Problem 101
Question
Verify the identity algebraically. Use a graphing utility to check your result graphically. $$\csc 2 \theta=\frac{\csc \theta}{2 \cos \theta}$$
Step-by-Step Solution
Verified Answer
The identity \(\csc 2 \theta=\frac{\csc \theta}{2 \cos \theta}\) is verified to be true both algebraically (by simplifying the expressions using trigonometric identities and equations) and through graphical representation.
1Step 1: Recall Trigonometric Identity
We first recall the double angle formula for cosecant, which is \(\csc 2\theta = 2\csc \theta \cot \theta\). This will be useful in simplifying left side of the identity.
2Step 2: Simplify Left Side
Substitute the double angle formula into the left side, we get \(\csc 2\theta = 2\csc \theta \cot\theta\). Since \(\cot \theta = \frac{1}{\tan \theta}\), and \(\tan \theta = \frac{\sin \theta}{\cos \theta}\), then \(\cot \theta = \frac{\cos \theta}{\sin \theta}\), the equation becomes \(\csc 2\theta = 2\csc \theta \cdot \frac{\cos \theta}{\sin \theta}\).
3Step 3: Simplify More
Since \(\csc \theta = \frac{1}{\sin \theta}\), replace it, we obtain \(\csc 2\theta = 2 \cdot \frac{1}{\sin \theta} \cdot \frac{\cos \theta}{\sin \theta} = \frac{1}{2\sin^2\theta}\cdot2\cos \theta = \frac{\csc \theta}{2\cos \theta}\). Left side and right side are equal now, the trigonometric identity is proved.
4Step 4: Verify by Graphing
Proceed to verify graphically using a graphing utility. Graph both \(\csc 2\theta\) and \(\frac{\csc \theta}{2\cos \theta}\) on the same graph. They should produce identical graphs if the identity holds true.
Key Concepts
Cosecant FunctionDouble Angle FormulasGraphing Trigonometric Functions
Cosecant Function
The cosecant function, indicated as \( \csc \theta \), is one of the trigonometric functions related to a right-angled triangle. It is defined as the reciprocal of the sine function. Therefore, \( \csc \theta = \frac{1}{\sin \theta} \). This function becomes particularly useful in various trigonometric identities and transformations.
- **Sin and Cosecant:** Since cosecant is the reciprocal of sine, it is undefined wherever sine is zero. This occurs at integer multiples of \( \pi \).
- **Range and Domain:** Because \( \csc \theta \) is the reciprocal, its range is \((-\infty, -1] \cup [1, \infty)\). Its domain consists of all real numbers except where \( \sin \theta = 0 \).
- **Important Property:** For any angle \( \theta \), \( \csc \theta \) changes signs whenever sine changes signs.
Double Angle Formulas
Double angle formulas are essential tools in trigonometry that help transform expressions or solve trigonometric equations. The double angle formula for cosecant, \( \csc 2\theta \), can be derived using known relationships among trigonometric functions.
- **The Formula:** Specifically, \( \csc 2\theta = 2\csc \theta \cot \theta \). To remember this, consider translating combined angles in terms of single angle functions.
- **Breaking it Down:** The cotangent function can be expressed as \( \cot \theta = \frac{\cos \theta}{\sin \theta} \). Therefore, substituting \( \cot \theta \) gives \( \csc 2\theta = 2 \times \frac{1}{\sin \theta} \times \frac{\cos \theta}{\sin \theta} \).
- **Application:** These formulas simplify complex expressions, like those encountered in calculus and physics, providing simpler representations that are easier to work with analytically or graphically.
Graphing Trigonometric Functions
Graphing trigonometric functions can visualize the validity of expressions and identities. For verifying \( \csc 2\theta = \frac{\csc \theta}{2\cos \theta} \), graphing the two sides of this identity should produce identical curves if the identity is true.
- **Graph Setup:** Use a graphing calculator or utility, input both functions, \( \csc 2\theta \) and \( \frac{\csc \theta}{2\cos \theta} \), possibly as \( y_1 \) and \( y_2 \).
- **Observation:** If both functions superimpose exactly over each other over the domain defined, then it visually confirms the algebraic identity.
- **Aspects of Graphs:** Notice the reflection and symmetry in cosecant graphs. They generally have vertical asymptotes corresponding to the zeros of the sine function, giving them a distinct U-like shape.
Other exercises in this chapter
Problem 100
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