sets. It plays a crucial role in solving problems where we need to find the number of ways something can happen. This includes determining combinations, permutations, and understanding how systems can be organized.
In our exercise, combinatorics is used to find the number of solutions to the equation \(x + y + z = 100\). The task involves counting different ways to distribute a total of 100 units among three variables—\(x, y,\) and \(z\).
Combinatorics is versatile and is commonly applied to problems in probability, statistics, computer science, and many other fields. Understanding the basic tools in combinatorics, such as the stars and bars theorem, is essential for solving problems involving non-negative solutions and ordered arrangements.
In our exercise, combinatorics is used to find the number of solutions to the equation \(x + y + z = 100\). The task involves counting different ways to distribute a total of 100 units among three variables—\(x, y,\) and \(z\).
Combinatorics is versatile and is commonly applied to problems in probability, statistics, computer science, and many other fields. Understanding the basic tools in combinatorics, such as the stars and bars theorem, is essential for solving problems involving non-negative solutions and ordered arrangements.
Ordered Triplets
An ordered triplet, in mathematics, is simply a group of three numbers or variables arranged in a specific sequence. These are denoted as \((x, y, z)\) where each position in the triplet is important and switching the order produces a different triplet.
Ordered triplets are crucial in problems where the arrangement matters, as different orderings represent different solutions. For example, the triplet \((3, 4, 5)\) is different from \((5, 4, 3)\).
In the exercise given, finding ordered triplets of positive integers means calculating all possible sequences of values for \(x\), \(y\), and \(z\) that add up to a certain number, while each value remains a positive integer.
Ordered triplets are crucial in problems where the arrangement matters, as different orderings represent different solutions. For example, the triplet \((3, 4, 5)\) is different from \((5, 4, 3)\).
In the exercise given, finding ordered triplets of positive integers means calculating all possible sequences of values for \(x\), \(y\), and \(z\) that add up to a certain number, while each value remains a positive integer.
- The importance of ordered triplets is highlighted when calculating permutations and combinations where order impacts the outcome.
- In our solution, the focus was on the arrangement of values satisfying the equation while maintaining their order.
Non-negative Solutions
Non-negative solutions refer to sets of numbers that all are either zero or positive. Unlike positive solutions, non-negative solutions allow for zero as a valid entry.
For example, if solving the equation \(a + b = 5\) for positive integer solutions, both \(a\) and \(b\) must be greater than zero. However, for non-negative solutions, \(a\) or \(b\) could be zero.
In the provided problem, we transformed the original equation into a form allowing us to use non-negative numbers: \(x' + y' + z' = 97\). This transition made it suitable to apply the stars and bars theorem, a combinatorial method that facilitates finding these solutions.
For example, if solving the equation \(a + b = 5\) for positive integer solutions, both \(a\) and \(b\) must be greater than zero. However, for non-negative solutions, \(a\) or \(b\) could be zero.
In the provided problem, we transformed the original equation into a form allowing us to use non-negative numbers: \(x' + y' + z' = 97\). This transition made it suitable to apply the stars and bars theorem, a combinatorial method that facilitates finding these solutions.
- Non-negative solutions are significant in combinatorics owing to their flexibility in allocation while maintaining the total sum at a constant value.
- The process involved reformulating the original variables to facilitate this approach.
Other exercises in this chapter
Problem 100
The number of non-negative integral solutions of \(x_{1}+\) \(x_{2}+x_{3}+4 x_{4}=20\) is (A) 436 (B) 536 (C) 602 (D) None of these
View solution Problem 101
The product of \(r\) consecutive positive integers is divisible by (A) \(r !\) (B) \((r-1) !\) (C) \((r+1) !\) (D) None of these
View solution Problem 103
The number of words that can be formed, with the letters of the work 'Pataliputra' without changing the relative order of the vowels and consonants, is (A) 3600
View solution Problem 104
On a new year day every student of a class sends a card to every other student. The postman delivers 600 cards. The number of students in the class are (A) 42 (
View solution