Problem 102
Question
Fifteen persons, among whom are \(A\) and \(B\), sit down at random at a round table. The probability that there are 4 persons between \(A\) and \(B\) is (A) \(\frac{1}{3}\) (B) \(\frac{1}{7}\) (C) \(\frac{1}{5}\) (D) none of these
Step-by-Step Solution
Verified Answer
(B) \(\frac{1}{7}\).
1Step 1: Understanding the circular permutation
In a round table arrangement with 15 people, we fix one person to break the symmetry of the circle. This leaves us with 14 people to arrange around this circle.
2Step 2: Positioning A and B with 4 people between them
To have exactly 4 people sitting between A and B, treat A and B as markers. If we fix A's position, there are two possible scenarios (clockwise or counterclockwise) as B can either be to the left or right with 4 people between them. There are only 2 such positions around one fixed A.
3Step 3: Counting the number of favorable arrangements
From Step 2, there are 2 favorable ways to place B relative to A.
4Step 4: Calculating total arrangements of the remaining people
With A fixed, 13 other people are free to be placed in the remaining 13 positions. This can be done in \(13!\) ways.
5Step 5: Calculating the probability
The total ways to arrange 14 people (considering one is fixed) is \(14!\). The probability is therefore computed as the fraction of favorable outcomes over total outcomes: \[ \text{Probability} = \frac{2 \times 13!}{14!} = \frac{2}{14} = \frac{1}{7}. \]
6Step 6: Conclusion
Thus, the probability that there are 4 persons between A and B in the round table arrangement is \(\frac{1}{7}\).
Key Concepts
Probability CalculationFactorial in CombinatoricsRound Table Problem
Probability Calculation
Probability is a branch of mathematics that deals with the likelihood or chance of different outcomes. In many real-world scenarios, probability is used to predict how likely an event is to occur. When calculating probability, we use the following formula:
After pinpointing the favorable outcomes, dividing this by the total number of possible arrangements gives us the probability. Such calculations always require a detailed breakdown of the problem, as seen with deciding how many people are between certain individuals at a table. This method ensures accuracy and clarity.
- The probability of an event = \( \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} \).
After pinpointing the favorable outcomes, dividing this by the total number of possible arrangements gives us the probability. Such calculations always require a detailed breakdown of the problem, as seen with deciding how many people are between certain individuals at a table. This method ensures accuracy and clarity.
Factorial in Combinatorics
Factorial is an essential concept in combinatorics, which is the branch of mathematics focused on counting, arrangement, and combination. The factorial of a number \( n \), denoted as \( n! \), is the product of all positive integers less than or equal to \( n \).
In the context of circular permutations like in our round table problem, factorial is used to calculate both the total number of ways people can be seated (14!) and the number of ways left when one person's position is fixed (13!). This helps in analyzing the potential arrangements or layouts in a problem efficiently.
Knowing when to use factorials can greatly enhance your problem-solving skills in probability and combinatorics, making these calculations more intuitive.
- For example, \( 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \).
In the context of circular permutations like in our round table problem, factorial is used to calculate both the total number of ways people can be seated (14!) and the number of ways left when one person's position is fixed (13!). This helps in analyzing the potential arrangements or layouts in a problem efficiently.
Knowing when to use factorials can greatly enhance your problem-solving skills in probability and combinatorics, making these calculations more intuitive.
Round Table Problem
The round table problem is a classic permutation problem that involves arranging people or objects in a circle. In circular permutation, the focus is on positions relative to each other, unlike linear permutations where edges matter. To understand this concept, imagine you have people sitting in a circle.
To calculate permutations in a round table problem, we often fix one person's position to break the rotational symmetry. This effectively linearizes the circle, allowing calculations akin to linear permutations. This is because there are no distinct ends in a circle; hence fixing a position avoids overcounting equivalent arrangements.
To calculate permutations in a round table problem, we often fix one person's position to break the rotational symmetry. This effectively linearizes the circle, allowing calculations akin to linear permutations. This is because there are no distinct ends in a circle; hence fixing a position avoids overcounting equivalent arrangements.
- For example, if you have 15 people, you fix one person, and calculate how to arrange the 14 remaining people, leading to \( 14! \) arrangements.
Other exercises in this chapter
Problem 100
If \(p\) and \(q\) are chosen randomly from the set \((1,2,3,4,\), \(5,6,7,8,9,10\) ) with replacement then the probability that the roots of the equation \(x^{
View solution Problem 101
Let \(A, B, C\) be three events. If the probability of occurring exactly one event out of \(A\) and \(B\) is \(1-a\), out of \(B\) and \(C\) is \(1-2 a\), out o
View solution Problem 103
A bag contains \(n\) white and \(n\) red balls. Pairs of balls are drawn without replcement until the bag is empty. The probability that each pair consists of o
View solution Problem 104
A bag contains \(a\) white and \(b\) black balls. Two players \(A\) and \(B\) alternately draw a ball from the bag, replacing the ball each time after the draw
View solution