Problem 10
Question
Using THE DISCRIMINANT Tell if the equation has two solutions, one solution, or no real solution. $$2 x^{2}-4 x+3=0$$
Step-by-Step Solution
Verified Answer
The equation \(2x^2 - 4x + 3 = 0\) has no real solutions.
1Step 1: Identify coefficients
From the equation \(2x^2 - 4x + 3 = 0\), we identify the coefficients as \(a=2\), \(b=-4\), and \(c=3\).
2Step 2: Find the discriminant
We calculate the discriminant using the formula \(b^{2}-4ac\), which becomes \((-4)^{2} - 4*2*3\).
3Step 3: Compute the discriminant
Calculate the expression \((-4)^{2} - 4*2*3 = 16 - 24 = -8\).
4Step 4: Determine the number of solutions
The number of solutions is determined by the sign of the discriminant. If the discriminant is greater than 0, there are two distinct solutions. If the discriminant is equal to 0, there is one solution. If the discriminant is less than 0, there are no real solutions. In this case, the discriminant is -8, which is less than 0.
Key Concepts
Quadratic EquationsCoefficientsReal Solutions
Quadratic Equations
A quadratic equation is a type of polynomial equation that involves the square of a variable. A typical quadratic equation has the form: \[ ax^2 + bx + c = 0 \]where \( a \), \( b \), and \( c \) are constants with \( a eq 0 \). Quadratic equations are characterized by the highest degree term being \( x^2 \). This form is common in mathematics because it appears in various real-world scenarios such as physics, engineering, and finance.
It's important to notice that these equations are called "quadratics" because the word "quadratic" comes from "quad," meaning square. The key component that makes them different from linear equations is the \( x^2 \) term. Solving these equations aims to find the value(s) of \( x \) that make the equation true.
When dealing with quadratic equations, we often use different methods like factoring, completing the square, or using the quadratic formula. Each method offers unique benefits depending on the specific equation.
It's important to notice that these equations are called "quadratics" because the word "quadratic" comes from "quad," meaning square. The key component that makes them different from linear equations is the \( x^2 \) term. Solving these equations aims to find the value(s) of \( x \) that make the equation true.
When dealing with quadratic equations, we often use different methods like factoring, completing the square, or using the quadratic formula. Each method offers unique benefits depending on the specific equation.
Coefficients
In the context of the quadratic equation \( ax^2 + bx + c = 0 \), coefficients are the numerical constants \( a \), \( b \), and \( c \) in the equation. Each coefficient serves a specific role:
- \( a \) is the coefficient of \( x^2 \); it determines the parabola's "direction" (upward if positive, downward if negative) and "width" (wider if \( |a| \) is smaller, narrower if \( |a| \) is larger).
- \( b \) is the coefficient of \( x \); it influences the line's slope and affects the position of the parabola along the x-axis.
- \( c \) is the constant term; it shifts the parabola up or down along the y-axis without affecting its shape.
Real Solutions
Real solutions of quadratic equations refer to the actual values of \( x \) that satisfy the equation when plotted on a real number line. The number of real solutions depends mainly on the discriminant, \( b^2 - 4ac \), a special part of the quadratic formula. Here's how it works:
- If the discriminant is positive, \( b^2 - 4ac > 0 \), the equation has two distinct real solutions. This means the parabola intersects the x-axis at two points.
- If the discriminant is zero, \( b^2 - 4ac = 0 \), there is exactly one real solution. The vertex of the parabola touches the x-axis, indicating one repeated root.
- If the discriminant is negative, \( b^2 - 4ac < 0 \), there are no "real" solutions. Instead, the solutions are complex or imaginary, as the parabola does not intersect the real number line.
Other exercises in this chapter
Problem 9
Tell whether the graph opens up or down. Write an equation of the axis of symmetry. $$ y=5 x^{2}-2 x+4 $$
View solution Problem 9
Describe the error.Simplify correctly. $$\begin{aligned} &\sqrt{50}=\sqrt{5}+70\\\ &r=5 \sqrt{10} \end{aligned}$$
View solution Problem 10
Evaluate the expression. $$-\sqrt{0.04}$$
View solution Problem 10
Solve the equation algebraically. Check the solution graphically. $$ 8 x^{2}=32 $$
View solution