Problem 102
Question
Nylon-6 is a polyamide formed by polymerizing \(\mathrm{H}_{2} \mathrm{NCH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CO}_{2} \mathrm{H} .\) Write an equation for this reaction.
Step-by-Step Solution
Verified Answer
The equation for polymerizing Nylon-6 is: \[ n \left( \mathrm{H}_2\mathrm{NCH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CO}_2 \mathrm{H} \right) \rightarrow \left( -\mathrm{HN} \left( \mathrm{CH}_2 \right)_5 \mathrm{C=O}- \right)_n + n \cdot \mathrm{H}_2\mathrm{O} \]
1Step 1: Understanding Polymerization
Nylon-6 is a type of polymer known as a polyamide. It is created through a polymerization process where monomers link together to form a long chain. The monomer for Nylon-6 is Caprolactam expressed as \( \mathrm{H}_{2} \mathrm{NCH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CO}_{2} \mathrm{H} \), which can open to form a repeating unit in the polymer chain.
2Step 2: Identifying the Repeating Unit
When polymerization occurs, the repeating unit in Nylon-6 consists of the monomer minus a molecule of water formed during the polymerization. The caprolactam opens up and the amine group (\( \mathrm{NH}_2 \)) from one monomer reacts with the carboxylic group (\( \mathrm{COOH} \)) of the adjacent monomer, releasing water and linking the monomers via an amide bond.
3Step 3: Writing the Polymerization Equation
The polymerization reaction can be represented with the chemical equation: \[ n \left( \mathrm{H}_2\mathrm{NCH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CO}_2 \mathrm{H} \right) \rightarrow \left( -\mathrm{HN} \left( \mathrm{CH}_2 \right)_5 \mathrm{C=O}- \right)_n + n \cdot \mathrm{H}_2\mathrm{O} \]This shows the monomer units (caprolactam) polymerizing to form Nylon-6, with the concurrent production of water molecules.
Key Concepts
Polyamide FormationCaprolactamAmide Bond Formation
Polyamide Formation
Polyamide formation is a fascinating process that results in the creation of polymers such as Nylon-6. In this process, monomers, which are small and similar units, join together to form a long, repeating chain known as a polymer. Nylon-6 is an example of a polyamide, which means it is made by linking together monomers through amide bonds. These bonds are integral for creating the structural integrity and strength of the polymer.
- Polyamides are typically formed via a polymerization reaction.
- In the case of Nylon-6, the polymerization is a step-growth process.
- The monomer units used in this process have both amine and carboxyl groups.
Caprolactam
Caprolactam is the monomer used in the production of Nylon-6. It is a cyclic compound with a chemical formula of \( \mathrm{C}_6 ext{H}_{11} ext{NO} \). When heated, Caprolactam undergoes a ring-opening polymerization. This involves opening up the cyclic structure to allow the reactive ends to join with other monomers.
- Caprolactam consists of six carbon atoms, a nitrogen atom, and an oxygen atom.
- It is known for its ability to react and form long chains easily, which is essential in polymer formation.
- The ring-opening polymerization initiates when heat is applied, providing enough energy to break the rings open.
Amide Bond Formation
Amide bond formation is one of the key chemical processes that enables the creation of polyamides, such as Nylon-6. An amide bond, also known as a peptide bond, occurs between a nitrogen atom and a carbon atom that carries a double-bonded oxygen (the carbonyl group). This type of bond connects the monomer units into a polymer.
- To create an amide bond, a reaction between an amine group (\( \text{NH}_2 \)) and a carboxylic acid group (\( \text{COOH} \)) is required.
- During the reaction, a water molecule is released as a by-product, a process known as condensation polymerization.
- This water release is a key feature of amide bond formation as it helps drive the reaction forward.
Other exercises in this chapter
Problem 99
The product of an addition reaction of an alkene is often predicted by Markovnikov's rule. (a) Draw the structure of the product of adding HBr to propene, and g
View solution Problem 100
There are three ethers with the formula \(\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}.\) Draw their structures.
View solution Problem 105
You have a liquid that is either cyclohexene or benzene. When the liquid is exposed to dark-red bromine vapor, the vapor is immediately decolorized. What is the
View solution Problem 106
Hydrolysis of an unknown ester of butanoic acid, \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CO}_{2} \mathrm{R},\) produces an alcohol \(\mathrm{A
View solution