Problem 100
Question
Simplify. Rationalize all denominators. $$ (\sqrt{8}-\sqrt{7})^{2} $$
Step-by-Step Solution
Verified Answer
The simplified and fully rationalized version of the expression is \(15 - 4\sqrt{14}\).
1Step 1: Simplify Radical
First, break down \(\sqrt{8}\) into \(\sqrt{4}* \sqrt{2} = 2\sqrt{2}\). Thus the new expression would be \( (2\sqrt{2} - \sqrt{7})^{2} \)
2Step 2: Square the Expression
Next, square the entire expression. Using the formula (a - b)^{2} = a^{2} - 2ab + b^{2}, we get \(4*2 - 2*2*\sqrt{2}* \sqrt{7} + 7 = 8 - 4\sqrt{14} + 7 = 15 - 4\sqrt{14}.\)
3Step 3: Rationalize if Necessary
A final review of the expression finds no denominators to rationalize. The final simplified expression is \(15 - 4\sqrt{14}\).
Key Concepts
Simplifying RadicalsBinomial ExpansionExponent Rules
Simplifying Radicals
Understanding radicals is important in algebra. Radicals often involve square roots. We encounter them when we want to simplify expressions like \( \sqrt{8} \).
To simplify a radical, break it down into smaller parts. Find a perfect square factor of the number under the radical (also known as the radicand). For example, since the number 8 has the perfect square factor 4, we can express its square root as \( \sqrt{8} = \sqrt{4} \cdot \sqrt{2} = 2\sqrt{2} \).
The method involves these key steps:
To simplify a radical, break it down into smaller parts. Find a perfect square factor of the number under the radical (also known as the radicand). For example, since the number 8 has the perfect square factor 4, we can express its square root as \( \sqrt{8} = \sqrt{4} \cdot \sqrt{2} = 2\sqrt{2} \).
The method involves these key steps:
- Identify a largest perfect square as a factor of the radicand.
- Rewrite the radical as the product of two square roots.
- Simplify the expression by pulling out of the square root any factors that are perfect squares.
Binomial Expansion
Binomial expansion involves expressing the square of a binomial in expanded form. This is guided by the formula \((a - b)^2 = a^2 - 2ab + b^2 \).
When faced with the expression \((2\sqrt{2} - \sqrt{7})^2\), we use this formula to expand and simplify.
Here is how the expansion works in this scenario:
When faced with the expression \((2\sqrt{2} - \sqrt{7})^2\), we use this formula to expand and simplify.
Here is how the expansion works in this scenario:
- First, square the first term \((a)\) which results in \((2\sqrt{2})^2 = 8\).
- Second, calculate \(2ab\), which involves multiplying \(2\times 2\sqrt{2} \times \sqrt{7}\) to get \(-4\sqrt{14}\).
- Finally, square the second term \((b)\) resulting in \(\sqrt{7}^2 = 7\).
Exponent Rules
Exponent rules are foundational in understanding algebraic expressions. These rules help us to simplify expressions by applying specific guidelines on exponents.
When dealing with the expression \((2\sqrt{2} - \sqrt{7})^2\), exponent rules ensure that we multiply exponents correctly while maintaining order of operations.
Key exponent rules to apply include:
When dealing with the expression \((2\sqrt{2} - \sqrt{7})^2\), exponent rules ensure that we multiply exponents correctly while maintaining order of operations.
Key exponent rules to apply include:
- The power of a product rule, which states \((ab)^n = a^n \cdot b^n\). This means both terms inside a parenthesis are raised to the power when squared.
- The power of a power rule, which tells us \((a^m)^n = a^{m \cdot n}\). This is applied when simplifying expressions with nested exponents.
Other exercises in this chapter
Problem 99
Simplify. Rationalize all denominators. $$ (\sqrt{5}-1)(\sqrt{5}+4) $$
View solution Problem 100
Solve. Check for extraneous solutions. $$ (3 x)^{\frac{1}{2}}=(x+6)^{\frac{1}{2}} $$
View solution Problem 101
Expand each binomial. $$ (x+4)^{8} $$
View solution Problem 101
Simplify. Rationalize all denominators. $$ \frac{2+\sqrt{10}}{2-3 \sqrt{5}} $$
View solution