Problem 100
Question
Explain how to determine the double-angle formula for \(\tan (2 x)\) using the double-angle formulas for \(\cos (2 x)\) and \(\sin (2 x)\)
Step-by-Step Solution
Verified Answer
The double-angle formula for \( \tan(2x) \) is \( \frac{2 \tan(x)}{1 - \tan^2(x)} \).
1Step 1: Recall Double-Angle Formulas
The double-angle formulas for sine and cosine are essential to derive the formula for tangent. Recall that \( \sin(2x) = 2 \sin(x) \cos(x) \) and \( \cos(2x) = \cos^2(x) - \sin^2(x) \). These will be used to find \( \tan(2x) \).
2Step 2: Express \( \tan(2x) \) as \( \frac{\sin(2x)}{\cos(2x)} \)
Tangent of an angle is defined as the ratio of sine to cosine. Therefore, \( \tan(2x) = \frac{\sin(2x)}{\cos(2x)} \). Use the double-angle formulas to replace \( \sin(2x) \) and \( \cos(2x) \) in this expression.
3Step 3: Substitute Double-Angle Expressions
Substitute the expressions from Step 1 into the equation: \( \tan(2x) = \frac{2 \sin(x) \cos(x)}{\cos^2(x) - \sin^2(x)} \). This forms a fraction that represents \( \tan(2x) \) in terms of \( \sin(x) \) and \( \cos(x) \).
4Step 4: Simplify the Expression
To simplify, divide both the numerator and denominator by \( \cos^2(x) \): \( \tan(2x) = \frac{2 \frac{\sin(x)}{\cos(x)}}{1 - \frac{\sin^2(x)}{\cos^2(x)}} \). This becomes \( \tan(2x) = \frac{2 \tan(x)}{1 - \tan^2(x)} \) by substituting \( \tan(x) = \frac{\sin(x)}{\cos(x)} \). This is the double-angle formula for tangent.
Key Concepts
TangentSineCosineTrigonometric Identities
Tangent
The tangent of an angle in trigonometry is calculated as the ratio of the sine of that angle to its cosine. The formula for tangent is given by
- \( \tan(x) = \frac{\sin(x)}{\cos(x)} \).
- \( \tan(2x) = \frac{\sin(2x)}{\cos(2x)} \).
- \( \tan(2x) = \frac{2 \tan(x)}{1 - \tan^2(x)} \).
Sine
Sine is an elementary function in trigonometry describing a ratio of sides in a right triangle. Unlike tangent, sine does not need to involve both the adjacent and opposite sides. Instead, it is simply the ratio of the opposite side to the hypotenuse
- \( \sin(x) = \frac{\text{opposite}}{\text{hypotenuse}} \).
- \( \sin(2x) = 2 \sin(x) \cos(x) \).
- \( \sin(a + b) = \sin(a)\cos(b) + \cos(a)\sin(b) \).
Cosine
Cosine, another cornerstone of trigonometry, is the ratio of the adjacent side to the hypotenuse of a right triangle
- \( \cos(x) = \frac{\text{adjacent}}{\text{hypotenuse}} \).
- \( \cos(2x) = \cos^2(x) - \sin^2(x) \).
- \( \cos(2x) = 2 \cos^2(x) - 1 \) or \( \cos(2x) = 1 - 2 \sin^2(x) \).
Trigonometric Identities
Trigonometric identities are fundamental expressions connecting the primary trigonometric functions. These include sine, cosine, and tangent. They are useful tools for simplifying and solving equations. In particular, the identities used in the double-angle formula for tangent are crucial for various applications in mathematics and engineering.The most useful identities are
- Pythagorean identities: such as \( \sin^2(x) + \cos^2(x) = 1 \).
- Sum and difference formulas like \( \sin(a\pm b) \) and \( \cos(a\pm b) \).
- Even-odd identities: \( \sin(-x) = -\sin(x) \) and \( \cos(-x) = \cos(x) \).
Other exercises in this chapter
Problem 97
If \(\alpha, \beta,\) and \(\gamma\) are angles in the same triangle, then prove or disprove \(\sin (\alpha+\beta)=\sin \gamma\)
View solution Problem 99
Explain how to determine the reduction identities from the double-angle identity \(\cos (2 x)=\cos ^{2} x-\sin ^{2} x\)
View solution Problem 103
For the following exercises, find the exact values of a \() \sin (2 x),\) b) \(\cos (2 x),\) and \(c ) \tan (2 x)\) without solving for \(x\) If \(\sin x=\frac{
View solution Problem 104
For the following exercises, find the exact values of a \() \sin (2 x),\) b) \(\cos (2 x),\) and \(c ) \tan (2 x)\) without solving for \(x\) If \(\cos x=\frac{
View solution