Problem 102
Question
For the following problems, perform the multiplications and combine any like terms. $$ 3 a^{2}\left(2 a^{3}-10 a^{2}-4 a+9\right) $$
Step-by-Step Solution
Verified Answer
Answer: The simplified expression is \(6a^5 - 30a^4 - 12a^3 + 27a^2\).
1Step 1: Distributive Property
Apply the distributive property to multiply \(3a^2\) by each term inside the parentheses.
$$
3a^2(2a^3) - 3a^2(10a^2) - 3a^2(4a) + 3a^2(9)
$$
2Step 2: Perform Multiplication
Multiply the coefficients and add the exponents of like bases in each term.
$$
6a^5 - 30a^4 - 12a^3 + 27a^2
$$
3Step 3: Finished Expression
Since there are no like terms to combine, we have our final simplified expression:
$$
6a^5 - 30a^4 - 12a^3 + 27a^2
$$
Key Concepts
Distributive PropertyCombining Like TermsMultiplication of PolynomialsExponents in Algebra
Distributive Property
Understanding the distributive property is essential when dealing with algebra. It allows you to multiply a single term by a group of terms within parentheses. The principle behind it is straightforward: you distribute the multiplication of the single term to each term inside the parentheses individually.
Think of it as sharing equally. If you have three friends and you give each one a slice of pizza, you're distributing one pizza among three people. Similarly, in algebra, if you have a term outside the parenthesis, you 'give' it to each term inside the parenthesis. In our exercise, the term outside the parenthesis is \(3a^2\), and it needs to be distributed across each term inside: \(2a^3\), \(-10a^2\), \(-4a\), and +9.
By doing this, you’re setting the stage for further simplification, making it easier to combine like terms and solve the expression.
Think of it as sharing equally. If you have three friends and you give each one a slice of pizza, you're distributing one pizza among three people. Similarly, in algebra, if you have a term outside the parenthesis, you 'give' it to each term inside the parenthesis. In our exercise, the term outside the parenthesis is \(3a^2\), and it needs to be distributed across each term inside: \(2a^3\), \(-10a^2\), \(-4a\), and +9.
By doing this, you’re setting the stage for further simplification, making it easier to combine like terms and solve the expression.
Combining Like Terms
Once you've distributed, it's time to bring like terms together through 'combining like terms.' Imagine you're organizing a fruit bowl. You'd group apples with apples, oranges with oranges, right? In algebra, 'like terms' are terms that have the same variables raised to the same powers. Coefficients can be different, but the variables must match.
In our exercise, after distributing \(3a^2\) and multiplying, we don't find any terms that have the same variable with the same exponent, hence there are no 'like terms' to combine. If there were, we would add or subtract the coefficients of these like terms to simplify the expression.
In our exercise, after distributing \(3a^2\) and multiplying, we don't find any terms that have the same variable with the same exponent, hence there are no 'like terms' to combine. If there were, we would add or subtract the coefficients of these like terms to simplify the expression.
Multiplication of Polynomials
When multiplying polynomials, it's like conducting a full-blown orchestra – every element plays a crucial role. Breaking down the term 'polynomial,' 'poly' means 'many' and 'nomial' means 'terms.' So a polynomial is an expression with many terms.
In algebra, multiplying polynomials involves distributing every term of the first polynomial to every term of the second polynomial. It's crucial to keep order and organization throughout this process. In the provided exercise, we multiplied a monomial \(3a^2\) by a polynomial to obtain a new polynomial. This technique is used as a building block for more complicated operations in algebra, such as factoring and solving polynomial equations.
In algebra, multiplying polynomials involves distributing every term of the first polynomial to every term of the second polynomial. It's crucial to keep order and organization throughout this process. In the provided exercise, we multiplied a monomial \(3a^2\) by a polynomial to obtain a new polynomial. This technique is used as a building block for more complicated operations in algebra, such as factoring and solving polynomial equations.
Exponents in Algebra
Exponents can be thought of as repeated multiplication. If you see an exponent, it tells you how many times to multiply the base by itself. For example, \(a^3\) means \(a \times a \times a\). In algebra, when you're multiplying two exponential expressions that have the same base, you keep the base and add the exponents together.
This rule streamlines operations with polynomials significantly. Referring back to our example: when we multiplied \(3a^2 \times 2a^3\), we simply added the exponents of \(a\) to get \(3\times 2a^{2+3} = 6a^5\). Remember, this rule only applies to multiplication with the same base; for division, you subtract the exponents, and for raising a power to a power, you multiply the exponents.
This rule streamlines operations with polynomials significantly. Referring back to our example: when we multiplied \(3a^2 \times 2a^3\), we simply added the exponents of \(a\) to get \(3\times 2a^{2+3} = 6a^5\). Remember, this rule only applies to multiplication with the same base; for division, you subtract the exponents, and for raising a power to a power, you multiply the exponents.
Other exercises in this chapter
Problem 101
For the following problems, perform the multiplications and combine any like terms. $$ 8\left(c^{3}+5 c+11\right) $$
View solution Problem 101
Simplify the algebraic expressions for the following problems. $$ (3 c+10)(3 c-10) $$
View solution Problem 102
Simplify the algebraic expressions for the following problems. $$ (4 a+3 b)(4 a-3 b) $$
View solution Problem 103
For the following problems, perform the multiplications and combine any like terms. $$ 6 a^{3} b^{3}\left(4 a^{2} b^{6}+7 a b^{8}+2 b^{10}+14\right) $$
View solution