Problem 101
Question
Sketch the graph of each function. Then locate the asymptote of the curve. $$ y=-27(3)^{x-1}+9 $$
Step-by-Step Solution
Verified Answer
The curve of the function \(y=-27(3)^{x-1}+9\) will be an inverted and shifted exponential curve, and will have a horizontal asymptote at \(y=9\).
1Step 1: Understanding the function
Firstly, acknowledge that the function provided, \(y=-27(3)^{x-1}+9\), is an exponential function. Here, \(a=-27\), \(b=3\), \(h=1\), and \(k=9\). This function implies the curve will flip over the x-axis because of the negative \(a\) value, move 1 unit right because of \(h=1\), and move up by 9 units because of \(k=9\).
2Step 2: Plotting the function
Now, begin plotting some key points to start sketching the graph. For \(x=0\), we get \(y=0\). For \(x=1\), replacing it in the original formula yields \(y=9\). For \(x=2\), this gives \(y=-18\). Plot these three points and draw a smooth curve through them, reflecting the shape of an exponential function.
3Step 3: Finding the asymptote
Given that this is an exponential function with a vertical shift up by 9, it will have a horizontal asymptote at \(y=9\). The curve will approach this line but never cross it.
Key Concepts
Understanding Asymptotes in Exponential FunctionsStep-by-Step Graph Sketching of Exponential FunctionsImpact of Transformations on Exponential Functions
Understanding Asymptotes in Exponential Functions
An asymptote is a line that a graph approaches but never actually touches. For exponential functions, horizontal asymptotes are the most common. In the case of the function \( y = -27(3)^{x-1} + 9 \), the asymptote is influenced by the constant \( k \). This constant shifts the entire graph up or down.
For this function, \( k = 9 \). As a result, the horizontal asymptote is located at \( y = 9 \). No matter how far the graph stretches in the positive or negative x-direction, it will never reach or cross this line.
The asymptote acts as a boundary, shaping the graph's behavior as it extends. This concept is crucial in sketching and understanding the limitations or extents of exponential graphs.
For this function, \( k = 9 \). As a result, the horizontal asymptote is located at \( y = 9 \). No matter how far the graph stretches in the positive or negative x-direction, it will never reach or cross this line.
The asymptote acts as a boundary, shaping the graph's behavior as it extends. This concept is crucial in sketching and understanding the limitations or extents of exponential graphs.
Step-by-Step Graph Sketching of Exponential Functions
Graph sketching is the process of drawing a rough representation of the function's curve. For the function \( y = -27(3)^{x-1} + 9 \), the graph follows several steps to capture its essence.
- Identify Key Points: Before sketching, find key points like the y-intercept and other values. In this function, the points calculated were \((0, 0)\), \((1, 9)\), and \((2, -18)\).
- Draw the Curve: Use these points to draw a smooth, continuous curve. Make sure this curve reflects the behavior of exponential functions, where the rate of increase or decrease is proportional.
- Consider the Asymptote: The graph will approach but not cross the line \( y=9 \).
Impact of Transformations on Exponential Functions
Transformations alter the appearance of a function's graph without changing its essential shape. The function \( y = -27(3)^{x-1} + 9 \) includes several transformations that modify its graph.
- Reflection: The negative value of \( a \) flips the graph over the x-axis. This reflection changes the direction in which the exponential curve opens.
- Horizontal Shift: The term \( x-1 \) shifts the graph 1 unit to the right. In general, \( x-h \) in the function \((x-h)\) represents a shift of \( h \) units to the right.
- Vertical Shift: The constant \( +9 \) results in a shift 9 units upwards, hence changing the baseline from which the graph grows or decays.
Other exercises in this chapter
Problem 100
Sketch the graph of each function. Then locate the asymptote of the curve. $$ y=-10(4)^{x+2} $$
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Solve each equation. Check for extraneous solutions. \(\sqrt[3]{7 x}-4=0\)
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Solve each equation. Check for extraneous solutions. \(2 \sqrt{w-1}=\sqrt{w+2}\)
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Write each expression in radical form. $$ t^{\frac{2}{3}} $$
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