Problem 101
Question
In Exercises 97-102, evaluate the expression. $$ \frac{5}{16}-\frac{3}{10} $$
Step-by-Step Solution
Verified Answer
The answer is \(\frac{1}{80}\).
1Step 1: Find the Least Common Denominator (LCD)
In order to subtract these fractions, they need to share the same denominator. The LCD or Least Common Denominator of 16 and 10 is 80. This is the smallest number that both 10 and 16 divide evenly into.
2Step 2: Convert the Fractions to have the LCD as the Denominator
For each fraction, multiply both the numerator and denominator by the factor needed to turn the original denominator into 80. For \(\frac{5}{16}\), multiply by 5. For \(\frac{3}{10}\), multiply by 8. This gives the new fractions \(\frac{25}{80}\) and \(\frac{24}{80}\).
3Step 3: Subtract the Fractions
Now both fractions have the same denominator, so they can be subtracted. Subtraction is carried out on the numerators only: \(\frac{25}{80}-\frac{24}{80}=\frac{1}{80}\).
Key Concepts
Understanding Least Common DenominatorConverting Fractions to Have the Same DenominatorSteps for Subtracting Fractions
Understanding Least Common Denominator
When subtracting or adding fractions, it is crucial for them to have the same denominator. The least common denominator (LCD) is the smallest multiple that is common to all denominators in the set. Finding the LCD simplifies the subtraction or addition process by aligning the fractions to a common base. For example, let's consider the fractions \( \frac{1}{3} \) and \( \frac{1}{4} \). The denominators here are 3 and 4.
The multiples of 3 are: 3, 6, 9, 12, 15, 18, and so forth. The multiples of 4 are: 4, 8, 12, 16, 20, etc. As you can see, the smallest number common to both lists is 12. Thus, 12 is the LCD for the fractions \( \frac{1}{3} \) and \( \frac{1}{4} \). Once you have found the LCD, you can proceed to convert the fractions so that they share this denominator.
Determining the LCD is an essential skill that helps streamline the fraction subtraction process.
The multiples of 3 are: 3, 6, 9, 12, 15, 18, and so forth. The multiples of 4 are: 4, 8, 12, 16, 20, etc. As you can see, the smallest number common to both lists is 12. Thus, 12 is the LCD for the fractions \( \frac{1}{3} \) and \( \frac{1}{4} \). Once you have found the LCD, you can proceed to convert the fractions so that they share this denominator.
Determining the LCD is an essential skill that helps streamline the fraction subtraction process.
Converting Fractions to Have the Same Denominator
Once the least common denominator is determined, the next step is converting the fractions so that they have this same denominator. This process involves adjusting the numerators according to the factor by which their original denominators are multiplied to reach the LCD. This ensures the value of the fraction remains unchanged.
For instance, take the fractions \( \frac{2}{5} \) and \( \frac{3}{7} \). If their LCD is 35, here's how you convert them:
For instance, take the fractions \( \frac{2}{5} \) and \( \frac{3}{7} \). If their LCD is 35, here's how you convert them:
- Multiply both the numerator and denominator of \( \frac{2}{5} \) by 7 (since \( 5 \times 7 = 35 \)), resulting in \( \frac{14}{35} \).
- Multiply both the numerator and denominator of \( \frac{3}{7} \) by 5 (because \( 7 \times 5 = 35 \)), resulting in \( \frac{15}{35} \).
Steps for Subtracting Fractions
Subtracting fractions with different denominators involves a few clear steps, ensuring each fraction has the same base to guarantee accuracy in subtraction.
Here’s a quick rundown of the process:
Here’s a quick rundown of the process:
- Identify the LCD: Determine the smallest common multiple of the two denominators.
- Convert the Fractions: Adjust the numerators and denominators so both fractions have the LCD as the new denominator.
- Subtract the Numerators: With both fractions now sharing a common denominator, you can simply subtract the numerators and keep the denominator the same.
- Simplify the Result: If possible, reduce the resulting fraction to its simplest form.
Other exercises in this chapter
Problem 100
In Exercises 97-102, evaluate the expression. $$ 6+3(4+2) $$
View solution Problem 100
In Exercises 97-100, identify the property of real numbers illustrated by the statement. $$ 7+(8+5)=(7+8)+5 $$
View solution Problem 102
$$ \frac{9}{16}+2 \frac{3}{12} $$
View solution Problem 103
In Exercises 103 and 104, evaluate the algebraic expression for the given values of the variable. $$ 3 x-2 $$ (a) \(x=2\) (b) \(x=-1\)
View solution