Problem 102
Question
The cancer drug cisplatin contains \(65.0 \%\) platinum. If you have \(1.53 \mathrm{~g}\) of the compound, calculate how many grams of platinum the sample contains.
Step-by-Step Solution
Verified Answer
The sample contains 0.9945 grams of platinum.
1Step 1: Understanding the Problem
We need to determine how many grams of platinum are present in a 1.53 g sample of a compound that contains 65% platinum.
2Step 2: Convert Percentage to Decimal Form
Since the percentage of platinum in the compound is given as 65%, we convert this percentage to decimal form by dividing by 100. So, in decimal form, it is \(0.65\).
3Step 3: Calculate the Mass of Platinum
To find the mass of platinum in the sample, we multiply the total mass of the compound by the decimal form of the percentage of platinum. \[ \text{Mass of platinum} = 0.65 \times 1.53 \] Perform the multiplication to find the result.
4Step 4: Compute the Result
Performing the multiplication from Step 3 gives: \[ 0.65 \times 1.53 = 0.9945 \] Therefore, the mass of platinum in the sample is \(0.9945\) grams.
Key Concepts
Understanding Percentage CompositionPerforming Mass CalculationSolving Chemistry Problems
Understanding Percentage Composition
Percentage composition is a crucial concept in chemistry, especially when analyzing compounds. It tells us what fraction of a compound is made up of a specific element by mass. For example, in the exercise, cisplatin is stated to be 65% platinum by mass. This means that in every 100 grams of cisplatin, 65 grams are pure platinum.
Understanding this helps us perform various calculations related to chemical quantities. To express percentage composition mathematically, we divide the mass of the element by the total mass of the compound and multiply by 100 to get a percentage. To use it in calculations like our exercise, it’s often necessary to convert this percentage to a decimal by dividing it by 100, so it integrates easily into mathematical operations.
Understanding this helps us perform various calculations related to chemical quantities. To express percentage composition mathematically, we divide the mass of the element by the total mass of the compound and multiply by 100 to get a percentage. To use it in calculations like our exercise, it’s often necessary to convert this percentage to a decimal by dividing it by 100, so it integrates easily into mathematical operations.
Performing Mass Calculation
Mass calculation involves using known quantities and relationships to determine unknown masses within a compound. In the exercise, we know the total mass of the compound (1.53 g) and the percentage composition of platinum (65%). Our goal is to find the mass of platinum within that sample.
To do this, we first convert our percentage of platinum to a decimal which is 0.65. Next, we use this decimal to find the mass of platinum by multiplying it by the total mass of the compound. Essentially, the formula looks like this:
To do this, we first convert our percentage of platinum to a decimal which is 0.65. Next, we use this decimal to find the mass of platinum by multiplying it by the total mass of the compound. Essentially, the formula looks like this:
- \( \text{Mass of platinum} = \text{Decimal form of percentage} \times \text{Total mass of compound} \)
- \( \text{Mass of platinum} = 0.65 \times 1.53 \)
Solving Chemistry Problems
Chemistry problem-solving often involves multiple steps that closely follow logical sequences just like mathematical puzzles. Here's how to efficiently tackle problems like these:
- First, ensure you understand the problem by identifying known and unknown quantities. In the exercise, the knowns are the total mass of cisplatin and its percentage composition of platinum.
- Next, use simpler operations for conversion and calculation, such as turning percentages into decimals.
- Then, utilize fundamental formulas for computation. In this case, multiplying the total mass by the decimal value of the percentage gives the mass of the specific element.
Other exercises in this chapter
Problem 100
The alum used in cooking is potassium aluminum sulfate hydrate, \(\mathrm{KAl}\left(\mathrm{SO}_{4}\right)_{2} \cdot x \mathrm{H}_{2} \mathrm{O} .\) To find the
View solution Problem 101
The density of a solution of sulfuric acid is \(1.285 \mathrm{~g} / \mathrm{cm}^{3}\), and it is \(38.08 \%\) acid by mass. Calculate the volume of the acid sol
View solution Problem 103
Ethyl alcohol, \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\), has a density of \(0.789 \mathrm{~g} / \mathrm{mL}\) at \(25^{\circ} \mathrm{C}\). Water weighs \(
View solution Problem 105
The fluoridation of city water supplies has been practiced in the United States for several decades because there is scientific evidence that fluoride prevents
View solution