Problem 102
Question
A patient is administered mercury-197 to evaluate kidney function. Mercury- 197 has a half-life of 65 hours. What fraction of an initial dose of mercury-197 remains after 6 days?
Step-by-Step Solution
Verified Answer
Answer: Approximately 18.9% of the initial dose remains after 6 days.
1Step 1: Convert 6 days to hours
Since there are 24 hours in a day, to convert 6 days to hours, multiply the number of days by 24.
6 days × 24 hours/day = 144 hours
2Step 2: Find the number of half-lives
In this step, we will determine how many half-lives of 65 hours have occurred within 144 hours. To do this, divide the total time that has passed (144 hours) by the half-life of mercury-197 (65 hours).
Number of half-lives = 144 hours / 65 hours = 2.215
3Step 3: Calculate the fraction of the remaining dose
The fraction of the initial dose that remains after each half-life can be calculated by raising 1/2 to the power of the number of half-lives. In this case, we will raise 1/2 to the power of 2.215.
Fraction remaining = (1/2)^(2.215) = 0.189
So, approximately 18.9% of the initial dose of mercury-197 remains after 6 days.
Key Concepts
Half-Life CalculationKidney Function EvaluationNuclear Medicine
Half-Life Calculation
Understanding how to calculate half-life is crucial when dealing with radioactive substances. The half-life is the time it takes for half of a radioactive sample to decay. In calculations, you start with determining how many half-lives fit into a given period. This provides insight into how much of the initial substance remains.
To calculate half-life decay, follow these steps:
To calculate half-life decay, follow these steps:
- Convert all time units to one consistent unit, commonly hours or days.
- Determine how many half-lives fit into the timeframe by dividing the total time by the half-life duration of the substance.
- Use the decay formula: \[ ext{Remaining Fraction} = \left( \frac{1}{2} \right)^{\text{Number of Half-Lives}} \]
Kidney Function Evaluation
In medical practice, evaluating kidney function is essential for assessing a patient’s health. Kidneys play a crucial role in filtering and excreting waste products from the blood.
Radionuclide studies use radioactive substances like mercury-197 to measure how well the kidneys perform their tasks.
Here’s why it's significant:
Radionuclide studies use radioactive substances like mercury-197 to measure how well the kidneys perform their tasks.
Here’s why it's significant:
- These tests can highlight any inefficiencies in kidney filtering.
- The measurement of how quickly a substance is filtered provides insights into kidney health.
- An accurate assessment can lead to early detection of kidney disorders.
Nuclear Medicine
Nuclear medicine is a fascinating field that combines medicine and radioactive substances to diagnose and treat diseases. This approach utilizes small amounts of radioactive materials, known as radiotracers, to examine organ function more accurately than traditional imaging methods.
A key part of nuclear medicine is understanding tracer behavior and decay, such as the process seen with mercury-197. Here's why it's important:
A key part of nuclear medicine is understanding tracer behavior and decay, such as the process seen with mercury-197. Here's why it's important:
- Nuclear medicine procedures offer unmatched detail in visualizing organ and tissue function.
- The precise decay rates of substances like mercury-197 are crucial in ensuring accurate diagnostic information.
- This branch of medicine provides non-invasive options to understand complex medical conditions.
Other exercises in this chapter
Problem 98
Predict the most likely mode of decay for the following isotopes used as imaging agents in nuclear medicine: (a) \(^{133} \mathrm{Xe}\) (cerebral blood flow); (
View solution Problem 99
A 1.00 mg sample of \(^{192}\) Ir was inserted into the artery of a heart patient. After 30 days, 0.756 mg remained. What is the half-life of \(^{192} \mathrm{I
View solution Problem 103
Rhodium-105 is an isotope currently under investigation in diagnostic applications. The half-life of \(^{105} \mathrm{Rh}\) is \(35.4 \mathrm{h}\) which is suff
View solution Problem 104
Cancer Palladium-103 is used to treat prostate cancer by inserting a small \((1 \mathrm{mm} \times 5 \mathrm{mm})\) cylindrical piece of \(^{103} \mathrm{Pd}\)
View solution