Problem 100
Question
In Exercises 95–102, use interval notation to represent all values of x satisfying the given conditions. $$ y=|2 x-5|+1 \text { and } y>9 $$
Step-by-Step Solution
Verified Answer
Therefore, the values of \(x\) that solve the inequality are all \(x\) that belong to the interval \((-∞, -1.5) \cup (6.5, ∞)\).
1Step 1: Work with the inequality
We're given that \(y = |2x - 5| + 1\) and \(y > 9\). Let's substitute the value of \(y\) in the inequality from the equation. So we get \(|2x - 5| + 1 > 9\). Now subtract 1 from both sides. We get \(|2x - 5| > 8\).
2Step 2: Break down the absolute value
The absolute value \( |a| \) has two possible solutions: \( a \) and \( -a \). So we can rewrite our inequality as two separate inequalities \( 2x - 5 > 8 \) and \( 2x - 5 < -8 \).
3Step 3: Solve the inequalities
For each inequality, we will isolate \(x\), which will give us the range of values it can take. We solve the first inequality and arrive at \(x > 6.5\), and from the second, we get \(x < -1.5\).
4Step 4: Combine the ranges
Given how the ranges for \(x\) are obtained, there's no value \(x\) that simultaneously obeys \(x > 6.5\) and \(x < -1.5\), hence there's no intersection. Thus, our answer will contain two separate ranges.
Key Concepts
Absolute Value InequalityCompound InequalitiesSolving Inequalities
Absolute Value Inequality
Understanding absolute value inequalities can greatly simplify the process of finding solutions. Absolute value refers to the distance a number is from zero on the number line, regardless of direction.
Thus, the absolute value of any real number is always non-negative.When solving an absolute value inequality like \( |2x - 5| > 8 \), it's important to remember that it involves considering two scenarios:
Thus, the absolute value of any real number is always non-negative.When solving an absolute value inequality like \( |2x - 5| > 8 \), it's important to remember that it involves considering two scenarios:
- \( 2x - 5 > 8 \): Here, the expression inside the absolute value is greater than 8.
- \( 2x - 5 < -8 \): Here, the expression is less than -8.
Compound Inequalities
Compound inequalities involve two separate inequalities joined by the words 'and' or 'or'.
These words determine how the intervals are expressed in notation.In the case of the problem statement with \( |2x - 5| > 8 \), you effectively have two separate inequalities to solve:
Understanding this concept is crucial as it dictates when a solution set will occupy a continuous range, or when it will segregate into two non-overlapping ranges.
These words determine how the intervals are expressed in notation.In the case of the problem statement with \( |2x - 5| > 8 \), you effectively have two separate inequalities to solve:
- \( 2x - 5 > 8 \) which simplifies to \( x > 6.5 \)
- \( 2x - 5 < -8 \) which simplifies to \( x < -1.5 \)
Understanding this concept is crucial as it dictates when a solution set will occupy a continuous range, or when it will segregate into two non-overlapping ranges.
Solving Inequalities
Solving inequalities follows a path similar to solving equations, with additional considerations.
An inequality shows a relationship where expressions are not necessarily equal, often using symbols like >, <, ≥, or ≤. When solving inequalities such as \( 2x - 5 > 8 \) or \( 2x - 5 < -8 \), the key is to isolate \( x \).
The same operations for the second inequality yield \( x < -1.5 \).Finally, always be aware that multiplying or dividing both sides of an inequality by a negative number will flip the inequality sign. Always check your work to ensure the inequality relationship holds true throughout the process.
An inequality shows a relationship where expressions are not necessarily equal, often using symbols like >, <, ≥, or ≤. When solving inequalities such as \( 2x - 5 > 8 \) or \( 2x - 5 < -8 \), the key is to isolate \( x \).
- Add or subtract terms on both sides to eliminate constant terms.
- Divide or multiply to remove coefficients of \( x \).
The same operations for the second inequality yield \( x < -1.5 \).Finally, always be aware that multiplying or dividing both sides of an inequality by a negative number will flip the inequality sign. Always check your work to ensure the inequality relationship holds true throughout the process.
Other exercises in this chapter
Problem 99
Solve equation by the method of your choice. $$ x^{2}-6 x+13=0 $$
View solution Problem 99
If 5 times a number is decreased by \(4,\) the principal square root of this difference is 2 less than the number. Find the number(s).
View solution Problem 100
Solve equation by the method of your choice. $$ x^{2}-4 x+29=0 $$
View solution Problem 100
If a number is decreased by \(3,\) the principal square root of this difference is 5 less than the number. Find the number(s).
View solution