Problem 101
Question
What is the total number of (a) \(\sigma\) bonds and (b) \(\pi\) bonds in the molecule \(\mathrm{CH}_{3} \mathrm{NCO}\) ?
Step-by-Step Solution
Verified Answer
The molecule \(\mathrm{CH}_{3} \mathrm{NCO}\) has a total of 6 sigma bonds and 2 pi bonds.
1Step 1: Break down molecule into structural formula
Firstly, it is necessary to know the molecular structure of \(\mathrm{CH}_{3} \mathrm{NCO}\). The structure is H3C-N=C=O, where the hyrdocarbon \(CH_{3}\) is bonded with Nitrogen, Nitrogen is double bonded with Carbon and Carbon is double bonded with Oxygen.
2Step 2: Count sigma bonds
Each single bond and each part of a double or triple bond is a sigma bond. So, in the molecule structure, there are three sigma bonds in the \(\mathrm{CH}_{3}\) group (between Carbon and Hydrogen atoms) and three more within the rest of the molecule (between Carbon-Nitrogen and Carbon-Oxygen). So, in total there are 6 sigma bonds.
3Step 3: Count pi bonds
Pi bonds are the 'extra' bonds in a double bond (N=C, C=O). For each double bond, there is one pi bond. Therefore, there are two pi bonds in the \(\mathrm{CH}_{3} \mathrm{NCO}\) molecule.
Key Concepts
Sigma BondsPi BondsMolecular Structure
Sigma Bonds
Sigma bonds are the first bonds formed between two atoms in a molecule. They are the strongest type of covalent bond due to the head-on overlapping of atomic orbitals. The sigma bond (denoted as \( \sigma \) bond) allows for free rotation of bonded atoms, which can influence the shape of the molecule.
In the molecule \( \text{CH}_3\text{NCO} \), sigma bonds are found in several places:
In the molecule \( \text{CH}_3\text{NCO} \), sigma bonds are found in several places:
- Three sigma bonds are present between the carbon atom and the three hydrogen atoms in the \( \text{CH}_3 \) group.
- One sigma bond exists between the carbon atom and the nitrogen atom.
- Another sigma bond is found between the nitrogen atom and the carbon atom.
- Finally, there is a sigma bond between the carbon and oxygen atoms.
Pi Bonds
Pi bonds (\( \pi \) bonds) are formed by the side-by-side overlap of p orbitals. They occur in addition to a sigma bond, which is why they are known as the 'extra' bonds in double or triple bonds. Unlike sigma bonds, pi bonds restrict the rotation of bonded atoms, playing a significant role in determining the molecule's geometry.
In a molecule like \( \text{CH}_3\text{NCO} \):
In a molecule like \( \text{CH}_3\text{NCO} \):
- There is one pi bond between the nitrogen (N) and the central carbon (C), as they are doubly bonded.
- Similarly, one pi bond exists between the carbon (C) and the oxygen (O), also connected by a double bond.
Molecular Structure
Understanding the molecular structure of a compound is key to identifying the number and types of bonds it contains. The molecular structure of \( \text{CH}_3\text{NCO} \) can be visualized as a series of atoms bonded in a chain: H\( _3 \)C-N=C=O.
To interpret this structure:
To interpret this structure:
- The \( \text{CH}_3 \) group forms a chain with three hydrogen atoms bonded to a central carbon atom.
- The carbon atom is then bonded to nitrogen, which is indicated in the formula.
- Following the nitrogen, the carbon atom forms a double bond, indicated by \( = \), with an oxygen atom.
Other exercises in this chapter
Problem 99
Explain why the molecular structure of \(\mathrm{BF}_{3}\) cannot be adequately described through overlaps involving pure \(s\) and \(p\) orbitals.
View solution Problem 100
Why does the hybridization \(s p^{3} d\) not account for bonding in the molecule BrF \(_{5} ?\) What hybridization scheme does work? Explain.
View solution Problem 102
102\. Which of the following species are paramagnetic? (a) \(\mathrm{B}_{2} ;\) (b) \(\mathrm{B}_{2}^{-} ;\) (c) \(\mathrm{B}_{2}^{+}\). Which species has the s
View solution Problem 103
Use the valence molecular orbital configuration to determine which of the following species is expected to have the lowest ionization energy: (a) \(\mathrm{C}_{
View solution