Problem 101
Question
Explaining the Concepts. Explain how to square a binomial difference. Give an example with your explanation.
Step-by-Step Solution
Verified Answer
To square a binomial difference, use the formula \( (a - b)^2 = a^2 - 2ab + b^2 \). For instance, for (x - 3)^2, 'a' is 'x' and 'b' is '3'. The square resolves to \( (x)^2 - 2(x)(3) + (3)^2 \), which simplifies to \( x^2 - 6x + 9 \)
1Step 1: Understanding the Formula
Before anything else, it is critical to understand the formula for squaring a binomial difference. Simply put, the square of a binomial difference \( (a-b)^2 \) expands to \( a^2 - 2ab + b^2 \). This formula is a guide that allows us to expand the expression correctly. The square of a binomial is not simply squaring each term. Instead, the formula incorporates a middle term, -2ab, which is derived from applying the distributive property twice.
2Step 2: Applying the Formula
After understanding the formula, the next step is to apply this to a specific example. Choose an example - let's use (x - 3)^2 as an example. Here, 'a' corresponds to 'x' and 'b' corresponds to '3'.
3Step 3: Performing the Operation
Use the formula to expand (x - 3)^2. Replace 'a' with 'x' and 'b' with '3'. Applied to the formula, the operation would work out as follows: \( (x)^2 - 2(x)(3) + (3)^2 \)
4Step 4: Simplify the Result
The operation in step 3 provides a result that can be simplified further. \( (x)^2 - 2(x)(3) + (3)^2 \) simplifies to \( x^2 - 6x + 9 \)
Key Concepts
Algebraic ExpressionsBinomial TheoremDistributive Property
Algebraic Expressions
An algebraic expression is a mathematical phrase that can contain ordinary numbers, variables (like x or y), and operators (such as plus, minus, multiplication, and division). When dealing with algebraic expressions, it's important to understand how to manipulate these phrases to simplify or solve them.
For example, when squaring a binomial difference—a specific type of algebraic expression—you're effectively multiplying the binomial by itself. It's crucial not to make the common mistake of only squaring the individual terms. Instead, consider the interplay between the terms using the distributive property, which will introduce an additional middle term. In the expression \(a - b)^2\), 'a' and 'b' could represent any numbers or variables, and squaring the binomial difference requires careful expansion to capture all parts of the expression.
For example, when squaring a binomial difference—a specific type of algebraic expression—you're effectively multiplying the binomial by itself. It's crucial not to make the common mistake of only squaring the individual terms. Instead, consider the interplay between the terms using the distributive property, which will introduce an additional middle term. In the expression \(a - b)^2\), 'a' and 'b' could represent any numbers or variables, and squaring the binomial difference requires careful expansion to capture all parts of the expression.
Binomial Theorem
Understanding the Power of Squaring Binomials
The binomial theorem provides a systematic way to expand expressions that raise a binomial to a power. The binomial theorem states that \( (a + b)^n \) can be expanded, and the coefficients of the resulting terms are determined by Pascal's triangle or the binomial coefficients. However, when squaring a binomial, specifically when \(n\) is 2, the pattern simplifies to \(a^2 + 2ab + b^2\) or \(a^2 - 2ab + b^2\) for binomial sums and differences, respectively.These expressions follow the same pattern as dictated by the theorem, which helps students understand and memorize the proper structure of the expansion without having to rely on repeated distribution. It is the foundation for correctly expanding binomials raised to any power and is particularly helpful for understanding the nature of quadratic expressions.
Distributive Property
Apply It Twice and Simplify
The distributive property is a cornerstone of algebra and critical to understanding how to square a binomial difference. It states that in the expression \(a(b + c)\), you can distribute \(a\) to both \(b\) and \(c\), resulting in \(ab + ac\). When squaring a binomial difference, like \(a - b)^2\), the distributive property must be applied twice.First, you distribute the 'a' across the binomial \(a(a - b)\), yielding \(a^2 - ab\), and then distribute the '-b' likewise, resulting in \-ab + b^2\). Combining these using addition, remembering that \-ab\ and \-ab\ are like terms, produces the middle term of -2ab, yielding the complete squared expression \(a^2 - 2ab + b^2\). As shown in our example with \(x - 3)^2\, the distributive property confirms the importance of including the middle term, which could be overlooked if one was to incorrectly only square the individual terms of the binomial.
Other exercises in this chapter
Problem 101
Simplify by reducing the index of the radical. \(\sqrt[4]{5^{2}}\)
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determine whether each statement makes sense or does not make sense, and explain your reasoning. I subtracted \(\frac{3 x-5}{x-1}\) from \(\frac{x-3}{x-1}\) and
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Perform the indicated computations. Write the answers in scientific notation. If necessary, round the decimal factor in your scientific notation answer to two d
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Write each algebraic expression without parentheses. $$\frac{1}{3}(3 x)+[(4 y)+(-4 y)]$$
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