Problem 101
Question
If \(\vec{a}, \vec{b}, \vec{c}\) are vectors such that \([\vec{a} \vec{b} \vec{c}]=4\) then \([\vec{a} \times \vec{b} \vec{b} \times \vec{c} \vec{c} \times \vec{a}]=\) (a) 16 (b) 64 (c) 4 (d) 8
Step-by-Step Solution
Verified Answer
16
1Step 1: Understanding the Cube Volume Formula
In vector algebra, the expression \([\vec{a} \vec{b} \vec{c} ]\) denotes the scalar triple product \(\vec{a} \cdot (\vec{b} \times \vec{c})\), which represents the volume of the parallelepiped formed by the vectors \(\vec{a}, \vec{b}, \vec{c}\). Given \([\vec{a} \vec{b} \vec{c} ] = 4\), the volume is 4.
2Step 2: Evaluating the Parallelepiped Volume using Cross Products
We are asked to evaluate the scalar triple product \([\vec{a} \times \vec{b} \vec{b} \times \vec{c} \vec{c} \times \vec{a} ]\). We can use the identity \((\vec{a} \times \vec{b}) \cdot (\vec{b} \times \vec{c}) \times (\vec{c} \times \vec{a}) = ([\vec{a} \vec{b} \vec{c}])^2\) to solve this, which calculates the volume squared of the original vectors.
3Step 3: Applying the Identity Correction
The identity states that \((\vec{a} \times \vec{b}) \cdot (\vec{b} \times \vec{c}) \times (\vec{c} \times \vec{a}) = ([\vec{a} \vec{b} \vec{c}])^2\). Given this, we substitute with the provided volume \([\vec{a} \vec{b} \vec{c}] = 4\).
4Step 4: Calculate the Result
Plug in \([\vec{a} \vec{b} \vec{c}]=4\) into the identity: \(([\vec{a} \vec{b} \vec{c}])^2 = 4^2 = 16\). Thus, \([\vec{a} \times \vec{b} \vec{b} \times \vec{c} \vec{c} \times \vec{a} ] = 16.\)
Key Concepts
Scalar Triple ProductCross Product IdentitiesParallelepiped Volume
Scalar Triple Product
The scalar triple product of three vectors, \(\vec{a}, \vec{b}, \vec{c}\), is denoted by \([\vec{a} \vec{b} \vec{c} ]\). It is defined as \(\vec{a} \cdot (\vec{b} \times \vec{c})\). This expression not only involves both dot and cross products but also represents a significant geometric interpretation.
The scalar triple product gives the volume of the parallelepiped (a kind of 3D box) formed by these vectors. If you imagine placing the vectors like edges extending from a common vertex, \([\vec{a} \vec{b} \vec{c} ]\) tells you how much space is enclosed within. For instance, if \([\vec{a} \vec{b} \vec{c} ]=4\), the volume of the parallelepiped is 4 cubic units.
The scalar triple product gives the volume of the parallelepiped (a kind of 3D box) formed by these vectors. If you imagine placing the vectors like edges extending from a common vertex, \([\vec{a} \vec{b} \vec{c} ]\) tells you how much space is enclosed within. For instance, if \([\vec{a} \vec{b} \vec{c} ]=4\), the volume of the parallelepiped is 4 cubic units.
- The scalar triple product provides insight into the alignment of vectors. If it's zero, the vectors are coplanar, meaning they lie in the same plane and don't span any volume.
- Mathematically, the scalar triple product is invariant under any cyclic permutation of the vectors, meaning \([\vec{a} \vec{b} \vec{c} ] = [\vec{b} \vec{c} \vec{a} ] = [\vec{c} \vec{a} \vec{b} ]\).
Cross Product Identities
Cross product identities are essential tools in vector algebra that assist in simplifying expressions involving multiple vector cross products. The identity used here is:
Cross products themselves are essential as they yield vectors perpendicular to the original input vectors, effectively giving us insights into the orientation of spatial planes made by these vectors. They follow distributive and anticommutative properties, meaning:
- \( (\vec{a} \times \vec{b}) \cdot (\vec{b} \times \vec{c}) \times (\vec{c} \times \vec{a}) = ([\vec{a}, \vec{b}, \vec{c}])^2 \)
Cross products themselves are essential as they yield vectors perpendicular to the original input vectors, effectively giving us insights into the orientation of spatial planes made by these vectors. They follow distributive and anticommutative properties, meaning:
- \( \vec{a} \times (\vec{b} + \vec{c}) = \vec{a} \times \vec{b} + \vec{a} \times \vec{c} \)
- \( \vec{a} \times \vec{b} = - (\vec{b} \times \vec{a}) \)
Parallelepiped Volume
The volume of a parallelepiped is a fundamental concept in vector algebra, allowing us to find the space enclosed by three vectors. As discussed, the volume is given by the scalar triple product, \([\vec{a} \vec{b} \vec{c}]\). However, when analyzing complex structures or expressions, understanding how this translates with different vector arrangements is important.
In the context of the exercise, understanding how the identity \((\vec{a} \times \vec{b}) \cdot (\vec{b} \times \vec{c}) \times (\vec{c} \times \vec{a}) = ([\vec{a}, \vec{b}, \vec{c}])^2\) was applied reveals the hidden layers of vector arrangement possibilities and their effects on volume. It shows that even if vectors are rearranged through cross products, the calculated volume squared is still consistent when this specific identity holds.
Parallelepiped volumes often crop up in physics and engineering when calculating real-world scenarios involving forces and movement through space. Comprehension of this geometric interpretation of vector quantities is invaluable for resolving spatial problems effectively.
In the context of the exercise, understanding how the identity \((\vec{a} \times \vec{b}) \cdot (\vec{b} \times \vec{c}) \times (\vec{c} \times \vec{a}) = ([\vec{a}, \vec{b}, \vec{c}])^2\) was applied reveals the hidden layers of vector arrangement possibilities and their effects on volume. It shows that even if vectors are rearranged through cross products, the calculated volume squared is still consistent when this specific identity holds.
Parallelepiped volumes often crop up in physics and engineering when calculating real-world scenarios involving forces and movement through space. Comprehension of this geometric interpretation of vector quantities is invaluable for resolving spatial problems effectively.
Other exercises in this chapter
Problem 99
\(\vec{a}=3 \hat{i}-5 \hat{j}\) and \(\vec{b}=6 \hat{i}+3 \hat{j}\) are two vectors and \(\vec{c}\) is a vector such that \(\vec{c}=\vec{a} \times \vec{b}\) the
View solution Problem 100
If the vectors \(\vec{c}, \vec{a}=x \hat{i}+y \hat{j}+z \hat{k}\) and \(\hat{b}=\hat{j}\) are such that \(\vec{a}, \vec{c}\) and \(\vec{b}\) form a right handed
View solution Problem 103
A particle just clears a wall of height \(\mathrm{b}\) at a distance a and strikes the ground at a distance \(c\) from the point of projection. The angle of pro
View solution Problem 104
A body weighing \(13 \mathrm{~kg}\) is suspended by two strings \(5 \mathrm{~m}\) and \(12 \mathrm{~m}\) long, their other ends being fastened to the extremitie
View solution