Problem 100
Question
Solve each equation. $$ \frac{7}{3} y+1=0 $$
Step-by-Step Solution
Verified Answer
The solution is \( y = -\frac{3}{7} \).
1Step 1: Isolate the Variable
First, we need to isolate the variable \( y \). Start by subtracting 1 from both sides of the equation to undo the addition: \[\frac{7}{3}y + 1 - 1 = 0 - 1\]This simplifies to:\[\frac{7}{3}y = -1\]
2Step 2: Solve for \( y \)
To solve for \( y \), multiply both sides of the equation by the reciprocal of \( \frac{7}{3} \), which is \( \frac{3}{7} \). This will cancel out the fraction on the left side:\[\left(\frac{3}{7}\right) \times \frac{7}{3}y = -1 \times \frac{3}{7}\]The left side simplifies to \( y \), and the right side simplifies to:\[y = -\frac{3}{7}\]
Key Concepts
Fraction OperationsIsolating VariablesReciprocal Multiplication
Fraction Operations
Handling fractions might seem tricky at first, but with a clear process, it becomes a lot easier. When dealing with equations, fractions can represent the coefficients of variables, as we saw with \(\frac{7}{3} y\) in this exercise.
Here are some basic operations you can perform on fractions:
Here are some basic operations you can perform on fractions:
- **Adding/Subtracting Fractions:** To add or subtract fractions, ensure they have a common denominator. If not, find equivalent fractions with the same denominator before performing the addition or subtraction.
- **Multiplying Fractions:** Multiply the numerators together and the denominators together. For example, \(\frac{a}{b} \times \frac{c}{d} = \frac{a \times c}{b \times d}\).
- **Dividing Fractions:** Inverse the second fraction and multiply. This is where reciprocal multiplication comes in, a concept we'll explore in detail soon.
Isolating Variables
Isolating the variable is a crucial step in solving any algebraic equation. Think of it as peeling away layers of operations surrounding the variable you want to solve for. This process reveals the 'core', or the value of the variable, just like removing layers from an onion. In our exercise, we had the equation \(\frac{7}{3} y + 1 = 0\).
To isolate \(y\), we started by removing the addition of 1. We do this by performing the inverse operation, which is subtraction. Here's how:
Remember, whatever operation you do to one side of the equation, you must also do to the other side. This keeps the equation balanced.
To isolate \(y\), we started by removing the addition of 1. We do this by performing the inverse operation, which is subtraction. Here's how:
- Subtract 1 from both sides of the equation: \(\frac{7}{3} y + 1 - 1 = 0 - 1\).
- This simplifies to \(\frac{7}{3} y = -1\), where all the terms have been simplified around \(y\).
Remember, whatever operation you do to one side of the equation, you must also do to the other side. This keeps the equation balanced.
Reciprocal Multiplication
Reciprocal multiplication is pivotal when solving equations with fractions, especially when isolating a variable. A reciprocal is essentially flipping the numerator and the denominator of a fraction. For example, the reciprocal of \(\frac{7}{3}\) is \(\frac{3}{7}\).
After isolating \(y\) in \(\frac{7}{3} y = -1\), we multiplied both sides of the equation by the reciprocal of \(\frac{7}{3}\). Here's why:
After isolating \(y\) in \(\frac{7}{3} y = -1\), we multiplied both sides of the equation by the reciprocal of \(\frac{7}{3}\). Here's why:
- Multiplying by the reciprocal \(\frac{3}{7}\) cancels out the fraction \(\frac{7}{3}\) on the left side of the equation because \(\left(\frac{3}{7}\right) \times \left(\frac{7}{3}\right) = 1\).
- This leaves us with \(1 \times y = y\) on one side of the equation.
- The right side of the equation becomes: \(-1 \times \frac{3}{7} = -\frac{3}{7}\).
Other exercises in this chapter
Problem 100
Simplify each expression. $$9\left(m^{3}+3\right)-5\left(3-m^{3}\right)-8\left(-1-m^{3}\right)$$
View solution Problem 100
Surface Area. To find the amount of tin needed to make the coffee can shown in below, we use the formula for the surface area of a right circular cylinder, \(A=
View solution Problem 101
Simplify each expression. $$21\left(\frac{6}{7} h^{2}-\frac{15}{21} h\right)+21\left(\frac{1}{3} h\right)$$
View solution Problem 101
Explain the difference between what perimeter measures and what area measures.
View solution