Problem 101
Question
Three consecutive binomial coefficients can never be in (A) G.P. (B) H.P. (C) A.P. (D) A.G.P.
Step-by-Step Solution
Verified Answer
Three consecutive binomial coefficients can never be in A.P.
1Step 1: Understand binomial coefficients
Binomial coefficients are numbers that appear in Pascal's Triangle and are written as \( \binom{n}{k} \), representing the number of ways to choose \( k \) items from \( n \) items without considering the order. For consecutive binomial coefficients, we consider three values: \( \binom{n}{r} \), \( \binom{n}{r+1} \), \( \binom{n}{r+2} \).
2Step 2: Identify sequences involved
The problem asks whether these three binomial coefficients can form specific types of sequences: Geometric Progression (G.P.), Harmonic Progression (H.P.), Arithmetic Progression (A.P.), and Arithmetico-Geometric Progression (A.G.P.).
3Step 3: Evaluate Conditions for A.P.
For an arithmetic progression (A.P.), the difference between consecutive terms is constant, i.e., \( \binom{n}{r+1} - \binom{n}{r} = \binom{n}{r+2} - \binom{n}{r+1} \). This translates to the middle term being the average of the first and third terms. In general, due to the combinatorial nature, the binomial coefficients cannot maintain this relationship.
4Step 4: Check other progressions if necessary
While the focus is on A.P., reviewing other progressions helps ensure none are overlooked. G.P., H.P., and A.G.P. are more complex and generally do not apply to binomial coefficients due to their multiplicative and additive nature.
Key Concepts
Geometric ProgressionArithmetic ProgressionHarmonic Progression
Geometric Progression
A geometric progression, or G.P., is a sequence where each term is multiplied by a constant ratio to get the next term. For instance, in the sequence 2, 4, 8, each term is multiplied by 2. One way to identify a geometric progression in practice is by checking if the ratio between consecutive terms remains consistent.
- If you have three terms, say a, b, and c, in geometric progression, then the relationship is given by \( \frac{b}{a} = \frac{c}{b} \).
- This constant is called the common ratio \( r \).
Arithmetic Progression
An arithmetic progression, or A.P., is a sequence where each term is derived by adding a constant difference to the preceding term. Think of a sequence like 3, 5, 7, where 2 is consistently added to each term.
Here’s how you can recognize an arithmetic progression:
Here’s how you can recognize an arithmetic progression:
- For three terms a, b, and c to be in A.P., they must satisfy \( b = \frac{a+c}{2} \).
- The difference between each term should remain constant, known as the common difference \( d \).
Harmonic Progression
A harmonic progression, or H.P., involves terms whose reciprocals are in arithmetic progression. This means that if you have a sequence \( a, b, c \) in H.P., then \( \frac{1}{a}, \frac{1}{b}, \frac{1}{c} \) will form an A.P.
For any three terms, the condition to check is:
For any three terms, the condition to check is:
- \( 2b = \frac{ac}{a+c} \), which results from the relationship \( \frac{1}{b} = \frac{1}{2} \left( \frac{1}{a} + \frac{1}{c} \right) \).
Other exercises in this chapter
Problem 99
If the 4th term in the expansion of \(\left(2+\frac{3}{8} x\right)^{10}\) has the maximum numerical value, then the range of values of is (A) \(-2 \leq x \leq 2
View solution Problem 100
If the 4th term in the expansion of \(\left(2+\frac{3}{8} x\right)^{10}\) has the maximum numerical value, then the range of values of is (A) \(-2 \leq x \leq 2
View solution Problem 102
The value of \(x\), for which the 6 th term in the expansion of the binomial \(\left[\sqrt{ \left.2^{\log \left(10-3^{x}\right.}\right)}+\sqrt[5]{2^{(x-2) \log
View solution Problem 104
The greatest term in the expansion of \((1+x)^{10}\), when \(x=\frac{2}{3}\) is (A) \(210\left(\frac{2}{3}\right)^{4}\) (B) \(6300\left(\frac{2}{3}\right)^{3}\)
View solution