Problem 101
Question
You have two pressure-proof steel cylinders of equal volume, one containing \(1.0 \mathrm{kg}\) of \(\mathrm{CO}\) and the other containing \(1.0 \mathrm{kg}\) of acetylene, \(\mathrm{C}_{2} \mathrm{H}_{2}\) (a) In which cylinder is the pressure greater at \(25^{\circ} \mathrm{C} ?\) (b) Which cylinder contains the greater number of molecules?
Step-by-Step Solution
Verified Answer
(a) Acetylene cylinder; (b) Acetylene cylinder.
1Step 1: Understanding Molar Mass
Firstly, we need to determine the molar mass of each gas. For carbon monoxide (\( \text{CO} \)), the molar mass is calculated as follows: \( \text{C: } 12.01 \, \text{g/mol} + \text{O: } 16.00 \, \text{g/mol} = 28.01 \, \text{g/mol} \). For acetylene (\( \text{C}_2\text{H}_2 \)), the molar mass is: \( \text{C: } 12.01 \, \text{g/mol} \times 2 + \text{H: } 1.01 \, \text{g/mol} \times 2 = 26.04 \, \text{g/mol} \).
2Step 2: Calculating Number of Moles
To find out the number of moles in each cylinder, use the formula: \( n = \frac{\text{mass}}{\text{molar mass}} \). For \( \text{CO} \): \( n_{\text{CO}} = \frac{1000 \, \text{g}}{28.01 \, \text{g/mol}} \approx 35.7 \, \text{mol} \). For \( \text{C}_2\text{H}_2 \): \( n_{\text{C}_2\text{H}_2} = \frac{1000 \, \text{g}}{26.04 \, \text{g/mol}} \approx 38.4 \, \text{mol} \).
3Step 3: Applying Ideal Gas Law
According to the ideal gas law \( PV = nRT \), pressure (\( P \)) is directly proportional to the number of moles (\( n \)) assuming volume (\( V \)) and temperature (\( T \)) are constant. Since \( n_{\text{C}_2\text{H}_2} > n_{\text{CO}} \), the pressure is greater in the acetylene (\( \text{C}_2\text{H}_2 \)) cylinder.
4Step 4: Determining Number of Molecules
The number of molecules in a gas is given by \( N = nN_A \), where \( N_A \) is Avogadro's number, \( 6.022 \times 10^{23} \, \text{mol}^{-1} \). Since the acetylene cylinder has more moles (\( n_{\text{C}_2\text{H}_2} > n_{\text{CO}} \)), it also contains more molecules.
Key Concepts
Molar MassAvogadro's NumberNumber of Moles
Molar Mass
Molar Mass is the mass of one mole of a given substance and is commonly expressed in grams per mole (g/mol). To calculate the molar mass, we need to sum up the atomic masses of all the atoms present in the molecular formula of the substance.
For example, in carbon monoxide (CO), the molar mass is determined by adding the atomic mass of carbon (12.01 g/mol) and oxygen (16.00 g/mol), resulting in a molar mass of 28.01 g/mol. Similarly, for acetylene (C\(_2\)H\(_2\)), we multiply the atomic mass of carbon by 2 (since there are two carbon atoms) and add to that the atomic mass of hydrogen multiplied by 2, giving a molar mass of 26.04 g/mol.
For example, in carbon monoxide (CO), the molar mass is determined by adding the atomic mass of carbon (12.01 g/mol) and oxygen (16.00 g/mol), resulting in a molar mass of 28.01 g/mol. Similarly, for acetylene (C\(_2\)H\(_2\)), we multiply the atomic mass of carbon by 2 (since there are two carbon atoms) and add to that the atomic mass of hydrogen multiplied by 2, giving a molar mass of 26.04 g/mol.
- CO has a molar mass of 28.01 g/mol
- C\(_2\)H\(_2\) has a molar mass of 26.04 g/mol
Avogadro's Number
Avogadro's Number is a fundamental constant in chemistry and is invaluable for understanding the composition of substances at the molecular level. This number, 6.022 × 10\(^{23}\) mol\(^{-1}\), represents the number of atoms, ions, or molecules contained in one mole of a substance.
In chemical calculations, such as determining the number of molecules in a given gas, Avogadro's number comes into play. When you know the number of moles of a substance, multiplying by Avogadro's number gives you the total number of molecules (or atoms or ions, depending on what's relevant).
In chemical calculations, such as determining the number of molecules in a given gas, Avogadro's number comes into play. When you know the number of moles of a substance, multiplying by Avogadro's number gives you the total number of molecules (or atoms or ions, depending on what's relevant).
- Avogadro's number = 6.022 × 10\(^{23}\) mol\(^{-1}\)
- Use Avogadro's number to convert between moles and molecules
Number of Moles
The Number of Moles indicates how many moles of a substance are present in a given mass. To calculate it, you divide the mass of the substance by its molar mass. This calculation is central to using the Ideal Gas Law, where the number of moles is a key variable that directly affects the calculations for pressure, volume, and temperature.
For instance, in the given cylinders problem, the number of moles for both CO and C\(_2\)H\(_2\) was calculated using the formula: \[ n = \frac{\text{mass}}{\text{molar mass}} \]
Applying this formula:
For instance, in the given cylinders problem, the number of moles for both CO and C\(_2\)H\(_2\) was calculated using the formula: \[ n = \frac{\text{mass}}{\text{molar mass}} \]
Applying this formula:
- The CO cylinder contains approximately 35.7 moles.
- The C\(_2\)H\(_2\) cylinder contains approximately 38.4 moles.
Other exercises in this chapter
Problem 99
A \(1.0-\) - flask contains 10.0 g each of \(\mathrm{O}_{2}\) and \(\mathrm{CO}_{2}\) at \(25^{\circ} \mathrm{C}\) (a) Which gas has the greater partial pressur
View solution Problem 100
If equal masses of \(\mathrm{O}_{2}\) and \(\mathrm{N}_{2}\) are placed in separate containers of equal volume at the same temperature, which of the following s
View solution Problem 102
Two flasks, each with a volume of \(1.00 \mathrm{L},\) contain \(\mathrm{O}_{2}\) gas with a pressure of 380 mm Hg. Flask \(A\) is at \(25^{\circ} \mathrm{C}\)
View solution Problem 104
Each of four flasks is filled with a different gas. Each flask has the same volume, and each is filled to the same pressure, \(3.0 \mathrm{atm},\) at \(25^{\cir
View solution