Problem 101
Question
Half-life period of the radioactive element \(X\) is 10 hours. Amount of \(X\) left in the 1 1th hour starting with one \(\operatorname{mol} \mathrm{X}\) is (a) \((1 / 2)^{1 / 10}\) (b) \((1 / 2)^{11 / 10}\) (c) \((1 / 2)^{12 / 11}\) (d) \((1 / 2)^{1 / 11}\)
Step-by-Step Solution
Verified Answer
(b) \((1 / 2)^{11 / 10}\)
1Step 1: Understand the Half-Life Concept
The half-life of a radioactive element is the time required for half of the radioactive atoms in a sample to decay. In this case, the element X has a half-life of 10 hours, meaning that every 10 hours, half of the original amount of X remains.
2Step 2: Apply the Half-Life Formula
The formula to calculate the remaining quantity of a radioactive element is \( N = N_0 \left( \frac{1}{2} \right)^{t/T} \), where \( N_0 \) is the initial quantity, \( t \) is the time elapsed, \( T \) is the half-life, and \( N \) is the remaining amount.
3Step 3: Calculate the Remaining Amount after 11 Hours
Here, \( N_0 = 1 \) mol, \( t = 11 \) hours, and \( T = 10 \) hours. Substitute these values into the formula: \( N = 1 \left( \frac{1}{2} \right)^{11/10} \). This simplifies to \( N = \left( \frac{1}{2} \right)^{11/10} \).
4Step 4: Determine the Correct Answer Option
Check the options given: (a) \((1 / 2)^{1 / 10}\)(b) \((1 / 2)^{11 / 10}\)(c) \((1 / 2)^{12 / 11}\)(d) \((1 / 2)^{1 / 11}\).The correct answer that matches our calculated expression is option (b).
Key Concepts
Radioactive DecayHalf-Life FormulaRemaining Amount Calculation
Radioactive Decay
Radioactive decay is a process by which an unstable atomic nucleus loses energy by emitting radiation. During this transformation, the nucleus of a radioactive element decays into a different element or a different isotope, releasing particles such as alpha particles, beta particles, or gamma rays. This release of particles leads to a change in the atomic structure of the radioactive substance.
A few key points about radioactive decay include:
A few key points about radioactive decay include:
- It is a random process at the level of single atoms, meaning it is impossible to predict when a particular atom will decay.
- However, with a large number of atoms, decay rates become predictable and are described by the half-life.
- Radioactive decay follows first-order kinetics, where the rate of decay is directly proportional to the number of undecayed nuclei present.
Half-Life Formula
The concept of a half-life is essential when discussing radioactive elements. It represents the time taken for half of a given quantity of a radioactive substance to decay. This period of time is consistent irrespective of the quantity present. The half-life provides a measure of the rate at which a radioactive element disintegrates.
For calculations involving half-life, scientists use the half-life formula:
For calculations involving half-life, scientists use the half-life formula:
- \[N = N_0 \left( \frac{1}{2} \right)^{t/T}\]
- Here, \(N\) is the remaining amount of the substance, \(N_0\) is the initial quantity, \(t\) is the time that has passed, and \(T\) is the half-life of the substance.
Remaining Amount Calculation
Calculating the remaining amount of a radioactive substance after a certain period involves using the half-life formula. This is crucial for predicting how much of a substance will be left after time has passed. Let's break it down.
Suppose we start with an initial amount of 1 mol of element \(X\), as in the original exercise. If \(X\) has a half-life of 10 hours, we want to know how much of \(X\) is left after 11 hours.
Suppose we start with an initial amount of 1 mol of element \(X\), as in the original exercise. If \(X\) has a half-life of 10 hours, we want to know how much of \(X\) is left after 11 hours.
- The formula given is:\[N = N_0 \left( \frac{1}{2} \right)^{t/T}\]
- Substitute \(N_0 = 1\) mol, \(t = 11\) hours, and \(T = 10\) hours:\[N = 1 \times \left( \frac{1}{2} \right)^{11/10}\]
- This calculation shows that the remaining amount of \(X\) is \[ \left( \frac{1}{2} \right)^{11/10} \] mol after 11 hours.
Other exercises in this chapter
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