Problem 101
Question
Match the following: List I List II 1\. element with highest (i) \(\mathrm{I}_{2}\) electronegativity 2\. element with highest (ii) \(\mathrm{Br}_{2}\) electron affinity 3\. liquid non metal (iii) \(\mathrm{Cl}_{2}\) 4\. metallic solid (iv) \(\mathrm{F}_{2}\) The correct matching is: (1) (2) (3) (4) (a) (iii) (ii) (i) (iv) (b) (iv) (iii) (i) (ii) (c) (ii) (iii) (iv) (i) (d) (i) (ii) (iii) (iv)
Step-by-Step Solution
Verified Answer
The correct matching is option (b).
1Step 1: Understand the Match Options
There are pairs given in List I and List II. We need to match each item in List I with the correct item from List II based on characteristics such as highest electronegativity, highest electron affinity, liquid state, and metallic nature.
2Step 2: Identify Element Characteristics (Step 1)
We know that Fluorine (F_{2}) has the highest electronegativity among the elements listed.
3Step 3: Identify Element Characteristics (Step 2)
Chlorine (Cl_{2}) is known to have the highest electron affinity among the elements provided.
4Step 4: Identify Element Characteristics (Step 3)
Bromine (Br_{2}) is the only liquid nonmetal at room temperature in the list.
5Step 5: Identify Element Characteristics (Step 4)
Iodine (I_{2}) exists as a metallic solid in its elemental state.
6Step 6: Match List I with List II
Using the identified characteristics, match as follows:
1. Element with highest electronegativity: F_{2} (iv)
2. Element with highest electron affinity: Cl_{2} (iii)
3. Liquid non-metal: Br_{2} (ii)
4. Metallic solid: I_{2} (i)
7Step 7: Select the Correct Option
Match these with their corresponding positions:
1 - (iv)
2 - (iii)
3 - (ii)
4 - (i)
This corresponds to option (b).
Key Concepts
ElectronegativityElectron AffinityLiquid NonmetalMetallic Solid
Electronegativity
Electronegativity is a measure of how strongly an atom can attract or hold onto electrons in a chemical bond. Think of it like a tug-of-war, where the atom with higher electronegativity pulls the electrons closer to itself. This concept is central to understanding how atoms interact in molecules.
If an atom draws electrons closer, it gains a partial negative charge, while the other atom becomes partially positive. This helps explain why some molecules are polar, having a positive and negative side.
If an atom draws electrons closer, it gains a partial negative charge, while the other atom becomes partially positive. This helps explain why some molecules are polar, having a positive and negative side.
- Fluorine ( F_{2} ) has the highest electronegativity of all elements; hence, it tends to attract electrons strongly in a bond.
- The electronegativity scale was developed by Linus Pauling, and it typically ranges from about 0.7 for francium (lowest) to 3.98 for fluorine (highest).
Electron Affinity
The electron affinity of an element is the amount of energy released when an electron is added to a neutral atom. It's the opposite of ionization energy, which measures how much energy is needed to remove an electron.
An element with high electron affinity tends to gain electrons more readily. This trait is important in defining how reactive an element might be, especially with nonmetals.
An element with high electron affinity tends to gain electrons more readily. This trait is important in defining how reactive an element might be, especially with nonmetals.
- Chlorine ( Cl_{2} ) is known for having one of the highest electron affinities. It releases a significant amount of energy when it gains an electron, becoming more stable.
- Typically, nonmetals have higher electron affinities than metals since they tend to gain electrons to fill their outer electron shells.
Liquid Nonmetal
The term 'liquid nonmetal' refers to the physical state of certain elements at room temperature. Most nonmetals are gases or solids, but some can be found as liquids.
Bromine ( Br_{2} ) is unique among common nonmetals because it is a liquid at room temperature. This trait is rather unusual in comparison to other nonmetals which are typically found in gaseous or solid states at similar conditions.
Bromine ( Br_{2} ) is unique among common nonmetals because it is a liquid at room temperature. This trait is rather unusual in comparison to other nonmetals which are typically found in gaseous or solid states at similar conditions.
- Bromine has a dark, reddish-brown color and a strong, unpleasant smell.
- It has applications in areas like flame retardants, and its liquid form is very reactive.
Metallic Solid
When we talk about a metallic solid, it refers to a state where the elements share electrons in a vast three-dimensional network. This structure gives metals their characteristic properties, such as electrical conductivity and malleability.
Interestingly, iodine ( I_{2} ) is a nonmetal that exhibits metallic characteristics under certain conditions, referred to as a metallic solid. It crystallizes in a way that allows it to conduct some electricity, and it has a shiny, metallic luster when pure.
Interestingly, iodine ( I_{2} ) is a nonmetal that exhibits metallic characteristics under certain conditions, referred to as a metallic solid. It crystallizes in a way that allows it to conduct some electricity, and it has a shiny, metallic luster when pure.
- This dual nature makes iodine unique among halogens.
- Metallic iodine can demonstrate properties common to metals while being primarily a nonmetal element.
Other exercises in this chapter
Problem 99
Which of the following orders are correct? (i) Thermal stability \(\mathrm{BeCO}_{3}\mathrm{NaOH}>\mathrm{KOH}>\mathrm{RbOH}>\mathrm{CsOH}\) (iii) Solubility in
View solution Problem 100
Sodium thiosulphate is used in photography because of its (a) reaction with light (b) oxidizing behaviour (c) reducing behaviour (d) complex forming behaviour
View solution Problem 101
Match the following: List I (n= un-paired e-) \(\quad\) List II (Meg. moment) 1\. \(\mathrm{Sc}^{3+}=0\) (i) \(5.92\) B.M. 2\. \(\mathrm{V}^{2+}=3\) (ii) \(1.73
View solution Problem 102
Calculate the electronegativity of fluorine from the following data. \(\mathrm{E}_{\mathrm{H}-\mathrm{H}}=104.2 \mathrm{Kcal} \mathrm{mol}^{-1}\) \(\mathrm{E}_{
View solution