Problem 101
Question
Determine whether each statement makes sense or does not make sense, and explain your reasoning. I subtracted \(\frac{3 x-5}{x-1}\) from \(\frac{x-3}{x-1}\) and obtained a constant.
Step-by-Step Solution
Verified Answer
The given statement does not make sense because the resulting expression after subtracting the presented fractions is not a constant, but a function dependent on 'x'. The result is \(\frac{-2x +2}{x -1}\), which clearly depends on 'x' and is, hence, not a constant.
1Step 1: Understand the given statement
The given statement says that upon subtracting \(\frac{3x - 5}{x - 1}\) from \(\frac{x - 3}{x - 1}\), we get a constant. A constant is a value that doesn't change irrespective of the value of the variable involved, in this case, x.
2Step 2: Subtract the two fractions
Both fractions have the same denominator, which is \(x - 1\). When we subtract two fractions with the same denominator, we subtract the numerators while the denominator remains the same, thus \[\frac{(x-3) - (3x - 5)}{x - 1} = \frac{x - 3 - 3x +5}{x - 1} = \frac{-2x + 2}{x - 1}.\]
3Step 3: Analyze the result
Inspecting the outcome \(\frac{-2x + 2}{x - 1}\), it clearly depends on the value of 'x' and is not a constant because the numerator contains an 'x' term. Therefore, the given statement does not make sense.
Other exercises in this chapter
Problem 101
Simplify by reducing the index of the radical. $$\sqrt[4]{5^{2}}$$
View solution Problem 101
Explain how to square a binomial difference. Give an example with your explanation.
View solution Problem 101
Factor and simplify each algebraic expression. $$ (4 x-1)^{\frac{1}{2}}-5(4 x-1)^{\frac{3}{2}} $$
View solution Problem 101
Perform the indicated computations. Write the answers in scientifi c notation. If necessary, round the decimal factor in your scientific notation answer to two
View solution