Problem 100
Question
Use the most appropriate method to solve each equation on the interval \([0,2 \pi) .\) Use exact values where possible or give approximate solutions correct to four decimal places. $$ \sin 2 x+\cos x=0 $$
Step-by-Step Solution
Verified Answer
There are four solutions to the given equation which are \( x = \pi/2, 3\pi/2, 7\pi/6, 11\pi/6 \).
1Step 1: Apply Double-Angle Identity
Use the double-angle identity for sine to rewrite the equation in terms of \(x\). Replace \( \sin(2x) \) by \( 2 \sin(x) \cos(x) \) in the equation, yielding \( 2 \sin(x) \cos(x) + \cos(x) = 0 \).
2Step 2: Factor The Equation
Factor the above equation by taking \( \cos(x) \) common to get: \( \cos(x) (2 \sin(x) + 1) = 0 \).
3Step 3: Set Each Factor Equal to Zero
Set each factor equal to zero to find the value of \( x \): \( \cos(x) = 0 \) and \( 2 \sin(x)+1 =0 \).
4Step 4: Solve the Two Equations
From \( \cos(x) = 0\), we get \( x = \pi/2, 3\pi/2 \).From \( 2 \sin(x)+1 = 0 \), we get \( \sin(x) = -1/2 \), which gives \( x = 7\pi/6, 11\pi/6 \).
5Step 5: Check the Validity
Since all solutions are within the range \( [0, 2\pi) \), all results are valid.
Key Concepts
Double-Angle IdentityFactoring Trigonometric ExpressionsUnit Circle
Double-Angle Identity
The double-angle identity is a critical tool in trigonometry that simplifies expressions involving angles twice a given angle. In this exercise, the identity used is specifically for sine. The double-angle identities for sine is given by:\[\sin(2x) = 2\sin(x)\cos(x)\]This identity helps to transform the original equation \(\sin(2x) + \cos(x) = 0\) into a more manageable form. By applying the identity, it becomes \(2\sin(x)\cos(x) + \cos(x) = 0\). The purpose of using such identities is to rewrite functions involving multiple angles in terms of single angles. Understanding and applying the double-angle identity makes solving trigonometric equations more straightforward. This is particularly useful when equations involve products of trigonometric functions or need simplification for easier analysis.
Factoring Trigonometric Expressions
Factoring is a mathematical technique used to simplify equations and solve for unknown values. When dealing with trigonometric equations, factoring plays a crucial role especially when the equation involves a common trigonometric factor.In the given step-by-step solution, factoring is used to break down the equation \(2\sin(x)\cos(x) + \cos(x) = 0\). Here, the expression is factored by taking \(\cos(x)\) as a common factor:\[\cos(x)(2\sin(x) + 1) = 0\] Once the expressions are factored, it becomes easier to solve because each factor can be set to zero independently:
- \(\cos(x) = 0\)
- \(2\sin(x) + 1 = 0\)
Unit Circle
Understanding the unit circle is essential for solving trigonometric equations, particularly those that result from factoring and other transformations. The unit circle is a circle with a radius of one, centered at the origin of a coordinate plane.Key points along the unit circle correspond to important angle measures in radians and help determine the sine and cosine values of these angles. For example:
- At \(\frac{\pi}{2}\) and \(\frac{3\pi}{2}\), \(\cos(x) = 0\)
- At \(\frac{7\pi}{6}\) and \(\frac{11\pi}{6}\), \(\sin(x) = -\frac{1}{2}\)
Other exercises in this chapter
Problem 99
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Graph each equation in a \(\left[-2 \pi, 2 \pi, \frac{\pi}{2}\right] b y\) \([-3,3,1]\) viewing rectangle. Then a. Describe the graph using another equation, an
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