Problem 100
Question
Food contains three main categories of compounds: carbohydrate, protein, and fat. Arctic explorers often eat a high-fat diet because fats have a high food value. The average food values for carbohydrate, protein, and fat are \(4 \mathrm{Cal} / \mathrm{g}, 4 \mathrm{Cal} / \mathrm{g},\) and \(9 \mathrm{Cal} / \mathrm{g},\) respectively. Consider a typical fat to have the chemical formula \(\mathrm{C}_{18} \mathrm{H}_{36} \mathrm{O}_{2},\) glucose \(\left(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\right)\) to be a representative carbohydrate, and the amino acid alanine \(\left(\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{NO}_{2}\right)\) a building block of proteins. Express the food values given above as \(\Delta H_{\text {comb }}\) in \(\mathrm{k} \mathrm{J} / \mathrm{mol}\).
Step-by-Step Solution
VerifiedKey Concepts
Calorimetry
To convert food calories to kilojoules, we use the conversion factor where 1 Cal (or kilocalorie) equals 4.184 kJ. For example, carbohydrates and proteins have a calorific value of 4 Cal/g. By multiplying 4 Cal/g with 4.184 kJ/Cal, we get 16.736 kJ/g as their energy content in kilojoules. Fats, with 9 Cal/g, convert to 37.656 kJ/g.
This understanding is crucial as it allows us to quantify the energy released during combustion in a laboratory setting, making calorimetry a powerful tool for both chemistry and nutrition.
Molar Mass Calculation
To calculate molar mass, we sum the atomic masses of each element in a compound. For example, for a typical fat molecule like \(\text{C}_{18}\text{H}_{36}\text{O}_{2}\), we calculate:
- Carbon (C): \(18 \times 12.01\, \text{g/mol} = 216.18\, \text{g/mol}\)
- Hydrogen (H): \(36 \times 1.008\, \text{g/mol} = 36.29\, \text{g/mol}\)
- Oxygen (O): \(2 \times 16.00\, \text{g/mol} = 32.00\, \text{g/mol}\)
Repeat similar calculations for carbohydrates \(\text{C}_{6}\text{H}_{12}\text{O}_{6}\) and proteins \(\text{C}_{3}\text{H}_{6}\text{NO}_{2}\) to find their molar masses. This forms a foundational step in calculating enthalpy of combustion.
Enthalpy of Combustion
To find \(\Delta H_{\text{comb}}\), multiply the energy content per gram with the molar mass of the substance. For instance, the enthalpy of combustion for fat is calculated as:
- 37.656 kJ/g (energy content) \(\times\) 284.48 g/mol (molar mass) = 10720.98 kJ/mol
This calculation helps in understanding why fats are so energy-rich, as they release more energy upon combustion compared to carbohydrates and proteins, making them a dense energy source, especially valuable in challenging environments.